Explanation The given function is E = { ( 2 , 3.5 ) , ( − 1 , 8 ) , ( 10 , 3.5 ) ( 0 , − 8 ) } . For a function to have one-to-one, for every value of x there is only one value of y . Which makes every value of the range and domain, unique. Thus, a one-to-one function is a function in which no ordered pairs are having the same second coordinate. In the given function, the second coordinate is same for ( 2 , 3

MYLAB MATH FOR INTERMEDIATE ALGEBRA 18WK

8th Edition

ISBN: 9780136418306

Author: Tobey

Publisher: PEARSON

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Chapter 10.4, Problem 11E

To determine

Whether the following function, E={(2,3.5),(−1,8),(10,3.5)(0,−8)} is one-to-one.

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Chapter 10.4, Problem 10E

Chapter 10.4, Problem 12E

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Chapter 10 Solutions

MYLAB MATH FOR INTERMEDIATE ALGEBRA 18WK

Ch. 10.1 - For the function f ( x ) = 3 x − 5 , find the...Ch. 10.1 - For the function , find the following. 2. Ch. 10.1 - Prob. 3E Ch. 10.1 - Prob. 4E Ch. 10.1 - Prob. 5E Ch. 10.1 - Prob. 6E Ch. 10.1 - For the function , find the following. 7. Ch. 10.1 - Prob. 8E Ch. 10.1 - Prob. 9E Ch. 10.1 - Prob. 10E

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Concept Check Explain how you can use a...Ch. 10.3 - Prob. 1E Ch. 10.3 - Prob. 2E Ch. 10.3 - Prob. 3E Ch. 10.3 - Prob. 4E Ch. 10.3 - Prob. 5E Ch. 10.3 - Prob. 6E Ch. 10.3 - Prob. 7E Ch. 10.3 - Prob. 8E Ch. 10.3 - Prob. 9E Ch. 10.3 - For the following functions, find (a) ( f + g ) (...Ch. 10.3 - Prob. 11E Ch. 10.3 - Prob. 12E Ch. 10.3 - Prob. 13E Ch. 10.3 - Prob. 14E Ch. 10.3 - For the following functions, find (a) and (b)...Ch. 10.3 - Prob. 16E Ch. 10.3 - Prob. 17E Ch. 10.3 - Prob. 18E Ch. 10.3 - Prob. 19E Ch. 10.3 - Prob. 20E Ch. 10.3 - Prob. 21E Ch. 10.3 - Prob. 22E Ch. 10.3 - Prob. 23E Ch. 10.3 - Let , and . Find the following: 24. 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Whether the following function, E = { ( 2 , 3.5 ) , ( − 1 , 8 ) , ( 10 , 3.5 ) ( 0 , − 8 ) } is one-to-one.

Solution Summary: The author explains that a one-to-one function is one in which no ordered pairs are having the same second coordinate.

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Whether the following function, E={(2,3.5),(−1,8),(10,3.5)(0,−8)} is one-to-one.

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Chapter 10 Solutions