Chapter 11, Problem 22P

A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector $\stackrel{\to }{r}=\left(2.00m\right)\hat{i}-\left(\text{3}\text{.00 m}\right)\hat{j}\text{+}\left(\text{2}\text{.00}\text{m}\right)\hat{k}$, the force is given by $\stackrel{\to }{F}=F_x\hat{i}\text{+}\left(\text{7}\text{.00}\text{N}\right)\hat{j}-\left(\text{6}\text{.00}\text{N}\right)\hat{k}$ and the corresponding torque about the origin is $\stackrel{\to }{\tau }=\left(4.00\text{N}\cdot \text{m}\right)\hat{i}\text{+}\left(\text{2}\text{.00}\text{N}\cdot \text{m}\right)\hat{j}-\left(\text{1}\text{.00}\text{N}\cdot \text{m}\right)\hat{k}$. Determine F_x.