
Concept explainers
a. Support for raising fees by gender
Support? | Gender | ||
Males | Females | Totals | |
For | 12 | 7 | 19 |
Against Totals |
|
|
|
b. Support for raising fees by discipline
Support? | Discipline | ||
Liberal Arts | Science and Business | Totals | |
For | 6 | 13 | 19 |
Against Totals |
|
|
|
c. Support for raising fees by tenured status
Support? | Status | ||
Tenured | Nontenured | Totals | |
For | 15 | 4 | 19 |
Against Totals |
|
|
|

(a)
To find:
The column percentages and maximum difference.
Answer to Problem 11.1P
Solution:
The column percentage table of the given data is,
Support? | Gender | |
Males | Females | |
For | 44.44% | 35% |
Against | 55.56% | 65% |
Totals | 100% | 100% |
The maximum difference is 9.44%.
The strength of association is weak.
In the column table, high percentage of one variable is associated with low percentage of another variable, therefore there is a positive association between the variables.
Explanation of Solution
Given:
The given statement is,
The administration of a local college campus wants to increase the mandatory student fee to finance an upgrading of the football program. A survey of a sample of faculty regarding this proposal has been completed.
The given table of information is,
Support? | Gender | ||
Males | Females | Totals | |
For | 12 | 7 | 19 |
Against | 15 | 13 | 38 |
Totals | 27 | 20 | 47 |
Approach:
If the maximum difference of the smallest and the largest column percentage in a row is less than 10%, it is said that there is a weak association between the categories.
If the maximum difference is between 10% and 30%, it is said that there is a moderate association between the categories and if the maximum difference is above 30%, then there is a high association between the categories.
Calculation:
From the given information,
The following table gives the column wise percentages based on gender.
Support? | Gender | |
Males | Females | |
For | 44.44% | 35% |
Against | 55.56% | 65% |
Totals | 100% | 100% |
The columns of the table are computed as,
Substitute the values from the given table of information,
Proceed in a similar manner to obtain rest of the values of the table.
For the first row,
The maximum percentage is 44.44%.
The minimum percentage is 35%.
The difference is given as,
The difference for the first row is 9.44%.
For the second row,
The maximum percentage is 65%.
The minimum percentage is 55.56%.
The difference is given as,
The difference for the second row is 9.44%.
The maximum difference is 9.44%.
Since, 9.44% is less than 10%, it shows that the strength of association is weak.
In the column table, high percentage of one variable is associated with low percentage of another variable, therefore there is a positive association between the variables.
Conclusion:
The column percentage table of the given data is,
Support? | Gender | |
Males | Females | |
For | 44.44% | 35% |
Against | 55.56% | 65% |
Totals | 100% | 100% |
The maximum difference is 9.44%.
The strength of association is weak.
In the column table, high percentage of one variable is associated with low percentage of another variable, therefore there is a positive association between the variables.

(b)
To find:
The column percentages and maximum difference.
Answer to Problem 11.1P
Solution:
The column percentage table of the given data is,
Support? | Discipline | |
Liberal Arts | Science and Business | |
For | 30% | 48.15% |
Against | 70% | 51.85% |
Totals | 100% | 100% |
The maximum difference is 18.15%.
The strength of association is moderate.
In the column table, high percentage of one variable is associated with low percentage of another variable, therefore there is a positive association between the variables.
Explanation of Solution
Given:
The given statement is,
The administration of a local college campus wants to increase the mandatory student fee to finance an upgrading of the football program. A survey of a sample of faculty regarding this proposal has been completed.
The given table of information is,
Support? | Discipline | ||
Liberal Arts | Science and Business | Totals | |
For | 6 | 13 | 19 |
Against | 14 | 14 | 38 |
Totals | 20 | 27 | 47 |
Approach:
If the maximum difference of the smallest and the largest column percentage in a row is less than 10%, it is said that there is a weak association between the categories.
If the maximum difference is between 10% and 30%, it is said that there is a moderate association between the categories and if the maximum difference is above 30%, then there is a high association between the categories.
Calculation:
From the given information,
The following table gives the column wise percentages based on discipline.
Support? | Discipline | |
Liberal Arts | Science and Business | |
For | 30% | 48.15% |
Against | 70% | 51.85% |
Totals | 100% | 100% |
The columns of the table are computed as,
Substitute the values from the given table of information,
Proceed in a similar manner to obtain rest of the values of the table.
For the first row,
The maximum percentage is 48.15%.
The minimum percentage is 30%.
The difference is given as,
The difference for the first row is 18.15%.
For the second row,
The maximum percentage is 70%.
The minimum percentage is 51.85%.
The difference is given as,
The difference for the second row is 18.15%.
The maximum difference is 18.15%.
Since, 18.15% is between 10% and 30%, it shows that the strength of association is moderate
In the column table, high percentage of one variable is associated with low percentage of another variable, therefore there is a positive association between the variables.
Conclusion:
The column percentage table of the given data is,
Support? | Discipline | |
Liberal Arts | Science and Business | |
For | 30% | 48.15% |
Against | 70% | 51.85% |
Totals | 100% | 100% |
The maximum difference is 18.15%.
The strength of association is moderate.
In the column table, high percentage of one variable is associated with low percentage of another variable, therefore there is a positive association between the variables.

(c)
To find:
The column percentages and maximum difference.
Answer to Problem 11.1P
Solution:
The column percentage table of the given data is,
Support? | Discipline | |
Tenured | Nontenured | |
For | 45.45% | 28.57% |
Against | 54.55% | 71.43% |
Totals | 100% | 100% |
The maximum difference is 16.88%.
The strength of association is moderate.
In the column table, high percentage of one variable is associated with low percentage of another variable, therefore there is a positive association between the variables.
Explanation of Solution
Given:
The given statement is,
The administration of a local college campus wants to increase the mandatory student fee to finance an upgrading of the football program. A survey of a sample of faculty regarding this proposal has been completed.
The given table of information is,
Support? | Status | ||
Tenured | Nontenured | Totals | |
For | 15 | 4 | 19 |
Against | 18 | 10 | 38 |
Totals | 33 | 14 | 47 |
Approach:
If the maximum difference of the smallest and the largest column percentage in a row is less than 10%, it is said that there is a weak association between the categories.
If the maximum difference is between 10% and 30%, it is said that there is a moderate association between the categories and if the maximum difference is above 30%, then there is a high association between the categories.
Calculation:
From the given information,
The following table gives the column wise percentages based on tenured status.
Support? | Status | |
Tenured | Nontenured | |
For | 45.45% | 28.57% |
Against | 54.55% | 71.43% |
Totals | 100% | 100% |
The columns of the table are computed as,
Substitute the values from the given table of information,
Proceed in a similar manner to obtain rest of the values of the table.
For the first row,
The maximum percentage is 45.45%.
The minimum percentage is 28.57%.
The difference is given as,
The difference for the first row is 16.88%.
For the second row,
The maximum percentage is 71.43%.
The minimum percentage is 54.55%.
The difference is given as,
The difference for the second row is 16.88%.
The maximum difference is 16.88%.
Since, 16.88% is between 10% and 30%, it shows that the strength of association is moderate
In the column table, high percentage of one variable is associated with low percentage of another variable, therefore there is a positive association between the variables.
Conclusion:
The column percentage table of the given data is,
Support? | Discipline | |
Tenured | Nontenured | |
For | 45.45% | 28.57% |
Against | 54.55% | 71.43% |
Totals | 100% | 100% |
The maximum difference is 16.88%.
The strength of association is moderate.
In the column table, high percentage of one variable is associated with low percentage of another variable, therefore there is a positive association between the variables.
Want to see more full solutions like this?
Chapter 11 Solutions
Essentials Of Statistics
- 4. [20] Let {X1,..., X} be a random sample from a continuous distribution with PDF f(x; 0) = { Axe 5 0, x > 0, otherwise. where > 0 is an unknown parameter. Let {x1,...,xn} be an observed sample. (a) Find the value of c in the PDF. (b) Find the likelihood function of 0. (c) Find the MLE, Ô, of 0. (d) Find the bias and MSE of 0.arrow_forward3. [20] Let {X1,..., Xn} be a random sample from a binomial distribution Bin(30, p), where p (0, 1) is unknown. Let {x1,...,xn} be an observed sample. (a) Find the likelihood function of p. (b) Find the MLE, p, of p. (c) Find the bias and MSE of p.arrow_forwardGiven the sample space: ΩΞ = {a,b,c,d,e,f} and events: {a,b,e,f} A = {a, b, c, d}, B = {c, d, e, f}, and C = {a, b, e, f} For parts a-c: determine the outcomes in each of the provided sets. Use proper set notation. a. (ACB) C (AN (BUC) C) U (AN (BUC)) AC UBC UCC b. C. d. If the outcomes in 2 are equally likely, calculate P(AN BNC).arrow_forward
- Suppose a sample of O-rings was obtained and the wall thickness (in inches) of each was recorded. Use a normal probability plot to assess whether the sample data could have come from a population that is normally distributed. Click here to view the table of critical values for normal probability plots. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. 0.191 0.186 0.201 0.2005 0.203 0.210 0.234 0.248 0.260 0.273 0.281 0.290 0.305 0.310 0.308 0.311 Using the correlation coefficient of the normal probability plot, is it reasonable to conclude that the population is normally distributed? Select the correct choice below and fill in the answer boxes within your choice. (Round to three decimal places as needed.) ○ A. Yes. The correlation between the expected z-scores and the observed data, , exceeds the critical value, . Therefore, it is reasonable to conclude that the data come from a normal population. ○…arrow_forwardding question ypothesis at a=0.01 and at a = 37. Consider the following hypotheses: 20 Ho: μ=12 HA: μ12 Find the p-value for this hypothesis test based on the following sample information. a. x=11; s= 3.2; n = 36 b. x = 13; s=3.2; n = 36 C. c. d. x = 11; s= 2.8; n=36 x = 11; s= 2.8; n = 49arrow_forward13. A pharmaceutical company has developed a new drug for depression. There is a concern, however, that the drug also raises the blood pressure of its users. A researcher wants to conduct a test to validate this claim. Would the manager of the pharmaceutical company be more concerned about a Type I error or a Type II error? Explain.arrow_forward
- Find the z score that corresponds to the given area 30% below z.arrow_forwardFind the following probability P(z<-.24)arrow_forward3. Explain why the following statements are not correct. a. "With my methodological approach, I can reduce the Type I error with the given sample information without changing the Type II error." b. "I have already decided how much of the Type I error I am going to allow. A bigger sample will not change either the Type I or Type II error." C. "I can reduce the Type II error by making it difficult to reject the null hypothesis." d. "By making it easy to reject the null hypothesis, I am reducing the Type I error."arrow_forward
- Given the following sample data values: 7, 12, 15, 9, 15, 13, 12, 10, 18,12 Find the following: a) Σ x= b) x² = c) x = n d) Median = e) Midrange x = (Enter a whole number) (Enter a whole number) (use one decimal place accuracy) (use one decimal place accuracy) (use one decimal place accuracy) f) the range= g) the variance, s² (Enter a whole number) f) Standard Deviation, s = (use one decimal place accuracy) Use the formula s² ·Σx² -(x)² n(n-1) nΣ x²-(x)² 2 Use the formula s = n(n-1) (use one decimal place accuracy)arrow_forwardTable of hours of television watched per week: 11 15 24 34 36 22 20 30 12 32 24 36 42 36 42 26 37 39 48 35 26 29 27 81276 40 54 47 KARKE 31 35 42 75 35 46 36 42 65 28 54 65 28 23 28 23669 34 43 35 36 16 19 19 28212 Using the data above, construct a frequency table according the following classes: Number of Hours Frequency Relative Frequency 10-19 20-29 |30-39 40-49 50-59 60-69 70-79 80-89 From the frequency table above, find a) the lower class limits b) the upper class limits c) the class width d) the class boundaries Statistics 300 Frequency Tables and Pictures of Data, page 2 Using your frequency table, construct a frequency and a relative frequency histogram labeling both axes.arrow_forwardTable of hours of television watched per week: 11 15 24 34 36 22 20 30 12 32 24 36 42 36 42 26 37 39 48 35 26 29 27 81276 40 54 47 KARKE 31 35 42 75 35 46 36 42 65 28 54 65 28 23 28 23669 34 43 35 36 16 19 19 28212 Using the data above, construct a frequency table according the following classes: Number of Hours Frequency Relative Frequency 10-19 20-29 |30-39 40-49 50-59 60-69 70-79 80-89 From the frequency table above, find a) the lower class limits b) the upper class limits c) the class width d) the class boundaries Statistics 300 Frequency Tables and Pictures of Data, page 2 Using your frequency table, construct a frequency and a relative frequency histogram labeling both axes.arrow_forward
- Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw HillBig Ideas Math A Bridge To Success Algebra 1: Stu...AlgebraISBN:9781680331141Author:HOUGHTON MIFFLIN HARCOURTPublisher:Houghton Mifflin HarcourtHolt Mcdougal Larson Pre-algebra: Student Edition...AlgebraISBN:9780547587776Author:HOLT MCDOUGALPublisher:HOLT MCDOUGAL


