EBK PRINCIPLES OF ELECTRIC CIRCUITS
10th Edition
ISBN: 9780134880068
Author: Buchla
Publisher: VST
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2) A 208 V, four-pole, 60 Hz, Y-connected, wound-rotor induction motor has a rated power of 30 HP. The components of its equivalent circuit are R1 = 0.100
R2 = 0.070
XM = 10.0
X1 = 0.210
X2 = 0.210
Pmec = 500 W
Psup ~ 0
Pcore = 400 W
For a slip of 0.05, find:
a) The line current
b) The stator copper losses PcE
c) The air gap power PEF
d) The power converted from mechanical to electrical form Pconv
e) The induced torque _ind
f) load torque _load
g) The total efficiency of the machine
h) The speed of the motor in revolutions per minute and in radians per second
5. There are three sources that would affect the current flow in this circuit. Find the current
through the 4k2 resistor that is caused solely by the 24V source (i.e., remove the 2mA and
12V sources using the correct methods).
(20 points)
24 V +
9k,
ww
www
4kS
2mA
24ΚΩ
www
++
12V
www
6k
24ΚΩ
"Can you explain the method of finding the
direction?"
the electric field in free space is given by
ety
E: 50 Cos [2π 10 t - Bz ]
a) find the direction of the wave propagation
b) Calculate W, B, A, S
V/m
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- Athle phase a.c. distributor AB has: The distance from A to B is 500 m. The distance from A to C is 800 m. The impedance of each section is (6+j 8) /km. A B C The voltage at the far end is maintained at 250 volt. Find: sending voltage, sending current, supply power factor and 80 A 60 A total voltage drop. 0.8 lag. P.f 0.6 lead. p.farrow_forwardThe transfer function H(s) = Y(s)/X(s) = Vo(s)/Vi(s) should be found from the circuit given that the initial conditions are equal to 0. Do not answer using AI Chatbots. PLEASEarrow_forwardA 10kW, 230V, long shunt compound DC generator has efficiency = 82%, armature resistance = 0.15 ohms, series field resistance = 0.1 ohm, shunt field resistance = 100 ohms. What are: armature current, armature voltage across the brushes, generated emf, total copper losses, and horsepower of prime mover?arrow_forward
- The capacitors in the circuit shown below have no energy stored in them and then switch “A” closes at time t=0. Find v(t) across the 6 uF capacitor for t≥0arrow_forwardConsider the circuit Below: A) Find and show the Thevenin equivalent with respect to terminals a,b B) Find and show the Norton equivalent with respect to terminals a,b C)Find the value of Ro and the maximum power delivered across it when its adjusted such that the power across it is the maximum possible when connected in this fashionarrow_forwardConsider the Circuit Below: A)Find Vo if Vin is 0.2 volts and the positive and negative power supply voltages are +15v and -15v respectively. B)What is the Maximum of Vin that will not hit saturation for this circuit?arrow_forward
- A shunt generator is rated at 125V, 25KW; armature resistance is 0.08 ohms, shunt field resistance is 25 ohms. What are: Armature voltage at rated load, armature power loss, shunt field power loss Total power generated in the armature?arrow_forwardA 12KW, 240V 1500RPM shunt generator has an armature resistance of .02 ohm and a shunt field resistance of 160 ohms. The stray power losses are 900W. Assuming a constant shunt field current, what (1) the efficiency at rated load and (2) the efficiency of the generator at half-rated load?arrow_forward4. Consider the three circuits shown in Figure. Determine each output voltage for (i) V₁ = 3 V and (ii) VI = -5 V. 40 ΚΩ www ww 20 ΚΩ 10 ΚΩ (a) 01 να гля 40 ΚΩ www www 20 ΚΩ 10 ΚΩ ww 10 ΚΩ www (b) www 48 ΚΩ ww -0% 6 kQ 15 ΚΩ (c) оооarrow_forward
- Find the mathematical expression for the points 1 and 2 for this pratical AM-DSB/SC modulatorarrow_forwardQuestion Two A generating station consisting of two generators, one of 20 MVA, 11 kV, 0.18 pu reactance with the unit transformer of 20 MVA, 11/132 kV, 0.08 pu reactance, another of 30 MVA, 11 kV, 0.18 pu reactance with the transformer of 30 MVA, 11/132 kV, 0.12 pu reactance, transmits power over double circuit 132-kV transmission line. Each line is having reactance of 120 ohms per phase. Determine the fault current supplied by the generators to a three-phase solid fault on the 132-kV bus-bar at the receiving end. Neglect pre-fault current and losses. Assume pre-fault generated voltages at rated value.arrow_forward4v+9v+8v=-3v+6v',-5v, where vi and vo are the input and output voltage, respectively.arrow_forward
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