Concept explainers
What physical characteristic distinguishes a fluid from a solid?
What physical characteristic distinguishes a fluid from a solid?
Answer to Problem 1CQ
The physical characteristic that distinguishes a fluid from a solid is that solids have a fixed volume and fixed shape while liquids only have a fixed volume but no fixed shape.
Explanation of Solution
Introduction:
Solid, liquid, gas, plasma and Bose-Einstein condensate are the five states in which mater exists.
The various states in which matter exists are distinguished on the basis of the structure and density of the particles comprising it.
In solids, the constituent particles are arranged in a regular and fixed pattern and are tightly bound to each other by the attractive forces which are strong in nature. As a result, solids have a fixed volume and also a fixed shape. Hence they do not deform easily under stress and resist shearing forces.
However, in the case of liquids, the constituent particles do not follow a fixed pattern and the attractive forces between them are also not as strong as in the case of solids. As a result, although liquids have a fixed volume but they do not have a fixed shape and hence they take the shape of the container in which they are kept. Hence they deform when a force is applied to them and yield on application of shearing forces.
Hence the distinguishing physical characteristic between solids and fluids is having a fixed volume but not a fixed shape.
Conclusion:
Hence, solids have a fixed shape and fixed volume while liquids have only a fixed volume and no fixed shape and this is the physical characteristic that distinguishes them.
Want to see more full solutions like this?
Chapter 11 Solutions
College Physics
Additional Science Textbook Solutions
Applications and Investigations in Earth Science (9th Edition)
Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
Introductory Chemistry (6th Edition)
Campbell Biology (11th Edition)
Microbiology with Diseases by Body System (5th Edition)
Microbiology: An Introduction
- Fresnel lens: You would like to design a 25 mm diameter blazed Fresnel zone plate with a first-order power of +1.5 diopters. What is the lithography requirement (resolution required) for making this lens that is designed for 550 nm? Express your answer in units of μm to one decimal point. Fresnel lens: What would the power of the first diffracted order of this lens be at wavelength of 400 nm? Express your answer in diopters to one decimal point. Eye: A person with myopic eyes has a far point of 15 cm. What power contact lenses does she need to correct her version to a standard far point at infinity? Give your answer in diopter to one decimal point.arrow_forwardParaxial design of a field flattener. Imagine your optical system has Petzal curvature of the field with radius p. In Module 1 of Course 1, a homework problem asked you to derive the paraxial focus shift along the axis when a slab of glass was inserted in a converging cone of rays. Find or re-derive that result, then use it to calculate the paraxial radius of curvature of a field flattener of refractive index n that will correct the observed Petzval. Assume that the side of the flattener facing the image plane is plano. What is the required radius of the plano-convex field flattener? (p written as rho )arrow_forward3.37(a) Five free electrons exist in a three-dimensional infinite potential well with all three widths equal to \( a = 12 \, \text{Å} \). Determine the Fermi energy level at \( T = 0 \, \text{K} \). (b) Repeat part (a) for 13 electrons. Book: Semiconductor Physics and Devices 4th ed, NeamanChapter-3Please expert answer only. don't give gpt-generated answers, & please clear the concept of quantum states for determining nx, ny, nz to determine E, as I don't have much idea about that topic.arrow_forward
- 3.37(a) Five free electrons exist in a three-dimensional infinite potential well with all three widths equal to \( a = 12 \, \text{Å} \). Determine the Fermi energy level at \( T = 0 \, \text{K} \). (b) Repeat part (a) for 13 electrons. Book: Semiconductor Physics and Devices 4th ed, NeamanChapter-3Please expert answer only. don't give gpt-generated answers, & please clear the concept of quantum states for determining nx, ny, nz to determine E, as I don't have much idea about that topic.arrow_forwardNo chatgpt pls will upvotearrow_forwardUse the following information to answer the next question. Two mirrors meet an angle, a, of 105°. A ray of light is incident upon mirror A at an angle, i, of 42°. The ray of light reflects off mirror B and then enters water, as shown below: Incident ray at A Note: This diagram is not to scale. a Air (n = 1.00) Water (n = 1.34) 1) Determine the angle of refraction of the ray of light in the water. Barrow_forward
- Hi can u please solvearrow_forward6. Bending a lens in OpticStudio or OSLO. In either package, create a BK7 singlet lens of 10 mm semi-diameter and with 10 mm thickness. Set the wavelength to the (default) 0.55 microns and a single on-axis field point at infinite object distance. Set the image distance to 200 mm. Make the first surface the stop insure that the lens is fully filled (that is, that the entrance beam has a radius of 10 mm). Use the lens-maker's equation to calculate initial glass curvatures assuming you want a symmetric, bi-convex lens with an effective focal length of 200 mm. Get this working and examine the RMS spot size using the "Text" tab of the Spot Diagram analysis tab (OpticStudio) or the Spd command of the text widnow (OSLO). You should find the lens is far from diffraction limited, with a spot size of more than 100 microns. Now let's optimize this lens. In OpticStudio, create a default merit function optimizing on spot size.Then insert one extra line at the top of the merit function. Assign the…arrow_forwardNo chatgpt pls will upvote Already got wrong chatgpt answer .arrow_forward
- Use the following information to answer the next question. Two mirrors meet an angle, a, of 105°. A ray of light is incident upon mirror A at an angle, i, of 42°. The ray of light reflects off mirror B and then enters water, as shown below: A Incident ray at A Note: This diagram is not to scale. Air (n = 1.00) Water (n = 1.34) Barrow_forwardUse the following information to answer the next question. Two mirrors meet an angle, a, of 105°. A ray of light is incident upon mirror A at an angle, i, of 42°. The ray of light reflects off mirror B and then enters water, as shown below: A Incident ray at A Note: This diagram is not to scale. Air (n = 1.00) Water (n = 1.34) Barrow_forwardGood explanation it sure experts solve it.arrow_forward
- College PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax CollegeCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningAn Introduction to Physical SciencePhysicsISBN:9781305079137Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar TorresPublisher:Cengage Learning
- College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningGlencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-Hill