Explanation Given data: x = 2 t (1) y = t + 1 (2) 0 ≤ t ≤ 1 . Calculation: Find d x d t Differentiate with respect to t of equation (1) as follows. d x d t = d d t ( 2 t ) = 2 d d t ( t ) = 2 Find d y d t Differentiate with respect to t of equation (2) as follows. d y d t = d d t ( t + 1 ) = d d t t + d d t 1 = 1 + 0 = 1 Find ( d x d t ) 2 + ( d y d t ) 2 . ( d x d t ) 2 + ( d y d t ) 2 = ( 2 ) 2 + ( 1 ) 2 = 4 + 1 = 5 Consider the expression to obtain an area cone frustum. A = ∫ 0 1 2 π y d s = ∫ 0 1 2 π y 5 d t Substitute t + 1 for y as follows

4th Edition

ISBN: 9780135910993

Author: Hass

Publisher: PEARSON

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Chapter 10.2, Problem 35E

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Find the surface area of frustum.

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Chapter 10.2, Problem 34E

Chapter 10.2, Problem 36E

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