Explanation Given data: The speed of the pulse on rope 1 is 1.4 times that of rope 2. Formula used: The speed of the transverse wave is given by, v = F μ = F m l Here, v is the speed of the transverse wave, F is the force exerted, and μ is the mass per unit length. Explanation: Let the length of both the ropes, which is same, be l . Both the ropes are stretched the same way, so the force on both the ropes is F . Write the expression for the speed of pulse in rope 1. v 1 = F 1 ( m 1 l 1 ) Here, m 1 is the mass of the rope 1, v 1 is the speed of the pulse in rope 1, F 1 is the force in rope 1, and l 1 is the length of rope 1. Substitute 1.4 v for v 1 , l for l 1 , and F for F 1 . 1.4 v = F ( m 1 l ) ……. (1) Again, write the expression for the speed of pulse in rope 2

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Chapter 11, Problem 14P

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The ratio of the mass of two ropes m1m2 if their lengths are equal and they are stretched the same way, and the speed of the pulse on rope 1 is 1.4 times that of rope 2.

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The ratio of the mass of two ropes m 1 m 2 if their lengths are equal and they are stretched the same way, and the speed of the pulse on rope 1 is 1.4 times that of rope 2.

Solution Summary: The author explains how to determine the ratio of the mass of two ropes if their lengths are equal and they are stretched the same way.

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The ratio of the mass of two ropes m1m2 if their lengths are equal and they are stretched the same way, and the speed of the pulse on rope 1 is 1.4 times that of rope 2.

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