(a) Interpretation: To write the general valence configuration of the nitrogen, Z=7. Concept Introduction: When the electrons are arranged in the increasing order of energy in the orbitals of an atom is known as electronic configuration of that atom. Atomic number of an atom in its neutral state is equal to the number of electrons which is unique for every element. On the basis of group of the element, one can identify the general valence configuration.
(a) Interpretation: To write the general valence configuration of the nitrogen, Z=7. Concept Introduction: When the electrons are arranged in the increasing order of energy in the orbitals of an atom is known as electronic configuration of that atom. Atomic number of an atom in its neutral state is equal to the number of electrons which is unique for every element. On the basis of group of the element, one can identify the general valence configuration.
Solution Summary: The author explains how to write the general valence configuration of the nitrogen, Z=7.
Study of body parts and their functions. In this combined field of study, anatomy refers to studying the body structure of organisms, whereas physiology refers to their function.
Chapter 11, Problem 112AP
Interpretation Introduction
(a)
Interpretation:
To write the general valence configuration of the nitrogen, Z=7.
Concept Introduction:
When the electrons are arranged in the increasing order of energy in the orbitals of an atom is known as electronic configuration of that atom. Atomic number of an atom in its neutral state is equal to the number of electrons which is unique for every element. On the basis of group of the element, one can identify the general valence configuration.
Interpretation Introduction
(b)
Interpretation:
To write the general valence configuration of the francium, Z=87.
Concept Introduction:
When the electrons are arranged in the increasing order of energy in the orbitals of an atom is known as electronic configuration of that atom. Atomic number of an atom in its neutral state is equal to the number of electrons which is unique for every element. On the basis of group of the element, one can identify the general valence configuration.
Interpretation Introduction
(c)
Interpretation:
To write the general valence configuration of the chlorine, Z=17.
Concept Introduction:
When the electrons are arranged in the increasing order of energy in the orbitals of an atom is known as electronic configuration of that atom. Atomic number of an atom in its neutral state is equal to the number of electrons which is unique for every element. On the basis of group of the element, one can identify the general valence configuration.
Interpretation Introduction
(d)
Interpretation:
To write the general valence configuration of the selenium, Z=34.
Concept Introduction:
When the electrons are arranged in the increasing order of energy in the orbitals of an atom is known as electronic configuration of that atom. Atomic number of an atom in its neutral state is equal to the number of electrons which is unique for every element. On the basis of group of the element, one can identify the general valence configuration.
Interpretation Introduction
(e)
Interpretation:
To write the general valence configuration of the magnesium, Z=12.
Concept Introduction:
When the electrons are arranged in the increasing order of energy in the orbitals of an atom is known as electronic configuration of that atom. Atomic number of an atom in its neutral state is equal to the number of electrons which is unique for every element. On the basis of group of the element, one can identify the general valence configuration.
Part II. Given two isomers: 2-methylpentane (A) and 2,2-dimethyl butane (B) answer the following:
(a) match structures of isomers given their mass spectra below (spectra A and spectra B)
(b) Draw the fragments given the following prominent peaks from
each spectrum:
Spectra A m/2 =43 and 1/2-57
spectra B m/2 = 43
(c) why is 1/2=57 peak in spectrum A more intense compared
to the same peak in spectrum B.
Relative abundance
Relative abundance
100
A
50
29
29
0
10
-0
-0
100
B
50
720
30
41
43
57
71
4-0
40
50
60 70
m/z
43
57
8-0
m/z = 86
M
90 100
71
m/z = 86
M
-O
0
10 20 30
40 50
60
70
80
-88
m/z
90
100
Part IV. C6H5 CH2CH2OH is an aromatic compound which was subjected to Electron Ionization - mass
spectrometry (El-MS) analysis. Prominent m/2 values: m/2 = 104 and m/2 = 9) was obtained.
Draw the structures of these fragments.
For each reaction shown below follow the curved arrows to complete each equationby showing the structure of the products. Identify the acid, the base, the conjugated acid andconjugated base. Consutl the pKa table and choose the direciton theequilibrium goes. However show the curved arrows. Please explain if possible.
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell