COMPUTER SYSTEMS&MOD MSGT/ET SA AC PKG
COMPUTER SYSTEMS&MOD MSGT/ET SA AC PKG
3rd Edition
ISBN: 9780134671123
Author: Bryant
Publisher: PEARSON
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Chapter 10.3, Problem 10.1PP
Program Plan Intro

Opening and Closing files:

Using “Open” function, a process can open an existing file or generates a new file.

  • This function is used to converts a filename to a file descriptor and returns the result as a descriptor number.
  • The descriptor returned is always the lowest descriptor that is not presently open in the process.
  • Each process in the LINUX begins life with three open files.
    • Descriptor 0 – standard input.
    • Descriptor 1 – standard output.
    • Descriptor 2 – standard error.
  • The “open” function consists of three arguments. That is “Open(filename, flags, mode)”.
    • The argument “filename” defines the name of the given file.
    • The argument “flags” represents how the process plans to access the file. Some flags names are as follows.
      • O_RDONLY – it means reading only.
      • O_WRONLY – it means writing only.
      • O_RDWR – it means reading and writing.
    • The “mode” argument identifies the access permission bits of new files.

Example:

The example for open an existing file for reading is shown below:

sample1 = Open("foo1.txt", O_RDONLY, 0);

From the above “open” function,

  • The filename is “foo1.txt”.
  • Flag name is “O_RDONLY”.
  • Mode is “0”.

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Specifications: Part-1Part-1: DescriptionIn this part of the lab you will build a single operation ALU. This ALU will implement a bitwise left rotation. Forthis lab assignment you are not allowed to use Digital's Arithmetic components.IF YOU ARE FOUND USING THEM, YOU WILL RECEIVE A ZERO FOR LAB2!The ALU you will be implementing consists of two 4-bit inputs (named inA and inB) and one 4-bit output (named out). Your ALU must rotate the bits in inA by the amount given by inB (i.e. 0-15).Part-1: User InterfaceYou are provided an interface file lab2_part1.dig; start Part-1 from this file.NOTE: You are not permitted to edit the content inside the dotted lines rectangle.Part-1: ExampleIn the figure above, the input values that we have selected to test are inA = {inA_3, inA_2, inA_1, inA_0} = {0, 1, 0,0} and inB = {inB_3, inB_2, inB_1, inB_0} = {0, 0, 1, 0}. Therefore, we must rotate the bus 0100 bitwise left by00102, or 2 in base 10, to get {0, 0, 0, 1}. Please note that a rotation left is…
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