ESSENTIALS OF COMPUTER ORGAN..-TEXT
ESSENTIALS OF COMPUTER ORGAN..-TEXT
4th Edition
ISBN: 9781284033144
Author: NULL
Publisher: JONES+BART
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Chapter 11, Problem 1E

Explanation of Solution

Performance of the system under the new execution mix:

  • System performance is considered as one of main factor of a processor.
  • It is used to determine the speed a problem can be solved.
  • It is also used to determine the factors such as number of problems that can be allocated at particular amount of time and also the number of problems that can be handled by the processor.
  • The relative performance between the two systems is measured and expected by the run time of the program of the individual.

Given:

The information about the system A and System c are shown in the below table:

ProgramExecution Frequency

Execution time

System A(sec)

Execution time

System C(sec)

V50%50500
W30%200600
X10%250500
Y5%400800
Z5%50003500

The information about the programs that run at the system A is shown below:

ProgramExecution Frequency

Execution time

System A(sec)

V25%50
W5%200
X10%250
Y5%400
Z55%5000

Calculating the weighted average time:

System A:

The below is the weighted average obtained from the table 1:

0.5×50+0.3×200+0.1×250+0.05×400+0.05×5000=380

The below is the weighted average obtained from the table 2:

0.25×50+0.05×200+0.1×250+0.05×400+0.55×5000=2817.5

System C:

The below is the weighted average obtained from the table 1:

0.5×500+0.3×600+0

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I need help fixing the minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place. My code: % Define frequency range for the plot f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz w = 2 * pi * f; % Angular frequency   % Parameters for the filters - let's adjust these to get more reasonable cutoffs R = 1e3; % Resistance in ohms (1 kΩ) C = 1e-6; % Capacitance in farads (1 μF)   % For bandpass, we need appropriate L value for desired cutoffs L = 0.1; % Inductance in henries - adjusted for better bandpass response   % Calculate cutoff frequencies first to verify they're in desired range f_cutoff_RC = 1 / (2 * pi * R * C); f_resonance = 1 / (2 * pi * sqrt(L * C)); Q_factor = (1/R) * sqrt(L/C); f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor)); f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor));   % Transfer functions % Low-pass filter (RC) H_low = 1 ./ (1 + 1i * w *…
My code is experincing minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place. My code: % Define frequency range for the plot f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz w = 2 * pi * f; % Angular frequency   % Parameters for the filters - let's adjust these to get more reasonable cutoffs R = 1e3; % Resistance in ohms (1 kΩ) C = 1e-6; % Capacitance in farads (1 μF)   % For bandpass, we need appropriate L value for desired cutoffs L = 0.1; % Inductance in henries - adjusted for better bandpass response   % Calculate cutoff frequencies first to verify they're in desired range f_cutoff_RC = 1 / (2 * pi * R * C); f_resonance = 1 / (2 * pi * sqrt(L * C)); Q_factor = (1/R) * sqrt(L/C); f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor)); f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor));   % Transfer functions % Low-pass filter (RC) H_low = 1 ./ (1 + 1i * w *…
I would like to know the main features about the following three concepts: 1. Default forwarded 2. WINS Server 3. IP Security (IPSec).
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