Explanation Procedure used: 1. Divide the first term of the dividend by the first term of the divisor. The partial quotient is placed above the first term of the dividend. 2. Multiply the partial quotient times the divisor and align the product under like terms of the dividend. 3. Subtract. 4. Bring down the next term of the dividend and repeat Steps 1-3. 5. Repeat Steps 1-4 until all terms of the dividend have been brought down. The result of the last subtraction is the remainder. 6. Write the remainder as a fraction with the remainder as the numerator and the divisor as the denominator. Calculation: Use the above procedure to simplify the expression 2 x 2 − x − 1 6 x 3 − x 2 − 4 x − 1 as follows. 2 x 2 − x − 1 3 x + 1 6 x 3 − x 2 − 4 x − 1 6 x 3 − 3 x 2 − 3 x _ <

College Mathematics for Trades and Technologies (10th Edition) (What's New in Trade Math)

10th Edition

ISBN: 9780134690339

Author: Cheryl Cleaves, Margie Hobbs

Publisher: PEARSON

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Chapter 11, Problem 101RE

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To divide: The expression 6x3−x2−4x−1 by the expression 2x2−x−1.

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Chapter 11, Problem 100RE

Chapter 11, Problem 1CA

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Chapter 11 Solutions

College Mathematics for Trades and Technologies (10th Edition) (What's New in Trade Math)

Ch. 11.1 - Prob. 1LC Ch. 11.1 - Prob. 2LC Ch. 11.1 - Prob. 1E Ch. 11.1 - Prob. 2E Ch. 11.1 - Prob. 3E Ch. 11.1 - Prob. 4E Ch. 11.1 - Prob. 5E Ch. 11.1 - Prob. 6E Ch. 11.1 - Prob. 7E Ch. 11.1 - Write the products. See Example 1. 2x3(5x8)

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To divide: The expression 6 x 3 − x 2 − 4 x − 1 by the expression 2 x 2 − x − 1 .

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To divide: The expression 6x3−x2−4x−1 by the expression 2x2−x−1.

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Chapter 11 Solutions