Explanation Consider the differential equations x ′ = y and y ′ = y ( 1 − 3 x 2 − 2 y 2 ) − x . The critical points are evaluated by setting the RHS of the differential equations equal to zero. Here, y = 0 and y ( 1 − 3 x 2 − 2 y 2 ) − x = 0 . Substitute y = 0 in the second equation

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Chapter 10.1, Problem 29E

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The possibility of the periodic solution with a numerical solver.

Solution Summary: The author illustrates the possibility of periodic solution with a numerical solver. The critical points are evaluated by setting the RHS of the differential equations equal to zero.

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The possibility of the periodic solution with a numerical solver.

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Chapter 10 Solutions