To find: The vertices, foci, and the asymptotes of the hyperbola x264−y236=1 . Also, sketch the graph.
The vertices of the hyperbola are (±8,0) , foci are (±10,0) and the asymptotes are y=±34x
Given information: The vertices equation of the hyperbola is x264−y236=1
Formula used: The equation of the hyperbola,
x2a2−y2b2=1 , here transverse axis is vertical.
Vertices of the hyperbola are (±a,0) and the foci are (±c,0) .
Here, c2=a2+b2
Slope of asymptotes are m=±ba , then asymptotes are y=±bax
Calculation:
Consider the equation of the hyperbola as,
x264−y236=1 ...... (1)
Compare equation (1) with x2a2−y2b2=1 , then
a2=64 implies that a=±8
And b2=36 implies that b=±6
Also, c2=a2+b2 implies that,
c2=64+36=100c=±10
Hence, the vertices of the hyperbola are (±a,0)=(±8,0) , foci are (±c,0)=(±10,0)
Also, the asymptotes are
y=±bax=±68x=±34x
The graph of the hyperbola can be drawn as,
Chapter 10 Solutions
High School Math 2015 Common Core Algebra 2 Student Edition Grades 10/11
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