Concept explainers
(a)
To find: The probability of selecting 3 are drug offenders if a list of potential parolees consists of eight drug offenders, five violent offenders and two convicted of property crimes.
(b)
To find: The probability of selecting 3 offenders in which two of three are property offenders if a list of potential parolees consists of eight drug offenders, five violent offenders and two convicted of property crimes.
(c)
To find: The probability of selecting 3 offenders are violent offenders if a list of potential parolees consists of eight drug offenders, five violent offenders and two convicted of property crimes.
(d)
To find: The probability of selecting 3 offenders are one of each type if a list of potential parolees consists of eight drug offenders, five violent offenders and two convicted of property crimes.
(e)
To find: The probability of selecting 3 offenders in which two are drug offenders and one violent offender if a list of potential parolees consists of eight drug offenders, five violent offenders and two convicted of property crimes.

Want to see the full answer?
Check out a sample textbook solution
Chapter 10 Solutions
MATH IN OUR WORLD (LL) W/18 WEEKS ALEKS
- The difference in length of a spring on a pogo stick from its non-compressed length when a teenager is jumping on it after θ seconds can be described by the function f(θ) = 2sinθ + √2.Part A: Determine all values where the pogo stick's spring will be equal to its non-compressed length. Part B: If the angle was doubled, that is θ became 2θ, what are the solutions in the interval [0, 2π)? How do these compare to the original function?Part C: A toddler is jumping on another pogo stick whose length of its spring can be represented by the function g(θ) = 1 cos^2θ + √2. At what times are the springs from the original pogo stick and the toddler's pogo stick lengths equal?arrow_forward3. [15] The joint PDF of RVS X and Y is given by fx.x(x,y) = { x) = { c(x + { c(x+y³), 0, 0≤x≤ 1,0≤ y ≤1 otherwise where c is a constant. (a) Find the value of c. (b) Find P(0 ≤ X ≤,arrow_forwardThe analysis of results from a leaf transmutation experiment (turning a leaf into a petal) is summarized by the type of transformation completed: A naturalist randomly selects three leaves from this set without replacement. Total Textural Transformation Yes No Total Yes 243 26 269 Total Color Transformation No 13 18 31 Total 256 44 300 Let X represent the number of leaves that have undergone both transformations. The appropriate probability distribution of X is a distribution. The parameters are population size N = size n = number of events K = and sample The probability that at least one leaf has undergone both transformations is probability to four decimal places.) X has a N = K= n = The requested probability is distribution. (Round thearrow_forwardThe life time of a certain battery is modeled with the Weibull distribution with shape parameter ẞ=2 and scale parameter 8-10 hours. Determine the mean time until failure of batteries. (Round the answer to one decimal place.) hoursarrow_forwardNeed help pleasearrow_forwardConsider the probability distribution below. 0 1 3 f(x) 0.3 0.3 0.4 E(X)=1.5. The variance of XV (X) equals 1.65 ○ 1.28 1.56 2.33arrow_forward7. [10] Suppose that Xi, i = 1,..., 5, are independent normal random variables, where X1, X2 and X3 have the same distribution N(1, 2) and X4 and X5 have the same distribution N(-1, 1). Let (a) Find V(X5 - X3). 1 = √(x1 + x2) — — (Xx3 + x4 + X5). (b) Find the distribution of Y. (c) Find Cov(X2 - X1, Y). -arrow_forward1. [10] Suppose that X ~N(-2, 4). Let Y = 3X-1. (a) Find the distribution of Y. Show your work. (b) Find P(-8< Y < 15) by using the CDF, (2), of the standard normal distribu- tion. (c) Find the 0.05th right-tail percentage point (i.e., the 0.95th quantile) of the distri- bution of Y.arrow_forward6. [10] Let X, Y and Z be random variables. Suppose that E(X) = E(Y) = 1, E(Z) = 2, V(X) = 1, V(Y) = V(Z) = 4, Cov(X,Y) = -1, Cov(X, Z) = 0.5, and Cov(Y, Z) = -2. 2 (a) Find V(XY+2Z). (b) Find Cov(-x+2Y+Z, -Y-2Z).arrow_forwardConsider the probability distribution below. 10 20 30 40 f(x) 0.3 0.4 0.2 0.1 The expected value of X equals 100 ○ 25 ○ 18 ○ 21arrow_forwardThe analysis of results from a leaf transmutation experiment (turning a leaf into a petal) is summarized by the type of transformation completed: A naturalist randomly selects three leaves from this set without replacement. Total Textural Transformation Yes No Total Yes 243 26 269 Total Color Transformation No 13 18 31 Total 256 44 300 Let X represent the number of leaves that have undergone both transformations. The appropriate probability distribution of X is a distribution. The parameters are population size N = size n = number of events K = and sample The probability that at least one leaf has undergone both transformations is probability to four decimal places.) X has a N = K= n = The requested probability is distribution. (Round thearrow_forwardThe thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters. Determine the mean of flange thickness. millimeters (Two decimal places.)arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
- Holt Mcdougal Larson Pre-algebra: Student Edition...AlgebraISBN:9780547587776Author:HOLT MCDOUGALPublisher:HOLT MCDOUGALCollege AlgebraAlgebraISBN:9781305115545Author:James Stewart, Lothar Redlin, Saleem WatsonPublisher:Cengage Learning


