CAMPBELL BIOLOGY IN FOCUS-MOD.MASTERING
3rd Edition
ISBN: 9780135191811
Author: Urry
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 11, Problem 12TYU
Summary Introduction
To determine:
The
Introduction:
In maize plant, the allele I inhibits the coloration of the kernels while the allele i expresses the coloration of the kernel. The P allele helps in achieving purple color while the p in homozygous state expresses red color.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
In corn plants, a dominant allele Z inhibits kernel color, while the recessive allele z permits color when homozygous. At a different locus, the dominant allele X causes purple kernel color, while the homozygous recessive genotype causes red kernel color. If corn plants heterozygous for both the Z and X genes are crossed, what are the chances that the offspring will have purple kernels? Enter your answer as a decimal fraction in the box (e.g. 0.25).
In the Roselle plant, the dominant allele of gene 'A' codes for a pink flower and the recessive form codes for yellow flowers, while the dominant form of gene 'B' codes
for serrated leaves, while the recessive form codes for smooth leaves. If the genes are trans linked, what are the expected genotypes and phenotypes and the
respective ratios when plants heterozygous for both genes are test crossed?
If a cross is made between two plants that are heterozygous for two traits (AaBb), then their offspring should follow the 9:3:3:1 ratio. In this case, A is the dominant allele for purple leaves, and B is the dominant allelle for curly roots. If the two parents were crossed to yield 320 progeny, approximately how many plants with purple leaves and curly roots would you expect?
Group of answer choices
a.180
b.225
c.25
d.50
As part of a lab experiment, you create a two-locus cross between two plants, and you expect to see a 8:4:2:2 ratio of offspring. You determine the phenotype for 160 offspring, and find the proportions 84:38:19:19. If you use a chi-square test to determine whether the offspring do indeed fit this pattern, how many degrees of freedom would the test have?
Group of answer choices
a.2
b.3
c.83
d.4
Chapter 11 Solutions
CAMPBELL BIOLOGY IN FOCUS-MOD.MASTERING
Ch. 11.1 - DRAW IT Pea plants heterozygous for flower...Ch. 11.1 - List all gametes that could be made by a pea plant...Ch. 11.1 - Prob. 3CCCh. 11.2 - For any gene with a dominant allele A and...Ch. 11.2 - Two organisms, with genotypes BbDD and BBDd, are...Ch. 11.2 - Prob. 3CCCh. 11.3 - Incomplete dominance and epistasis are both terms...Ch. 11.3 - Prob. 2CCCh. 11.3 - WHAT IF? A rooster with gray feathers and a hen of...Ch. 11.4 - Lucia and Jared each have a sibling with cystic...
Ch. 11.4 - MAKE CONNECTIONS In Table 11.1, note the...Ch. 11 - DRAW IT Two pea plants heterozygous for the...Ch. 11 - A man with type A blood marries a woman with type...Ch. 11 - A man has six fingers on each hand and six toes on...Ch. 11 - Prob. 4TYUCh. 11 - Flower position, stem length, and seed shape are...Ch. 11 - Prob. 6TYUCh. 11 - Prob. 7TYUCh. 11 - Prob. 8TYUCh. 11 - Prob. 9TYUCh. 11 - Prob. 10TYUCh. 11 - In tigers, a recessive allele that is pleiotropic...Ch. 11 - Prob. 12TYUCh. 11 - Prob. 13TYUCh. 11 - Imagine that you are a genetic counselor, and a...Ch. 11 - Prob. 15TYUCh. 11 - Prob. 16TYUCh. 11 - Prob. 17TYUCh. 11 - Prob. 18TYU
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- If a cross is made between two plants that are heterozygous for two traits (AaBb), then their offspring should follow the 9:3:3:1 ratio. In this case, A is the dominant allele for purple leaves, and B is the dominant allelle for curly roots. If the two parents were crossed to yield 320 progeny, approximately how many plants with purple leaves and curly roots would you expect? Group of answer choices a. 180 b.225 c.25 d.50arrow_forwardIn corn plants, a dominant allele (K) allows kernel colour and a recessive allele (k) inhibits kernel colour when homozygous. On a different chromosome, the dominant gene P causes purple kernel colour and the homozygous recessive genotype causes red kernel colour.A true breeding white corn plant was crossed with a purple corn plant, yielding 50% red corn plants and 50% purple corn plants.What are the genotypes of the parental corn plants? Select one: a. KKPp kkpp b. KkPP kkPP c. kkPp KkPp d. KKPP kkPparrow_forwardA series of experiments shows that oil content in a diploid grain is influenced by four genes (a through d) with additive alleles. A homozygous dominant strain produces 30% oil content; A homozygous recessive plant has the lowest production at 0%. A plant of unknown genotype has an oil content of 22.5%. What is a possible genotype for this plant (+ = additive alleles)? O at a+b+ bccdd Oaab+bc+ cd+d+ O at a+b+b+ cc dd O at a+b+b+c+ c+d+ d Oa+a+bb+c+c+d+ darrow_forward
- In peas, purple flowers are dominant to white. If a purple-flowered, heterozygous plant were crossed with a white-flowered plant, what is the expected ratio of genotypes and phenotypes among the F1F1offspring? If two of the purple-flowered F1F1 offspring were randomly selected and crossed, what is the expected ratio of genotypes and phenotypes among the F2F2 offspring?arrow_forwardLet us suppose that two plants are crossed (mated). One plant (female) is homozygous dominant and produces chlorophyll, and the other (male) is homozygous recessive and does not produce chlorophyll. These two plants are considered the parental, or P generation. What would be the possible genotypes and phenotypes of these two individuals? Fill in the table below with the parental generation's descriptional information. Table 6.1 Female Male Description Parental Generation Homozygous dominant P Generation Genotype gg Phenotype Greenarrow_forwardThe production of purple pigment in a certain species of flower is dependent upon two gene loci. You cross two purple flowered plants that are heterozygous at each gene locus. The offspring show the following phenotypes: 91 purple and 68 white.a. What is the simplified phenotypic ratio is observed in the offspring? What mode of inheritance is associated with this ratio? b. What is/are the genotype(s) of the purple offspring? What is/are the genotype(s) of the white offspring?arrow_forward
- Colored aleurone in the kernels of corn is due to the dominant allele R. The recessive allele r, when homozygous, produces colorless aleurone. The plant color (not the kernel color) is controlled by another gene with two alleles, Y and y. The dominant Y allele results in green color, whereas the homozygous presence of the recessive y allele causes the plant to appear yellow. In a testcross between a plant of unknown genotype and phenotype and a plant that is homozygous recessive for both traits, the following progeny were obtained: colored, green 88 colored, yellow 12 colorless, green 8 colorless, yellow 92 Explain how these results were obtained by determining the exact genotype and phenotype of the unknown plant, including the precise arrangement of the alleles on the homologs.arrow_forwardIn peaches fuzzy skin (F) is completely dominant to smooth, nectarine skin (f). The gland at the base of the leaves is controlled by a separate, unlinked locus. The gland in heterozygotes is round, while homozygotes with the Go allele have oval glands, and homozygotes with the the GN allele have no glands. A homozygous fuzzy, no-gland peach variety is bred to a smooth, oval-gland variety. The F1 offspring are interbred to produce the F2 generation. What fraction of the F2 offspring will be smooth with round glands? A) 3/16 B) 7/16 C) 4/16 D) 6/16 E) 9/16 F) 2/16 G) 12/16 H) 1/16arrow_forwardA variety of opium poppy (Papaver somniferum L.) with lacerate leaves was crossed with a variety that has normal leaves. All the F1 had lacerate leaves. Two F1 plants were interbred to produce the F2. Of the F2, 249 had lacerate leaves and 16 had normal leaves. Give genotypes for all the plants in the P, F1, and F2 generations. Explain how lacerate leaves are determined in the opium poppy.arrow_forward
- A researcher at ASU is studying the exotic Unicorn Fairy plant. The plant has three genes of interest with the dominant alleles being T-tall, H=hairy leaves and P=purple flowers. The three genes are located in different chromosomes. A trihybrid plant is crossed with a plant that is heterozygous for T and homozygous recessive for the other two genes. What is the probability of getting offspring that is tall, has hairy leaves and white flowers? 9/64 5/8 8/64 O 3/64 O 3/16arrow_forwardIn a genetic cross between a homozygous tall plant with homozygous purple flowers and a homozygous short plant with heterozygous purple flowers, how many short plants will you expect in the F2 generation if you sample 36 individuals? Both tall and purple are dominant.arrow_forwardIn chickens, comb shape is determined by genes at two loci (R, r and P, p). A walnut comb is produced when at least one dominant gene R is present at one locus and at least one dominant gene P is present at a second locus (genotype R_ P_). A rose comb is produced when at least one dominant gene is present at the first locus and two recessive genes are present at the second locus (genotype R_ pp). A pea comb is produced when two recessive genes are present at the first locus and at least one dominant gene is present at the second (genotype rr P_). If two recessive genes are present at the first and the second locus (rr pp), a single comb is produced. Give genotypes for comb shape of the parents in the following cross: Rose crossed with pea produces 20 walnut offspring. O A. Rr pp x Rr Pp B. Rr pp x rr PP C. Rr pp x rr Pp D. RR pp x rr PP O E. RR pp x rr Pp Reset Selection Mark for Douiouuarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Human Anatomy & Physiology (11th Edition)BiologyISBN:9780134580999Author:Elaine N. Marieb, Katja N. HoehnPublisher:PEARSONBiology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStaxAnatomy & PhysiologyBiologyISBN:9781259398629Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa StouterPublisher:Mcgraw Hill Education,
- Molecular Biology of the Cell (Sixth Edition)BiologyISBN:9780815344322Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter WalterPublisher:W. W. Norton & CompanyLaboratory Manual For Human Anatomy & PhysiologyBiologyISBN:9781260159363Author:Martin, Terry R., Prentice-craver, CynthiaPublisher:McGraw-Hill Publishing Co.Inquiry Into Life (16th Edition)BiologyISBN:9781260231700Author:Sylvia S. Mader, Michael WindelspechtPublisher:McGraw Hill Education
Human Anatomy & Physiology (11th Edition)
Biology
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:PEARSON
Biology 2e
Biology
ISBN:9781947172517
Author:Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher:OpenStax
Anatomy & Physiology
Biology
ISBN:9781259398629
Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa Stouter
Publisher:Mcgraw Hill Education,
Molecular Biology of the Cell (Sixth Edition)
Biology
ISBN:9780815344322
Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter Walter
Publisher:W. W. Norton & Company
Laboratory Manual For Human Anatomy & Physiology
Biology
ISBN:9781260159363
Author:Martin, Terry R., Prentice-craver, Cynthia
Publisher:McGraw-Hill Publishing Co.
Inquiry Into Life (16th Edition)
Biology
ISBN:9781260231700
Author:Sylvia S. Mader, Michael Windelspecht
Publisher:McGraw Hill Education
How to solve genetics probability problems; Author: Shomu's Biology;https://www.youtube.com/watch?v=R0yjfb1ooUs;License: Standard YouTube License, CC-BY
Beyond Mendelian Genetics: Complex Patterns of Inheritance; Author: Professor Dave Explains;https://www.youtube.com/watch?v=-EmvmBuK-B8;License: Standard YouTube License, CC-BY