Concept explainers
a.
To describe: The shape of the data distribution and then to determine the best measures of center and variation to represent the data.
a.
Answer to Problem 2CT
Distribution is symmetric, mean for center and standard deviation for variation.
Explanation of Solution
Given Information: Histogram of the distribution.
The data at left-side is approximately the mirror image of data at right side, distribution is symmetric. By this, it can be concluded that mean is the best measure for center and standard deviation is the most appropriate measure for variation.
Thus, distribution is symmetric, mean for center and standard deviation for variation.
b.
To describe: The shape of the data distribution and then to determine the best measures of center and variation to represent the data.
b.
Answer to Problem 2CT
Distribution is skewed right, median for center and five-number summary for variation.
Explanation of Solution
Given Information: Histogram of the distribution.
Most of the data is placed at left-side and ‘tail’ extends to the right. This signifies that data is skewed right. As the data is skewed, best measure to describe center is median and that for variation is five-number summary.
Thus, distribution is skewed right, median for center and five-number summary for variation.
c.
To describe: The shape of the data distribution and then to determine the best measures of center and variation to represent the data.
c.
Answer to Problem 2CT
Distribution is skewed left, median for center and five-number summary for variation.
Explanation of Solution
Given Information: Histogram of the distribution.
Most of the data lies at right-side and ‘tail’ extends to the left. This signifies that data is skewed left. As the data is skewed, best measure to describe center is median and that for variation is five-number summary.
Thus, distribution is skewed left, median for center and five-number summary for variation.
Chapter 11 Solutions
BIG IDEAS MATH Algebra 1: Common Core Student Edition 2015
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