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The formation of shooting star.
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Answer to Problem 1QFR
The burning of the meteor that enters the atmosphere of the Earth in the form of light seen as a shooting star in the night sky.
Explanation of Solution
Shooting star is a spark of light forms in the Earth’s atmosphere only in a fraction of a second which fastly fades away. This spark occurs due to the burning of meteor. Shooting stars fastly shoots across the sky. When they are moving through the atmosphere , the speed will be very high so that it will heats up and starts sparking for a small time. They are usually rocks that falls into Earth’s atmosphere. When it falls due to the friction between the air and rock makes the rock to gets hot.
Thus the shooting star is due to the burning of the meteor in the night sky.
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Chapter 11 Solutions
Loose Leaf For Explorations: Introduction To Astronomy
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- 4. A voltmeter with resistance 10 kQ is used to measure the pd across the 1 kQ resistor in the circuit below. 6V 5ΚΩ 1ΚΩ V Calculate the percentage difference between the value with and without the voltmeter.arrow_forward1. A 9V battery with internal resistance 5 2 is connected to a 100 2 resistor. Calculate: a. the Power dissipated in the 100 2 resistor b. The heat generated per second inside the battery. C. The rate of converting chemical to electrical energy by the battery. 2. A 230 V kettle is rated at 1800 W. Calculate the resistance of the heating element.arrow_forward2. If each of the resistors in the circuit below has resistance R show that the total resistance between A and B is 5R/11 A Barrow_forward
- 1. At 0°C a steel cable is 1km long and 1cm diameter when it is heated it expands and its resistivity increases. Calculate the change in resistance of the cable as it is heated from 0-20°C The temperature coefficient of resistance a, gives the fractional increase in resistance per °C. So increase in resistance AR = Ra.AT Where R, is the resistance at 0°C For steel a, 0.003 °C The coefficient of linear expansion a- gives the fractional increase in length per °C temperature rise. So increase in Length AL La-AT Where L, is the length at 0°C For steel a₁ = 12 x 10 °C-1 The resistivity of steel at 0°C = 1.2 x 10 Qmarrow_forward1. F E 6V 10 1.1. B a 6V b C C Apply Kirchoff's 1st law to point C for the circuit above Apply Kirchoff's 2nd Law to loops: a. ABCFA b. ABDEA C. FCDEF d. Find values for currents a,b and c Darrow_forward2. The results of the Rutherford experiment can be categorized in 3 statements. Fill in the missing words Most 11. Some III. A few State which result gives evidence that the nucleus is a. heavier than an alpha particle b. very small compared to the size of the atom c. positively charged 3. Using values in the diagram derive an expression for r .0 e marrow_forward
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