The fraction of moles of NaCl existing as ion pairs and the freezing point of the solution has to be calculated. Concept Introduction: Mole fraction of a compound can be defined as the number of moles of a substance to the total number of moles present in them. The mole fraction can be calculated by, Mole fraction of compound= Number of moles(in mol) Total number of moles(in mol) Freezing point of solution can be calculated from the equation, ΔT f =K f m ΔT f = change in freezing point K f = molal depression freezing point constant m = moles of solute particles
The fraction of moles of NaCl existing as ion pairs and the freezing point of the solution has to be calculated. Concept Introduction: Mole fraction of a compound can be defined as the number of moles of a substance to the total number of moles present in them. The mole fraction can be calculated by, Mole fraction of compound= Number of moles(in mol) Total number of moles(in mol) Freezing point of solution can be calculated from the equation, ΔT f =K f m ΔT f = change in freezing point K f = molal depression freezing point constant m = moles of solute particles
Solution Summary: The author explains the mole tion of NaCl as ion pairs and the freezing point of the solution.
The fraction of moles of
NaCl existing as ion pairs and the freezing point of the solution has to be calculated.
Concept Introduction:
Mole fraction of a compound can be defined as the number of moles of a substance to the total number of moles present in them. The mole fraction can be calculated by,
Rank the labeled protons (Ha-Hd) in order of increasing acidity, starting with the least acidic.
НОН НЬ
OHd
Онс
Can the target compound at right be efficiently synthesized in good yield from the unsubstituted benzene at left?
?
starting
material
target
If so, draw a synthesis below. If no synthesis using reagents ALEKS recognizes is possible, check the box under the drawing area.
Be sure you follow the standard ALEKS rules for submitting syntheses.
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Note for advanced students: you may assume that you are using a large excess of benzene as your starting material.
C
:0
T
Add/Remove step
G
The following equations represent the formation of compound MX. What is the AH for the
electron affinity of X (g)?
X₂ (g) → 2X (g)
M (s) → M (g)
M (g)
M (g) + e-
AH = 60 kJ/mol
AH = 22 kJ/mol
X (g) + e-X (g)
M* (g) +X (g) → MX (s)
AH = 118 kJ/mol
AH = ?
AH = -190 kJ/mol
AH = -100 kJ/mol
a)
-80 kJ
b)
-30 kJ
c)
-20 kJ
d)
20 kJ
e)
156 kJ
Chapter 11 Solutions
Bundle: Chemistry, 10th + Laboratory Handbook for General Chemistry, 3rd + Student Resource Center Printed Access Card + Student Solutions Manual for ... Access Card for Zumdahl/Zumdahl/DeCoste