Explanation Given: Suppose you have, in a second-floor bedroom, a water bed that measures 8ft ×7ft ×0.75ft. One day it leaks and all the water drains into the room below the bedroom. The lower room measures 10ft× 8ft and water has a density of 62.4pounds per cubic foot. Concept Used: Volume of a cuboid = length× breadth× height. Weight of a liquid = density of the liquid× volume of the liquid Calculation: The water bed has the dimensions 8ft ×7ft ×0.75ft. Hence, the volume of water = 8×7×0.75 = 42 cubic feet a.) Assuming that all of the water leaked from the bedroom has accumulated in the lower room, the volume of water in the water bed will be same as the volume of water in the lower room. Suppose that the depth of water in the lower is h feet...

7th Edition

ISBN: 8220106844434

Author: Briggs

Publisher: PEARSON

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Chapter 10.B, Problem 87E

To determine

a.) The depth of water accumulated in the lower room.

b.) Weight of water that was in the water bed.

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Chapter 10.B, Problem 86E

Chapter 10.B, Problem 88E

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a.) The depth of water accumulated in the lower room. b.) Weight of water that was in the water bed.