Mathematics All Around (6th Edition)
6th Edition
ISBN: 9780134434681
Author: Tom Pirnot
Publisher: PEARSON
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Chapter 10.CR, Problem 6CR
To determine
To Explain:
The reason why the Huntington–Hill apportionment principle will avoid an Alabama paradox.
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Chapter 10 Solutions
Mathematics All Around (6th Edition)
Ch. 10.1 - Sharpening your Skills In Exercises 1-6, use the...Ch. 10.1 - Sharpening your Skills In Exercises 1-6, use the...Ch. 10.1 - Sharpening your Skills In Exercises 1-6, use the...Ch. 10.1 - Sharpening your Skills In Exercises 1-6, use the...Ch. 10.1 - Sharpening your Skills In Exercises 1-6, use the...Ch. 10.1 - Prob. 6ECh. 10.1 - Sharpening Your Skills If the American Nurses...Ch. 10.1 - Prob. 8ECh. 10.1 - Sharpening your Skills Which state is more poorly...Ch. 10.1 - Prob. 10E
Ch. 10.1 - Sharpening your Skills Recall that on a 10-member...Ch. 10.1 - Sharpening your Skills Redo Exercise 11 for Aroco...Ch. 10.1 - Sharpening your Skills Apportioning...Ch. 10.1 - Sharpening your Skills Apportioning...Ch. 10.1 - Applying What Youve Learned The Alabama paradox....Ch. 10.1 - Applying What Youve Learned The Alabama paradox....Ch. 10.1 - Applying What Youve Learned The Alabama paradox...Ch. 10.1 - Prob. 18ECh. 10.1 - Prob. 19ECh. 10.1 - Prob. 20ECh. 10.1 - Prob. 21ECh. 10.1 - Prob. 25ECh. 10.1 - Prob. 26ECh. 10.1 - Prob. 27ECh. 10.1 - Prob. 28ECh. 10.2 - Prob. 1ECh. 10.2 - Prob. 2ECh. 10.2 - Prob. 3ECh. 10.2 - Prob. 4ECh. 10.2 - Prob. 5ECh. 10.2 - Prob. 6ECh. 10.2 - Prob. 7ECh. 10.2 - Prob. 8ECh. 10.2 - Prob. 9ECh. 10.2 - Prob. 10ECh. 10.2 - Prob. 11ECh. 10.2 - Prob. 12ECh. 10.2 - Prob. 13ECh. 10.2 - Prob. 14ECh. 10.2 - Prob. 15ECh. 10.2 - Prob. 16ECh. 10.2 - Prob. 17ECh. 10.2 - Prob. 18ECh. 10.2 - Prob. 19ECh. 10.2 - Prob. 20ECh. 10.2 - Prob. 21ECh. 10.2 - Prob. 22ECh. 10.2 - Prob. 23ECh. 10.2 - Prob. 24ECh. 10.2 - Prob. 25ECh. 10.2 - Prob. 26ECh. 10.2 - Prob. 27ECh. 10.2 - Prob. 28ECh. 10.2 - Prob. 29ECh. 10.2 - Prob. 30ECh. 10.2 - Prob. 31ECh. 10.2 - Prob. 32ECh. 10.2 - Prob. 33ECh. 10.2 - Prob. 34ECh. 10.3 - In Exercises 1-4, we give you a total population,...Ch. 10.3 - Prob. 2ECh. 10.3 - In Exercises 1-4, we give you a total population,...Ch. 10.3 - Prob. 4ECh. 10.3 - Prob. 5ECh. 10.3 - Use the Jefferson method to assign the seats on...Ch. 10.3 - Prob. 7ECh. 10.3 - Prob. 8ECh. 10.3 - Choosing representatives on a negotiations...Ch. 10.3 - Prob. 10ECh. 10.3 - Prob. 11ECh. 10.3 - Use the Webster method to apportion the members of...Ch. 10.3 - Prob. 13ECh. 10.3 - Prob. 14ECh. 10.3 - Prob. 15ECh. 10.3 - Prob. 16ECh. 10.3 - Prob. 17ECh. 10.3 - Prob. 18ECh. 10.3 - Prob. 19ECh. 10.3 - Prob. 20ECh. 10.3 - Prob. 21ECh. 10.3 - Prob. 22ECh. 10.3 - Prob. 23ECh. 10.3 - Use the Webster method to assign the number of...Ch. 10.3 - Prob. 25ECh. 10.3 - Prob. 26ECh. 10.3 - Prob. 27ECh. 10.3 - In Exercises 25-32, we use the Hamilton method to...Ch. 10.3 - Prob. 29ECh. 10.3 - Prob. 30ECh. 10.3 - In Exercises 25-32, we use the Hamilton method to...Ch. 10.3 - In Exercises 25-32, we use the Hamilton method to...Ch. 10.3 - Exercises 33-36Illustrate that the Jefferson and...Ch. 10.3 - Prob. 34ECh. 10.3 - Prob. 35ECh. 10.3 - Prob. 36ECh. 10.3 - Prob. 37ECh. 10.3 - Prob. 38ECh. 10.3 - Prob. 39ECh. 10.3 - Prob. 40ECh. 10.3 - Prob. 43ECh. 10.3 - Prob. 44ECh. 10.3 - Prob. 45ECh. 10.3 - Prob. 46ECh. 10.3 - Prob. 47ECh. 10.4 - Identify each situation as dealing with either...Ch. 10.4 - Identify each situation as dealing with either...Ch. 10.4 - Use the method of sealed bids to complete the...Ch. 10.4 - Prob. 4ECh. 10.4 - Use the method of sealed bids to complete the...Ch. 10.4 - Prob. 6ECh. 10.4 - Prob. 7ECh. 10.4 - Prob. 8ECh. 10.4 - Prob. 9ECh. 10.4 - Use the method of sealed bids to complete the...Ch. 10.4 - Prob. 11ECh. 10.4 - Prob. 12ECh. 10.4 - Prob. 13ECh. 10.4 - Prob. 14ECh. 10.4 - Prob. 15ECh. 10.4 - In Exercises 15 and 16, use the method of sealed...Ch. 10.4 - Prob. 17ECh. 10.4 - Prob. 18ECh. 10.4 - Prob. 19ECh. 10.4 - Prob. 20ECh. 10.4 - Prob. 21ECh. 10.4 - Prob. 22ECh. 10.4 - Prob. 23ECh. 10.4 - Prob. 24ECh. 10.4 - Prob. 25ECh. 10.4 - Prob. 26ECh. 10.4 - Prob. 27ECh. 10.4 - Prob. 28ECh. 10.CR - Prob. 1CRCh. 10.CR - Prob. 2CRCh. 10.CR - Prob. 3CRCh. 10.CR - Prob. 4CRCh. 10.CR - Prob. 5CRCh. 10.CR - Prob. 6CRCh. 10.CR - Prob. 7CRCh. 10.CR - Prob. 8CRCh. 10.CR - Prob. 9CRCh. 10.CR - Prob. 10CRCh. 10.CR - Prob. 11CRCh. 10.CR - Prob. 12CRCh. 10.CR - Prob. 13CRCh. 10.CR - Prob. 14CRCh. 10.CR - Prob. 15CRCh. 10.CR - Prob. 16CRCh. 10.CT - What is the Alabama paradox?Ch. 10.CT - Suppose state C has a population of 1,640,000 and...Ch. 10.CT - The Metropolitan Community College Arts Council...Ch. 10.CT - Prob. 4CTCh. 10.CT - Suppose that Arizona has a population of 5.23...Ch. 10.CT - Prob. 6CTCh. 10.CT - Prob. 7CTCh. 10.CT - Prob. 8CTCh. 10.CT - Prob. 9CTCh. 10.CT - Prob. 10CTCh. 10.CT - Prob. 11CTCh. 10.CT - Prob. 12CTCh. 10.CT - Prob. 13CTCh. 10.CT - Prob. 14CTCh. 10.CT - Three brothersLarry, Moe, and Curlyare dissolving...
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- QUESTION 11 An apportionment method exists that satisfies the quota condition and is free from both the population paradox and the Alabama paradox. True Falsearrow_forwardConsider the following apportionment problem. North: 1,820,000 Northeast: 2,950,000 East: 1,760,000 Southeast: 1,980,000 South: 1,200,000 Southwest: 2,480,000 West: 3,300,000 Northwest: 1,140,000 If there are to be 475 representatives, use the apportionment plan requested below. Hamilton's plan North Northeast East Southeast South Southwest West Northwestarrow_forward3. Six provincial construction project will start two months from now. To maintain orderliness in the construction site , 158 security guard will be assigned . Find the apportionment of the security guardusing the Hamilton and Jefferson plan. Show solution and justify your answer.Location workersManila 3,240Baguio 1,286Cebu 2,085Nueva Ecija 872Naga 1,901Bulacan 2,692arrow_forward
- 5. Name the apportionment method in which we round each group's modified quota to the nearest whole number? 6. Name the paradox. " The addition of a new group changed the apportionments of other groups"arrow_forwardI need help working on this please. I don't understand it.arrow_forwardIn a small Vermont town of 5,000 adults, 2,000 live in private homes while the remaining live in apartment buildings. Of those living in private homes, 240 are upper income, 1,200 are middle income and 560 are lower income. Of those living in apartment buildings, 900 are upper income, 600 are middle income, and 1,500 are lower income. The town council is interested in making a policy change to restructure the property tax base in the town and needs to make an informed decision based on demographic trends and real data. Set up a cross-classification table for type of dwelling unit and income status and find the probability that a person chosen at random: a. Is middle incomeb. Lives in an apartment buildingc. Lives in a private home and is upper incomed. Lives in an apartment building or is lower incomee. Is middle income, if it is known that he lives in an apartment buildingarrow_forward
- Jefferson's method, Webster's method, and Adams's method require using a _______ quota. arrow_forwardA small country consists of three states, whose populations are listed below.A: 6,000 B: 6,000 C: 2,000a. If the legislature has 10 seats, use Hamilton’s method to apportion the seats.b. If the legislature grows to 11 seats, use Hamilton’s method to apportion the seats.c. Which apportionment paradox does this illustrate?arrow_forwardSuppose the Texas Lottery is designing a new scratch-off card! It’s a simplepirate-themed card consisting of one box you must scratch to uncover. It contains either...• a treasure chest, which means you’ve won $1,000,000,• a treasure map, which means you’ve won $1,000,• a parrot, which means you’ve won $5, or• a plank, which means you’ve won a whopping $0.Suppose the designer plans to distribute the tickets so that 1 treasure chest appears in every1,000 tickets, 10 treasure chests appear in every 1,000 tickets, 100 parrots appear in every1,000 tickets, and the rest of the tickets are planks.Using the definition of mathematical fairness given in class, what price should the TexasLottery charge per ticket to make this fair?arrow_forward
- Consider the following apportionment problem. North: 1,930,000 Northeast: 2,950,000 East: 1,650,000 Southeast: 1,980,000 South: 2,000,000 Southwest: 2,480,000 West: 2,500,000 Northwest: 1,140,000 If there are to be 475 representatives, use the apportionment plan requested below. Webster's plan North Northeast East Southeast South Southwest West Northwestarrow_forward1. Using an ordinary deck of playing cards, Zia drew 10 cards one-at-a-time while returning the card each time. If the number of red cards drawn out of 10 cards is at most four, she will give her mother a 5,000-Peso worth of SM gift certificate. Otherwise. she will buy her new kitchenware. Which gift is she likely to give her mother? comarrow_forwardConsider the apportionment problem for College Town. North : 5,500 , South : 4,500 , East : 7,600, West : 7,400 Suppose each council member is to represent approximately 2,100 citizens. Use Jefferson's plan assuming there must be 10 representatives.arrow_forward
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