Concept explainers
One of the autosomal loci controlling eye color in fruit flies has two alleles: one for brown eyes and the other for red eyes. Fruit flies from a true-breeding line with brown eyes were crossed with flies from a true-breeding line with red eyes. The F1 flies had red eyes. What conclusion can be drawn from this experiment? (a) these alleles underwent independent assortment (b) these alleles underwent segregation (c) these genes are X-linked (d) the allele for red eyes is dominant to the allele for brown eyes (e) all the preceding are true
Introduction: Locus (pl:loci) is the specific location of the gene in the chromosome. Alleles are variants of a gene. The allele that masks the expression of the other allele in heterozygous form is called the dominant allele.
Answer to Problem 1TYU
Correct answer: When fruits flies of true-breeding line with brown eyes are crossed with fruits flies of true-breeding line with red eyes, the F1 had red eyes that show that the allele for red eyes is dominant to the allele for brown eyes. Therefore, option (d) is correct.
Explanation of Solution
Reason for the correct answer.
When true breeding parents are crossed where one parent is homozygous for one allele and the other parent is homozygous for another allele, the trait expressed in the F1 generation is the dominant allele. When applying the above principle for the given question, where fruits flies of true-breeding line with brown eyes are crossed with fruits flies of true-breeding line with red eyes, the F1 will have red eyes. This shows that the allele for red eyes is dominant to the allele for brown eyes.
Option (d) is given as “the allele for red eyes is dominant to the allele for brown eyes”.
When fruits flies of true-breeding line with brown eyes are crossed with fruits flies of true-breeding line with red eyes, the F1 will have red eyes that show that the allele for red eyes is dominant to the allele for brown eyes. Therefore, option (d) is correct.
Reasons for the incorrect statements.
Option (a) is given as “these alleles underwent independent assortment”.
Independent assortment can be explained with two traits only. Here, only one trait is mentioned, that is eye color, therefore, they can show only segregation, not independent assortment. Hence, option (a) is incorrect.
Option (b) is given as “these alleles underwent segregation”.
This option is correct, yet the most suitable option will be option (d) as the law of segregation has proved right for single traits. This experiment reveals the dominant allele more than segregation. Hence, option (b) is incorrect.
Option (c) is given as “these genes are X-linked”.
The question mentions that these alleles are present in autosomal loci and therefore, they cannot be X-linked. Hence, option (c) is incorrect.
Option (e) is given as “all the preceding are true”.
Option (d) is the most suitable answer followed by option (b). The other options are incorrect. Hence, option (e) is incorrect.
Hence, options (a), (b), (c), and (e) are incorrect.
When fruits flies of true-breeding line with brown eyes are crossed with fruits flies of true-breeding line with red eyes, the F1 will have red eyes that show that the allele for red eyes is dominant over the allele for brown eyes.
Want to see more full solutions like this?
Chapter 11 Solutions
Biology (MindTap Course List)
- examples of synamptomorphyarrow_forwardexamples of synamtomorphy.arrow_forwardE. Bar Graph Use the same technique to upload the completed image. We will use a different type of graph to derive additional information from the CO2 data (Fig A1.6.2) 1. Calculate the average rate of increase in COz concentration per year for the time intervals 1959-1969, 1969- 1979, etc. and write the results in the spaces provided. The value for 1959-1969 is provided for you as an example. 2. Plot the results as a bar graph. The 1959-1969 is plotted for you. 3. Choose the graph that looks the most like yours A) E BAR GRAPH We will use a different type of graph to derive additional information from the CU, data (rig. nive). Average Yearly Rate of Observatory, Hawall interval Rate of increase per year 1959-1969 0.9 1969-1979 1979-1989 1989-1999 1999-2009 Figure A1.6.2 1999-2009 *- mrame -11- -n4 P2 جية 1989-1999 1979-1989 1969-1979 1959-1969 This bar drawn for you as an example 1.0 CO, Average Increase/Year (ppmv) B) E BAR GRAPH We will use a different type of graph to derive…arrow_forward
- Use the relationships you just described to compute the values needed to fill in the blanks in the table in Fig A1.4.1 depth (a) 1.0 cml 0.7 cml cm| base dimensions (b, c)| 1.0 cm| 1.0 cm| 1.0 cm 1.0 cm| 1.0 cm| 1.0 cm volume (V) 1.0_cm' cm'| cm'| density (p) 1.0 g/cm'| 1.0 g/cm 1.0 g/cm' mass (m)| 0.3 g Column 1: depth at 1.0 cm volume mass Column 2: depth at 0.7 cm volume mass Column 3: unknown depth depth volumearrow_forwardSan Andreas Transform Boundary Plate Motion The geologic map below of southern California shows the position of the famous San Andreas Fault, a transform plate boundary between the North American Plate (east side) and the Pacific Plate (west side). The relative motion between the plates is indicated by the half arrows along the transform plate boundary (i.e., the Pacific Plate is moving to the northwest relative to the North American Plate). Note the two bodies of Oligocene volcanic rocks (labeled Ov) on the map in the previous page located along either side of the San Andreas Fault. These rocks are about 23.5 million years old and were once one body of rock. They have been separated by displacement along the fault. 21. Based on the offset of these volcanic rocks, what is the average annual rate of relative plate motion in cm/yr? SAF lab 2.jpg Group of answer choices 0.67 cm/yr 2 cm/yr 6.7 cm/yr 1.5 cm/yr CALIFORNIA Berkeley San Francisco K Os Q San Andreas Fault Ov…arrow_forwardThese are NOT part of any graded assignment. Are there other examples of synapomorphy. What is it called when the traits retained are similar to ancestors?arrow_forward
- Please hand draw everying. Thank you! Draw a gram positive bacterial cell below. Your cell should have the following parts, labeled: A coccus shape A capsule The gram positive cell wall should have the peptidoglycan labeled, as well as its component parts (NAM, NAG, and teichoic acid) A cell membrane Fimbriae A nucleoid Ribosomes Inclusionsarrow_forwardDraw a gram negative bacterial cell below. Your cell should have the following parts, labeled: A bacillus shape Fimbriae Amphitrichous flagella 2 membranes (outer and inner) The outer membrane should have lipopolysaccharide (LPS) with lipid A and O antigens Periplasmic space The thin peptidoglycan cell wall between the 2 membranes A nucleoid Ribosomes Inclusionsarrow_forwardBacterial species Cell wall type Example: S. mitis Gram positive S. epidermidis H. pylori M. bovis S. marcescens Shape and arrangement Coccus, streptococcus Drawing 0000000arrow_forward
- Draw a gram positive bacterial cell below. Your cell should have the following parts, labeled: A coccus shape A capsule The gram positive cell wall should have the peptidoglycan labeled, as well as its component parts (NAM, NAG, and teichoic acid) A cell membrane Fimbriae A nucleoid Ribosomes Inclusionsarrow_forwardwhat rank is above kingdom? order, class, phylum or domainarrow_forwardin the hierarchy of taconomic categories, with kingdom at the top, what taxon is below classarrow_forward
- Human Biology (MindTap Course List)BiologyISBN:9781305112100Author:Cecie Starr, Beverly McMillanPublisher:Cengage LearningHuman Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning
- Biology: The Dynamic Science (MindTap Course List)BiologyISBN:9781305389892Author:Peter J. Russell, Paul E. Hertz, Beverly McMillanPublisher:Cengage LearningBiology (MindTap Course List)BiologyISBN:9781337392938Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. BergPublisher:Cengage LearningConcepts of BiologyBiologyISBN:9781938168116Author:Samantha Fowler, Rebecca Roush, James WisePublisher:OpenStax College