CHEMISTRY:ATOMS FIRST-2 YEAR CONNECT
2nd Edition
ISBN: 9781260592320
Author: Burdge
Publisher: MCG
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Chapter 11, Problem 11.151QP
Interpretation Introduction
Interpretation:
The volume around each atom into which the center of another atom cannot penetrate , the excluded volume for 1 mole of the atoms and the volume compare with the sum of the volume of 1 mole of the atoms have to be explained.
Concept introduction:
The volume around each atom into which the centre of another atom cannot penetrate is called the excluded volume. To determine the excluded volume, use the formula for volume of a sphere to calculate the volume of a sphere of radius
The atoms are spherical, the equation for the volume of a sphere is
Multiply the excluded volume per molecule by
Avogadro’s number is
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A sample of 3.54 mol of krypton is confined at low pressure in a volume at a temperature of 56 °C. Describe
quantitatively the effects of each of the following changes on the pressure, the average kinetic energy per
molecule in the gas, and the root-mean-square speed.
(a) The temperature is decreased to -44 °C.
(b) The volume is tripled.
(c) The amount of krypton is increased to 4.84 mol.
Give each answer as a decimal factor of the form: new value = factor old value. A factor of 1 means no
change.
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A flask at room temperature contains equal numbers of di-nitrogen molecules and krypton atoms. (a) Which of the two gases exerts the higher partial pressure? (b) Which gas has a higher kinetic energy per molecule/atom? (c) Which gas has molecules with a higher velocity? Explain your answers.
There are two particles, one is heavy and the other is light. The light particles diffuse faster than the heavy particles. This relationship is known as Graham’s Law of Effusion. Since both gases are at the same temperature, they must have the same average kinetic energy (½ mv2), where m is mass and v is the velocity (like speed). Since both gases have the same average kinetic energy, you can state that ½ mLvL2 = ½ mHvH2. Multiplying both sides by 2 gives you mLvL2 = mHvH2. Rearranging the equation to get both masses on the same side of the equation will give you mL/mH = VH2/VL2. In 3a and 3b, you probably noticed that the heavy gas particles took twice as long to diffuse as the light gas particles. This means that the light gas particles are moving twice as fast, VH/VL = ½. Therefore, VH2/VL2 = ¼. How many times heavier is the heavy gas compared to the light gas? If the light gas was Ne, what would be a reasonable identity for the heavy gas?
Chapter 11 Solutions
CHEMISTRY:ATOMS FIRST-2 YEAR CONNECT
Ch. 11.2 - Prob. 11.1WECh. 11.2 - Prob. 1PPACh. 11.2 - Prob. 1PPBCh. 11.2 - Prob. 1PPCCh. 11.2 - Prob. 11.2.1SRCh. 11.2 - Prob. 11.2.2SRCh. 11.3 - Prob. 11.2WECh. 11.3 - Prob. 2PPACh. 11.3 - Prob. 2PPBCh. 11.3 - Arrange the four columns of liquid [(i)(iv)] in...
Ch. 11.3 - Prob. 11.3.1SRCh. 11.3 - Prob. 11.3.2SRCh. 11.3 - Prob. 11.3.3SRCh. 11.3 - Prob. 11.3.4SRCh. 11.3 - Prob. 11.3.5SRCh. 11.4 - Prob. 11.3WECh. 11.4 - Prob. 3PPACh. 11.4 - Prob. 3PPBCh. 11.4 - Prob. 3PPCCh. 11.4 - Prob. 11.4WECh. 11.4 - Prob. 4PPACh. 11.4 - Prob. 4PPBCh. 11.4 - Prob. 4PPCCh. 11.4 - If we combine 3.0 L of NO and 1.5 L of O2, and...Ch. 11.4 - What volume (in liters) of water vapor will be...Ch. 11.4 - Prob. 5PPBCh. 11.4 - Prob. 5PPCCh. 11.4 - Prob. 11.6WECh. 11.4 - Prob. 6PPACh. 11.4 - Prob. 6PPBCh. 11.4 - Prob. 6PPCCh. 11.4 - Prob. 11.4.1SRCh. 11.4 - Prob. 11.4.2SRCh. 11.4 - Prob. 11.4.3SRCh. 11.4 - Prob. 11.4.4SRCh. 11.4 - Prob. 11.4.5SRCh. 11.4 - Prob. 11.4.6SRCh. 11.5 - Prob. 11.7WECh. 11.5 - Prob. 7PPACh. 11.5 - Prob. 7PPBCh. 11.5 - Prob. 7PPCCh. 11.5 - Prob. 11.8WECh. 11.5 - Prob. 8PPACh. 11.5 - Prob. 8PPBCh. 11.5 - Prob. 8PPCCh. 11.5 - Prob. 11.9WECh. 11.5 - Prob. 9PPACh. 11.5 - Prob. 9PPBCh. 11.5 - Prob. 9PPCCh. 11.5 - Prob. 11.5.1SRCh. 11.5 - Prob. 11.5.2SRCh. 11.5 - Prob. 11.5.3SRCh. 11.5 - Prob. 11.5.4SRCh. 11.6 - Prob. 11.10WECh. 11.6 - Prob. 10PPACh. 11.6 - Prob. 10PPBCh. 11.6 - Prob. 10PPCCh. 11.6 - Prob. 11.11WECh. 11.6 - Determine the excluded volume per mole and the...Ch. 11.6 - Prob. 11PPBCh. 11.6 - Prob. 11PPCCh. 11.6 - Prob. 11.6.1SRCh. 11.6 - Prob. 11.6.2SRCh. 11.7 - Prob. 11.12WECh. 11.7 - Prob. 12PPACh. 11.7 - Prob. 12PPBCh. 11.7 - Prob. 12PPCCh. 11.7 - Prob. 11.13WECh. 11.7 - Prob. 13PPACh. 11.7 - Prob. 13PPBCh. 11.7 - Prob. 13PPCCh. 11.7 - Prob. 11.7.1SRCh. 11.7 - Prob. 11.7.2SRCh. 11.7 - Prob. 11.7.3SRCh. 11.7 - Prob. 11.7.4SRCh. 11.7 - Prob. 11.7.5SRCh. 11.8 - Prob. 11.14WECh. 11.8 - Prob. 14PPACh. 11.8 - Prob. 14PPBCh. 11.8 - Prob. 14PPCCh. 11.8 - Prob. 11.15WECh. 11.8 - Prob. 15PPACh. 11.8 - Prob. 15PPBCh. 11.8 - Prob. 15PPCCh. 11.8 - Calcium metal reacts with water to produce...Ch. 11.8 - Prob. 16PPACh. 11.8 - Determine the volume of gas collected over water...Ch. 11.8 - Prob. 16PPCCh. 11.8 - Prob. 11.8.1SRCh. 11.8 - Prob. 11.8.2SRCh. 11.8 - Prob. 11.8.3SRCh. 11 - Prob. 11.1QPCh. 11 - Prob. 11.2QPCh. 11 - Prob. 11.3QPCh. 11 - Prob. 11.4QPCh. 11 - Prob. 11.5QPCh. 11 - Prob. 11.6QPCh. 11 - Prob. 11.7QPCh. 11 - Prob. 11.8QPCh. 11 - Prob. 11.9QPCh. 11 - Prob. 11.10QPCh. 11 - Prob. 11.11QPCh. 11 - The 235U isotope undergoes fission when bombarded...Ch. 11 - Prob. 11.13QPCh. 11 - Prob. 11.14QPCh. 11 - Prob. 11.15QPCh. 11 - Prob. 11.16QPCh. 11 - Prob. 11.17QPCh. 11 - Prob. 11.18QPCh. 11 - Prob. 11.19QPCh. 11 - Prob. 11.20QPCh. 11 - Prob. 11.21QPCh. 11 - Prob. 11.22QPCh. 11 - Prob. 11.23QPCh. 11 - Prob. 11.24QPCh. 11 - Prob. 11.25QPCh. 11 - Prob. 11.26QPCh. 11 - Prob. 11.27QPCh. 11 - Prob. 11.28QPCh. 11 - Prob. 11.29QPCh. 11 - Prob. 11.30QPCh. 11 - Prob. 11.31QPCh. 11 - A sample of air occupies 3.8 L when the pressure...Ch. 11 - Prob. 11.33QPCh. 11 - Prob. 11.34QPCh. 11 - Prob. 11.35QPCh. 11 - Prob. 11.36QPCh. 11 - Prob. 11.37QPCh. 11 - Prob. 11.38QPCh. 11 - A gaseous sample of a substance is cooled at...Ch. 11 - Prob. 11.40QPCh. 11 - Prob. 11.41QPCh. 11 - Prob. 11.42QPCh. 11 - Prob. 11.43QPCh. 11 - Prob. 11.44QPCh. 11 - Prob. 11.45QPCh. 11 - Prob. 11.46QPCh. 11 - Prob. 11.47QPCh. 11 - Prob. 11.48QPCh. 11 - Prob. 11.49QPCh. 11 - Prob. 11.50QPCh. 11 - Prob. 11.51QPCh. 11 - Prob. 11.52QPCh. 11 - Prob. 11.53QPCh. 11 - Prob. 11.54QPCh. 11 - Prob. 11.55QPCh. 11 - Prob. 11.56QPCh. 11 - Prob. 11.57QPCh. 11 - A certain anesthetic contains 64.9 percent C, 13.5...Ch. 11 - A compound has the empirical formula SF4. At 20C,...Ch. 11 - Prob. 11.60QPCh. 11 - Prob. 11.61QPCh. 11 - Prob. 11.62QPCh. 11 - Prob. 11.63QPCh. 11 - Write the van der Waals equation for a real gas....Ch. 11 - Prob. 11.65QPCh. 11 - Prob. 11.66QPCh. 11 - Prob. 11.67QPCh. 11 - Prob. 11.68QPCh. 11 - Prob. 11.69QPCh. 11 - Prob. 11.70QPCh. 11 - Prob. 11.71QPCh. 11 - Prob. 11.72QPCh. 11 - Prob. 11.73QPCh. 11 - Prob. 11.74QPCh. 11 - Prob. 11.75QPCh. 11 - Prob. 11.76QPCh. 11 - Prob. 11.77QPCh. 11 - Prob. 11.78QPCh. 11 - Prob. 11.79QPCh. 11 - Prob. 11.1VCCh. 11 - Prob. 11.2VCCh. 11 - Prob. 11.3VCCh. 11 - Prob. 11.4VCCh. 11 - Prob. 11.80QPCh. 11 - Prob. 11.81QPCh. 11 - Prob. 11.82QPCh. 11 - Prob. 11.83QPCh. 11 - Prob. 11.84QPCh. 11 - Prob. 11.85QPCh. 11 - Prob. 11.86QPCh. 11 - Prob. 11.87QPCh. 11 - Prob. 11.88QPCh. 11 - Ethanol (C2H5OH) bums in air: C2H5OH(l) + O2(g) ...Ch. 11 - Prob. 11.90QPCh. 11 - Prob. 11.91QPCh. 11 - Prob. 11.92QPCh. 11 - Prob. 11.93QPCh. 11 - Prob. 11.94QPCh. 11 - Prob. 11.95QPCh. 11 - Prob. 11.96QPCh. 11 - Prob. 11.97QPCh. 11 - Prob. 11.98QPCh. 11 - Prob. 11.99QPCh. 11 - Prob. 11.100QPCh. 11 - Prob. 11.101QPCh. 11 - Prob. 11.102QPCh. 11 - Prob. 11.103QPCh. 11 - Prob. 11.104QPCh. 11 - Prob. 11.105QPCh. 11 - Prob. 11.106QPCh. 11 - Prob. 11.107QPCh. 11 - Prob. 11.108QPCh. 11 - Prob. 11.109QPCh. 11 - A 180.0-mg sample of an alloy of iron and metal X...Ch. 11 - Prob. 11.111QPCh. 11 - Prob. 11.112QPCh. 11 - Prob. 11.113QPCh. 11 - Prob. 11.114QPCh. 11 - Prob. 11.115QPCh. 11 - Prob. 11.116QPCh. 11 - Prob. 11.117QPCh. 11 - Prob. 11.118QPCh. 11 - Prob. 11.119QPCh. 11 - Prob. 11.120QPCh. 11 - Prob. 11.121QPCh. 11 - Prob. 11.122QPCh. 11 - Prob. 11.123QPCh. 11 - Prob. 11.124QPCh. 11 - Prob. 11.125QPCh. 11 - Acidic oxides such as carbon dioxide react with...Ch. 11 - Prob. 11.127QPCh. 11 - Prob. 11.128QPCh. 11 - Prob. 11.129QPCh. 11 - Prob. 11.130QPCh. 11 - Prob. 11.131QPCh. 11 - Prob. 11.132QPCh. 11 - Prob. 11.133QPCh. 11 - Prob. 11.134QPCh. 11 - Prob. 11.135QPCh. 11 - Prob. 11.136QPCh. 11 - Prob. 11.137QPCh. 11 - Prob. 11.138QPCh. 11 - Prob. 11.139QPCh. 11 - Prob. 11.140QPCh. 11 - Prob. 11.141QPCh. 11 - At what temperature will He atoms have the same...Ch. 11 - Prob. 11.143QPCh. 11 - Prob. 11.144QPCh. 11 - Prob. 11.145QPCh. 11 - Prob. 11.146QPCh. 11 - Prob. 11.147QPCh. 11 - Prob. 11.148QPCh. 11 - Prob. 11.149QPCh. 11 - Prob. 11.150QPCh. 11 - Prob. 11.151QPCh. 11 - A 5.00-mole sample of NH3 gas is kept in a 1.92-L...Ch. 11 - Prob. 11.153QPCh. 11 - Prob. 11.154QPCh. 11 - Prob. 11.155QPCh. 11 - Prob. 11.156QPCh. 11 - Prob. 11.157QPCh. 11 - Prob. 11.158QPCh. 11 - Prob. 11.159QPCh. 11 - Prob. 11.160QPCh. 11 - Prob. 11.161QPCh. 11 - Determine the mole fraction of helium in a gaseous...Ch. 11 - Prob. 11.2KSPCh. 11 - Prob. 11.3KSPCh. 11 - Prob. 11.4KSP
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