Fundamentals of Engineering Thermodynamics
8th Edition
ISBN: 9781118832301
Author: SHAPIRO
Publisher: JOHN WILEY+SONS,INC.-CONSIGNMENT
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Chapter 10.7, Problem 11E
To determine
The reason of being discharging of only warm air from car’s air-conditioning.
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Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to find
Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findthe internal force andkeep either side of the
Procedure:
1- Cartesian system, 2D3D,
type of support
2- Free body diagram
3 - Find the support reactions
4- If you find a negative
number then flip the force
5- Find the internal force
3D
∑Fx=0
∑Fy=0
∑Fz=0
∑Mx=0
∑My=0
ΣMz=0
2D
ΣFx=0
ΣFy=0
ΣMz=0
5- Use method of section
and cut the element
where you want to find
the internal force and
keep either side of the
Chapter 10 Solutions
Fundamentals of Engineering Thermodynamics
Ch. 10.7 - Prob. 1ECh. 10.7 - Prob. 2ECh. 10.7 - Prob. 3ECh. 10.7 - Prob. 4ECh. 10.7 - Prob. 5ECh. 10.7 - Prob. 6ECh. 10.7 - Prob. 7ECh. 10.7 - Prob. 8ECh. 10.7 - Prob. 9ECh. 10.7 - Prob. 10E
Ch. 10.7 - Prob. 11ECh. 10.7 - Prob. 12ECh. 10.7 - Prob. 13ECh. 10.7 - Prob. 14ECh. 10.7 - Prob. 1CUCh. 10.7 - Prob. 11CUCh. 10.7 - Prob. 12CUCh. 10.7 - 13. Why is wet compression avoided within...Ch. 10.7 - Prob. 14CUCh. 10.7 - Prob. 15CUCh. 10.7 - Prob. 16CUCh. 10.7 - Prob. 17CUCh. 10.7 - Prob. 18CUCh. 10.7 - Prob. 19CUCh. 10.7 - Prob. 20CUCh. 10.7 - Prob. 21CUCh. 10.7 - Prob. 22CUCh. 10.7 - Prob. 23CUCh. 10.7 - Prob. 24CUCh. 10.7 - Prob. 25CUCh. 10.7 - Prob. 26CUCh. 10.7 - Prob. 27CUCh. 10.7 - Prob. 28CUCh. 10.7 - Prob. 29CUCh. 10.7 - Prob. 30CUCh. 10.7 - Prob. 31CUCh. 10.7 - Prob. 32CUCh. 10.7 - 33. The desuperheating section of the refrigerant...Ch. 10.7 - 34. A throttling process is usually modeled as an...Ch. 10.7 - Prob. 35CUCh. 10.7 - Prob. 36CUCh. 10.7 - Prob. 37CUCh. 10.7 - Prob. 38CUCh. 10.7 - Prob. 39CUCh. 10.7 - Prob. 40CUCh. 10.7 - Prob. 41CUCh. 10.7 - Prob. 42CUCh. 10.7 - Prob. 43CUCh. 10.7 - Prob. 44CUCh. 10.7 - Prob. 45CUCh. 10.7 - Prob. 46CUCh. 10.7 - Prob. 47CUCh. 10.7 - 48. In a cascade vapor-compression refrigeration...Ch. 10.7 - Prob. 49CUCh. 10.7 - Prob. 50CUCh. 10.7 - Prob. 51CUCh. 10.7 - Prob. 1PCh. 10.7 - Prob. 2PCh. 10.7 - Prob. 3PCh. 10.7 - Prob. 4PCh. 10.7 - 10.5 For the cycle in Problem 10.4, determine
(a)...Ch. 10.7 - Prob. 6PCh. 10.7 - Prob. 7PCh. 10.7 - 10.8 Refrigerant 134a is the working fluid in an...Ch. 10.7 - Prob. 9PCh. 10.7 - Prob. 10PCh. 10.7 - Prob. 11PCh. 10.7 - Prob. 13PCh. 10.7 - 10.15 A vapor-compression refrigeration cycle...Ch. 10.7 - Prob. 16PCh. 10.7 - Prob. 17PCh. 10.7 - Prob. 18PCh. 10.7 - 10.19 If the minimum and maximum allowed...Ch. 10.7 - Prob. 21PCh. 10.7 - Prob. 22PCh. 10.7 - Prob. 23PCh. 10.7 - 10.24 The window-mounted air conditioner shown in...Ch. 10.7 - 10.25 A vapor-compression refrigeration system for...Ch. 10.7 - Prob. 26PCh. 10.7 - Prob. 28PCh. 10.7 - Prob. 29PCh. 10.7 - Prob. 31PCh. 10.7 - 10.32 Figure P10.32 shows the schematic diagram of...Ch. 10.7 - Prob. 33PCh. 10.7 - Vapor-Compression Heat Pump Systems
10.34 Figure...Ch. 10.7 - Prob. 35PCh. 10.7 - Prob. 36PCh. 10.7 - 10.37 An office building requires a heat transfer...Ch. 10.7 - Prob. 38PCh. 10.7 - Prob. 39PCh. 10.7 - Prob. 40PCh. 10.7 - 10.41 Refrigerant 134a enters the compressor of a...Ch. 10.7 - Prob. 42PCh. 10.7 - Prob. 43PCh. 10.7 - Prob. 44PCh. 10.7 - Prob. 46PCh. 10.7 - Prob. 47PCh. 10.7 - 10.48 The table below provides steady-state...Ch. 10.7 - Prob. 50PCh. 10.7 - Prob. 51PCh. 10.7 - Prob. 53PCh. 10.7 - Prob. 54PCh. 10.7 - Prob. 55PCh. 10.7 - Prob. 56P
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- Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findthe internal force andkeep either side of thearrow_forwardProcedure: 1- Cartesian system, 2(D)/(3)D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D \sum Fx=0 \sum Fy=0 \sum Fz=0 \sum Mx=0 \sum My=0 \Sigma Mz=0 2D \Sigma Fx=0 \Sigma Fy=0 \Sigma Mz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of the sectionarrow_forwardProcedure: 1- Cartesian system, 2(D)/(3)D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D \sum Fx=0 \sum Fy=0 \sum Fz=0 \sum Mx=0 \sum My=0 \Sigma Mz=0 2D \Sigma Fx=0 \Sigma Fy=0 \Sigma Mz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of the sectionarrow_forward
- For each system below with transfer function G(s), plot the pole(s) on the s-plane. and indicate whether the system is: (a) "stable" (i.e., a bounded input will always result in a bounded output), (b) "marginally stable," or (c) "unstable" Sketch a rough graph of the time response to a step input. 8 a) G(s) = 5-5 8 b) G(s) = c) G(s) = = s+5 3s + 8 s² - 2s +2 3s +8 d) G(s): = s²+2s+2 3s+8 e) G(s): = s² +9 f) G(s): 8 00 == Sarrow_forwardPlease answer the following question. Include all work and plase explain. Graphs are provided below. "Consider the Mg (Magnesium) - Ni (Nickel) phase diagram shown below. This phase diagram contains two eutectic reactions and two intermediate phases (Mg2Ni and MgNi2). At a temperature of 505oC, determine what the composition of an alloy would need to be to contain a mass fraction of 0.20 Mg and 0.80 Mg2Ni."arrow_forwardThe triangular plate, having a 90∘∘ angle at AA, supports the load PP = 370 lblb as shown in (Figure 1).arrow_forward
- Design a 4-bar linkage to carry the body in Figure 1 through the two positions P1 and P2 at the angles shown in the figure. Use analytical synthesis with the free choice values z = 1.075, q= 210°, ß2 = −27° for left side and s = 1.24, y= 74°, ½ = − 40° for right side. φ 1.236 P2 147.5° 210° 2.138 P1 Figure 1 Xarrow_forwardDesign a 4-bar linkage to carry the body in Figure 1 through the two positions P1 and P2 at the angles shown in the figure. Use analytical synthesis with the free choice values z = 1.075, q= 210°, B₂ = −27° for left side and s = 1.24, y= 74°, ½ = − 40° for right side. 1.236 P2 147.5° 210° P1 Figure 1 2.138 Xarrow_forwardcan you explain how in a coordinate frame transformation: v = {v_n}^T {n-hat} and then it was found that {n-hat} = [C]^T {b-hat} so v_n = {v_n}^T [C]^T {b-hat}, how does that equation go from that to this --> v_n = [C]^T v_barrow_forward
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