Interpretation:
The molecule that has a stronger force of attraction between ammonia and methylamine and the reasons for the same is to be determined. Also, based on the reasons, list the other experiment that is done with these molecules to test the same hypothesis is to be determined.
Conceptual introduction:
The force of attraction between the hydrogen and an electronegative atom is called hydrogen bonding.
The force of attraction between the same atoms of different molecules is called van der Waals force of attraction.
The force of attraction between the charged ion and a polar compound is called ionic-dipole interaction.
The force of attraction between the two polar compounds is called as dipole-dipole interaction.
To determine:
The molecule that has a stronger force of attraction from ammonia and methylamine and the reasons for the same.
Answer to Problem 1DE
Solution: The molecule that has a stronger force of attraction from ammonia and methylamine is methylamine and the reasons for the same are stated below.
Explanation of Solution
The force of attraction between the hydrogen and an electronegative atom is called hydrogen bonding.
Nitrogen is an electronegative atom compared to hydrogen. Therefore, there exist the hydrogen bonding interaction between the nitrogen of one ammonia molecule and the hydrogen of another ammonia molecule.
Thus, the liquification of ammonia gas is easier.
According to the given data, methylamine is liquefied more easily than ammonia, since, the boiling point of ammonia is less than that of methylamine.
Therefore, the interaction between the two methylamine molecules is stronger than that between two ammonia molecules.
The reason for this is that the interaction between the two methylamine molecules other than hydrogen bonding exist, that is, van der Waals forces. This is due to the hydrophobic regions of the two different molecules and the dipole-dipole interaction present between the carbon and the nitrogen atom in a molecule.
The solubility of a salt of methyl ammine is stronger than that of ammonia, since in methylammonium ion, the positive charge is stabilized by the positive inductive effect of the methyl group. This effect is absent in an ammonium ion.
The
Therefore, ammonia is less basic than methylamine. This is due to the inductive effect of methyl group that pushes electrons to extract a proton much easily. This effect is absent in ammonia.
Methylamine has stronger intermolecular force of attraction between its two molecule compared to that of ammonia.
Want to see more full solutions like this?
Chapter 11 Solutions
Chemistry, The Central Science, Volume 1, Custom For Houston Community College
- Show work. don't give Ai generated solutionarrow_forwardHi!! Please provide a solution that is handwritten. Ensure all figures, reaction mechanisms (with arrows and lone pairs please!!), and structures are clearly drawn to illustrate the synthesis of the product as per the standards of a third year organic chemistry course. ****the solution must include all steps, mechanisms, and intermediate structures as required. Please hand-draw the mechanisms and structures to support your explanation. Don’t give me AI-generated diagrams or text-based explanations, no wordy explanations on how to draw the structures I need help with the exact mechanism hand drawn by you!!! I am reposting this—ensure all parts of the question are straightforward and clear or please let another expert handle it thanks!!arrow_forwardHi!! Please provide a solution that is handwritten. Ensure all figures, reaction mechanisms (with arrows and lone pairs please!!), and structures are clearly drawn to illustrate the synthesis of the product as per the standards of a third year organic chemistry course. ****the solution must include all steps, mechanisms, and intermediate structures as required. Please hand-draw the mechanisms and structures to support your explanation. Don’t give me AI-generated diagrams or text-based explanations, no wordy explanations on how to draw the structures I need help with the exact mechanism hand drawn by you!!! I am reposting this—ensure all parts of the question are straightforward and clear or please let another expert handle it thanks!!arrow_forward
- . (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. < cleavage Bond A • CH3 + 26. t cleavage 2°C• +3°C• Bond C Cleavage CH3 ZC '2°C. 26. E Strongest 3°C. 2C. Gund Largest BDE weakest bond In that molecule a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. Weakest C bond Produces A Weakest Bond Most Strongest Bond Stable radical Strongest Gund produces least stable radicals b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 人 8°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. methyl radical •CH3 formed in bund A Cleavagearrow_forwardWhich carbocation is more stable?arrow_forwardAre the products of the given reaction correct? Why or why not?arrow_forward
- The question below asks why the products shown are NOT the correct products. I asked this already, and the person explained why those are the correct products, as opposed to what we would think should be the correct products. That's the opposite of what the question was asking. Why are they not the correct products? A reaction mechanism for how we arrive at the correct products is requested ("using key intermediates"). In other words, why is HCl added to the terminal alkene rather than the internal alkene?arrow_forwardMy question is whether HI adds to both double bonds, and if it doesn't, why not?arrow_forwardStrain Energy for Alkanes Interaction / Compound kJ/mol kcal/mol H: H eclipsing 4.0 1.0 H: CH3 eclipsing 5.8 1.4 CH3 CH3 eclipsing 11.0 2.6 gauche butane 3.8 0.9 cyclopropane 115 27.5 cyclobutane 110 26.3 cyclopentane 26.0 6.2 cycloheptane 26.2 6.3 cyclooctane 40.5 9.7 (Calculate your answer to the nearest 0.1 energy unit, and be sure to specify units, kJ/mol or kcal/mol. The answer is case sensitive.) H. H Previous Nextarrow_forward
- A certain half-reaction has a standard reduction potential Ered +1.26 V. An engineer proposes using this half-reaction at the anode of a galvanic cell that must provide at least 1.10 V of electrical power. The cell will operate under standard conditions. Note for advanced students: assume the engineer requires this half-reaction to happen at the anode of the cell. Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have? If so, check the "yes" box and calculate the minimum. Round your answer to 2 decimal places. If there is no lower limit, check the "no" box.. Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have? If so, check the "yes" box and calculate the maximum. Round your answer to 2 decimal places. If there is no upper limit, check the "no" box. yes, there is a minimum. 1 red Πν no minimum Oyes, there is a maximum. 0 E red Dv By using the information in the ALEKS…arrow_forwardIn statistical thermodynamics, check the hcv following equality: ß Aɛ = KTarrow_forwardPlease correct answer and don't used hand raitingarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY