EBK USING MIS
10th Edition
ISBN: 8220103633635
Author: KROENKE
Publisher: YUZU
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Chapter 10.9, Problem 4SGDQ
Program Plan Intro
Super-advanced AI systems:
Super-advanced
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I need help writing pseudocode for this function. The following pseudocode statement calls a function named half, which returns a value that is half that of the argument. (Assume both the result and number variables are Real.)
Set result = half(number)
Need help converting my pseudocode to python, AND have a flowchart showing everything!The code:Main Module Call InputModuleEnd Main Module
Module InputModule // This module gets input from the user Declare Principal, AnnualRate, Years as Float
Output "Enter the Principal amount (P): " Input Principal
Output "Enter the Annual Interest Rate (in percentage, e.g., 5 for 5%): " Input AnnualRate
Output "Enter the number of Years to repay the loan: " Input Years
Call DisplayPayment(Principal, AnnualRate, Years)End Module
Module DisplayPayment(Principal, AnnualRate, Years) // This module calculates and displays the monthly payment Declare R, N as Float Declare MonthlyPayment as Float Declare PowerFactor as Float // second local variable
// Calculate monthly interest rate R and number of months N Set R = (AnnualRate / 100) / 12 Set N = Years * 12
// Calculate PowerFactor = (1 + R)^N Set PowerFactor = (1 + R) ^ N
// Calculate…
Whats wrong with my pseudocode? Where did I make an error?Code:
Module main()
Declare Real mileage
Call getMileage()
Display “You’ve drive a total of “, mileage, “ miles
End Module
Module getMilage() Display “Enter your mileage: “
Input mileage
End Module
Chapter 10 Solutions
EBK USING MIS
Ch. 10.4 - Prob. 1NFBQCh. 10.4 - Prob. 2NFBQCh. 10.4 - Prob. 3NFBQCh. 10.4 - Prob. 4NFBQCh. 10.4 - Prob. 5NFBQCh. 10.4 - Prob. 6NFBQCh. 10.5 - Prob. 1EGDQCh. 10.5 - Prob. 2EGDQCh. 10.5 - Prob. 3EGDQCh. 10.5 - Prob. 4EGDQ
Ch. 10.5 - Prob. 5EGDQCh. 10.5 - Prob. 6EGDQCh. 10.5 - Prob. 7EGDQCh. 10.9 - Prob. 1SGDQCh. 10.9 - Prob. 2SGDQCh. 10.9 - Prob. 3SGDQCh. 10.9 - Prob. 4SGDQCh. 10.9 - Prob. 10.1ARQCh. 10.9 - Prob. 10.2ARQCh. 10.9 - Prob. 10.3ARQCh. 10.9 - Prob. 10.4ARQCh. 10.9 - Prob. 10.5ARQCh. 10.9 - Prob. 10.6ARQCh. 10.9 - Prob. 10.7ARQCh. 10.9 - Prob. 10.8ARQCh. 10.9 - Prob. 10.9ARQCh. 10 - Prob. 10.1UYKCh. 10 - Prob. 10.2UYKCh. 10 - Prob. 10.3UYKCh. 10 - Prob. 10.4CE10Ch. 10 - Prob. 10.5CE10Ch. 10 - Prob. 10.6CE10Ch. 10 - Prob. 10.7CE10Ch. 10 - Prob. 10.8CS10Ch. 10 - Prob. 10.9CS10Ch. 10 - Prob. 10.1CS10Ch. 10 - Prob. 10.11CS10Ch. 10 - Prob. 10.12CS10Ch. 10 - Prob. 10.13CS10Ch. 10 - Prob. 10.14CS10Ch. 10 - Prob. 10.15MMLCh. 10 - Prob. 10.16MML
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- I need help finishing my python rock paper scissors code, where it asks the user "rock, paper, scissors", the user types either option (repeatedly asks until its one of the three), and for a random option from the code to select also rock paper scissors. The end result would be you winning, code winning, or a tie.My code:import randomOPTIONS = ("ROCK", "PAPER", "SCISSOR") def getInput(): """ Function getInput() will receive and validate user input to be the string ROCK, PAPER, or SCISSOR. Input must be spelled correctly and in all capital letters. Function will return the validated input @return user input as ROCK, PAPER, OR SCISSOR """ #need help here def checkWinner(user, computer): """ Function checkWinner will accept 2 string parameters that must be unique values of ROCK, PAPER, or SCISSOR. Functions should return true if the string in parameter user beats the string in parameter computer in a game of rock…arrow_forwardI need help understanding how could I got the IP Address for the 1st Host on this Subnet, the IP Address for the Last Host on this Subnet & the Broadcast Address for this Subnet My Explanation:8 bits --> 17 & 0 128 64 32 16 | 8 4 2 1 0 0 0 1 0 0 0 1 -->17+ 0 0 0 0 0 0 0 0 --> 0 0 0 0 0 0 0 0 0 --> 0 (The Major (Base) Network Address): 142.20.33.0 To find the broadcast address, we can set all the bits in the host portion of the address to 1, which gives us 142.20.33.255. Based on the subnet mask 255.255.255.0, no bits were borrowed from the host portion, meaning 8 bits remain in the host portion. Using the formula 2^h – 2 (where h represents the number of host bits), we get 2^8 - 2 = 254 hosts. 8 bits --> 17 & 252 128 64 32 16 | 8 4 2 1 0 0 0 1 0 0 0 1 --> 17+ 1 1 1 1 1 1 0 0 --> 252 0 0 0 1…arrow_forwardWhich of the following opens when you click the launcher in the Size group on the Ribbon? Question 19Select one: a. Size dialog box b. Layout dialog box c. Width and Height dialog box d. Format dialog boxarrow_forward
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