World record free fall On October 14, 2012, Felix Baumgartner stepped off a balloon capsule at an altitude of 127,852.4 feet and began his free fall. It is claimed that Felix reached the speed of sound 34 seconds into his fall at an altitude of 109,731 feet and that he continued to fall at supersonic speed for 30 seconds until he was at an altitude of 75,330.4 feet. Let f ( t ) equal the distance that Felix had fallen t seconds after leaving his capsule. Calculate f (0), f (34), f (64), and his average supersonic speed f ( 64 ) − f ( 34 ) 64 − 34 (in ft/s) over the time interval [34, 64] ( Source http://www.redbullstratos.com )
World record free fall On October 14, 2012, Felix Baumgartner stepped off a balloon capsule at an altitude of 127,852.4 feet and began his free fall. It is claimed that Felix reached the speed of sound 34 seconds into his fall at an altitude of 109,731 feet and that he continued to fall at supersonic speed for 30 seconds until he was at an altitude of 75,330.4 feet. Let f ( t ) equal the distance that Felix had fallen t seconds after leaving his capsule. Calculate f (0), f (34), f (64), and his average supersonic speed f ( 64 ) − f ( 34 ) 64 − 34 (in ft/s) over the time interval [34, 64] ( Source http://www.redbullstratos.com )
World record free fall On October 14, 2012, Felix Baumgartner stepped off a balloon capsule at an altitude of 127,852.4 feet and began his free fall. It is claimed that Felix reached the speed of sound 34 seconds into his fall at an altitude of 109,731 feet and that he continued to fall at supersonic speed for 30 seconds until he was at an altitude of 75,330.4 feet. Let f(t) equal the distance that Felix had fallen t seconds after leaving his capsule. Calculate f(0), f(34), f(64), and his average supersonic speed
f
(
64
)
−
f
(
34
)
64
−
34
(in ft/s) over the time interval [34, 64] (Sourcehttp://www.redbullstratos.com)
Only 100% sure experts solve it correct complete solutions ok
rmine the immediate settlement for points A and B shown in
figure below knowing that Aq,-200kN/m², E-20000kN/m², u=0.5, Depth
of foundation (DF-0), thickness of layer below footing (H)=20m.
4m
B
2m
2m
A
2m
+
2m
4m
sy = f(x)
+
+
+
+
+
+
+
+
+
X
3
4
5
7
8
9
The function of shown in the figure is continuous on the closed interval [0, 9] and differentiable on the open
interval (0, 9). Which of the following points satisfies conclusions of both the Intermediate Value Theorem
and the Mean Value Theorem for f on the closed interval [0, 9] ?
(A
A
B
B
C
D
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