Explanation Given: The given equation is- ( cos y + 1 ) d y d t = 2 t such that y ( 2 ) = 0 y ( 6 ) = π 3 Calculation: Solving the given equation- ( cos y + 1 ) d y d t = 2 t ( cos y + 1 ) d y = 2 t × d t Integrating both sides- ∫ ( cos y + 1 ) d y = ∫ 2 t × d t sin y + y = t 2 + C ........ ( 1 ) Where C is integrating constant . Applying the given condition y ( 2 ) = 0 in equation(1) sin 0 + 0 = 2 2 + C C = − 4 Putting the value of C , in equation(1) sin y + y = t 2 − 4 Now differentiate the above equation- d d t ( sin y + y ) = d d t ( t 2 − 4 ) d d t ( sin y

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ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

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Chapter 10.1, Problem 48E

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The equation of tangent line to the graph of y(t) at (6,π3).

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Chapter 10.1, Problem 47E

Chapter 10.1, Problem 49E

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Chapter 10 Solutions

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The equation of tangent line to the graph of y ( t ) at ( 6, π 3 ) .

Solution Summary: The author explains the equation of tangent line to the graph of y=8x+pi 3-48.

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