Explanation Given information: Sketch the graph of e market value of a new car as a function of time for a period of 20 years. Assume the car is well maintained. Calculation: f ( x ) = 3 x 2 − x + 2 ( 1 ) ⇒ f ( 2 ) = 3 ( 2 ) 2 − 2 + 2 put x = 2 f ( 2 ) = 12 ⇒ f ( − 2 ) = 3 ( − 2 ) 2 − ( − 2 ) + 2 put x = − 2 in equation ( 1 ) f ( − 2 ) = 12 + 2 + 2 = 16 ∴ f ( − 2 ) = 16 ⇒ f ( a ) = 3 ( a ) 2 − ( a ) + 2 put x = a in equation ( 1 ) f ( a ) = 3 a 2 − a + 2 ⇒ f ( − a ) = 3 ( − a ) 2 − ( − a ) + 2 put x = − a in equation ( 1 ) f ( − a ) = 3 a 2 + a + 2 ⇒ f ( a + 1 ) = 3 ( a + 1 ) 2 − ( a + 1 ) + 2 put x = a + 1 in equation ( 1 ) f ( a + 1 ) = 3 [ a 2 + 1 + 2 a ] − a − 1 + 2 f ( a + 1 ) = 3 a 2 + 3 + 6 a − a + 1 ∴ f ( a + 1 ) = 3 a 2 + 5 a + 4 2 f ( a ) = 2 [ 3 ( a ) 2 − a + 2 ] put x = a in equation ( 1 ) 2 f ( a ) = 2 [ 3 a 2 − a + 2 ] 2 f ( a ) = 6 a 2 − 2 a + 4 f ( 2 a ) = 3

15th Edition

ISBN: 9781133109631

Author: Stewart, JAMES, Day, Troy

Publisher: Cengage Learning,

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Question

Chapter 1.1, Problem 27E

To determine

To Find: f(2),f(−2),f(a),f(−a),f(a+1),2f(a),f(2a),f(a2),

[f(a)]2 and f(a+h) .

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Chapter 1.1, Problem 26E

Chapter 1.1, Problem 28E

Chapter 1 Solutions

Biocalculus

Ch. 1.1 - Prob. 1E Ch. 1.1 - Prob. 2E Ch. 1.1 - Prob. 3E Ch. 1.1 - Prob. 4E Ch. 1.1 - Prob. 5E Ch. 1.1 - Prob. 6E Ch. 1.1 - Prob. 7E Ch. 1.1 - Prob. 8E Ch. 1.1 - Prob. 9E Ch. 1.1 - Prob. 10E

Ch. 1.1 - Prob. 11E Ch. 1.1 - Prob. 12E Ch. 1.1 - Prob. 13E Ch. 1.1 - Prob. 14E Ch. 1.1 - Prob. 15E Ch. 1.1 - Prob. 16E Ch. 1.1 - Prob. 17E Ch. 1.1 - Prob. 18E Ch. 1.1 - Prob. 19E Ch. 1.1 - Prob. 20E Ch. 1.1 - Prob. 21E Ch. 1.1 - Prob. 22E Ch. 1.1 - Prob. 23E Ch. 1.1 - Prob. 24E Ch. 1.1 - Prob. 25E Ch. 1.1 - Prob. 26E Ch. 1.1 - Prob. 27E Ch. 1.1 - Prob. 28E Ch. 1.1 - Prob. 29E Ch. 1.1 - Prob. 30E Ch. 1.1 - Prob. 31E Ch. 1.1 - Prob. 32E Ch. 1.1 - Prob. 33E Ch. 1.1 - Prob. 34E Ch. 1.1 - Prob. 35E Ch. 1.1 - Prob. 36E Ch. 1.1 - Prob. 37E Ch. 1.1 - Prob. 38E Ch. 1.1 - Prob. 39E Ch. 1.1 - Prob. 40E Ch. 1.1 - Prob. 41E Ch. 1.1 - Prob. 42E Ch. 1.1 - Prob. 43E Ch. 1.1 - Prob. 44E Ch. 1.1 - Prob. 45E Ch. 1.1 - Prob. 46E Ch. 1.1 - Prob. 47E Ch. 1.1 - Prob. 48E Ch. 1.1 - Prob. 49E Ch. 1.1 - Prob. 50E Ch. 1.1 - Prob. 51E Ch. 1.1 - Prob. 52E Ch. 1.1 - Prob. 53E Ch. 1.1 - Prob. 54E Ch. 1.1 - Prob. 55E Ch. 1.1 - Prob. 56E Ch. 1.1 - Prob. 57E Ch. 1.1 - Prob. 58E Ch. 1.1 - Prob. 59E Ch. 1.1 - Prob. 60E Ch. 1.1 - 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f ( 2 ) , f ( − 2 ) , f ( a ) , f ( − a ) , f ( a + 1 ) , 2 f ( a ) , f ( 2 a ) , f ( a 2 ) , [ f ( a ) ] 2 and f ( a + h ) .

Solution Summary: The author illustrates the graph of the e market value of a new car.

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To Find: f(2),f(−2),f(a),f(−a),f(a+1),2f(a),f(2a),f(a2),

[f(a)]2 and f(a+h) .

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Chapter 1 Solutions

f ( 2 ) , f ( − 2 ) , f ( a ) , f ( − a ) , f ( a + 1 ) , 2 f ( a ) , f ( 2 a ) , f ( a 2 ) , [ f ( a ) ] 2 and f ( a + h ) .

Solution Summary: The author illustrates the graph of the e market value of a new car.

Concept explainers

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To Find: f(2),f(−2),f(a),f(−a),f(a+1),2f(a),f(2a),f(a2), [f(a)]2 and f(a+h) .

Want to see the full answer?

Chapter 1 Solutions

To Find: f(2),f(−2),f(a),f(−a),f(a+1),2f(a),f(2a),f(a2),

[f(a)]2 and f(a+h) .