The Lewis structure of OF 2 is to be drawn. Concept introduction: To draw the Lewis structure of the molecule there are following steps: Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom. Step 2: Calculate the total number of valence electrons. Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond. Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons.

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Answer 1

Question

Chapter 10.1, Problem 10.1BFP

(a)

Interpretation Introduction

Interpretation:

The Lewis structure of OF2 is to be drawn.

Concept introduction:

To draw the Lewis structure of the molecule there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons.

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons.

(b)

Interpretation Introduction

Interpretation:

The Lewis structure of the CH2Br2 is to be drawn

Concept introduction:

To draw the Lewis structure of the molecule there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons

(c)

Interpretation Introduction

Interpretation:

The Lewis structure of the IBr2+ is to be drawn

Concept introduction:

To draw the Lewis structure of the molecule with multiple bonds there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons

Step 5: Convert the lone pair into bond pair.

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Q1: Draw the most stable and the least stable Newman projections about the C2-C3 bond for each of the following isomers (A-C). Are the barriers to rotation identical for enantiomers A and B? How about the diastereomers (A versus C or B versus C)? enantiomers H Br H Br (S) CH3 H3C (S) (R) CH3 H3C H Br A Br H C H Br H3C (R) B (R)CH3 H Br H Br H3C (R) (S) CH3 Br H D identical

Label the spectrum

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Answer 2

Question

Chapter 10.1, Problem 10.1BFP

(a)

Interpretation Introduction

Interpretation:

The Lewis structure of OF2 is to be drawn.

Concept introduction:

To draw the Lewis structure of the molecule there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons.

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons.

(b)

Interpretation Introduction

Interpretation:

The Lewis structure of the CH2Br2 is to be drawn

Concept introduction:

To draw the Lewis structure of the molecule there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons

(c)

Interpretation Introduction

Interpretation:

The Lewis structure of the IBr2+ is to be drawn

Concept introduction:

To draw the Lewis structure of the molecule with multiple bonds there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons

Step 5: Convert the lone pair into bond pair.

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Answer 3

Question

Chapter 10.1, Problem 10.1BFP

(a)

Interpretation Introduction

Interpretation:

The Lewis structure of OF2 is to be drawn.

Concept introduction:

To draw the Lewis structure of the molecule there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons.

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons.

(b)

Interpretation Introduction

Interpretation:

The Lewis structure of the CH2Br2 is to be drawn

Concept introduction:

To draw the Lewis structure of the molecule there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons

(c)

Interpretation Introduction

Interpretation:

The Lewis structure of the IBr2+ is to be drawn

Concept introduction:

To draw the Lewis structure of the molecule with multiple bonds there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons

Step 5: Convert the lone pair into bond pair.

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Answer 4

Question

Chapter 10.1, Problem 10.1BFP

(a)

Interpretation Introduction

Interpretation:

The Lewis structure of OF2 is to be drawn.

Concept introduction:

To draw the Lewis structure of the molecule there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons.

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons.

(b)

Interpretation Introduction

Interpretation:

The Lewis structure of the CH2Br2 is to be drawn

Concept introduction:

To draw the Lewis structure of the molecule there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons

(c)

Interpretation Introduction

Interpretation:

The Lewis structure of the IBr2+ is to be drawn

Concept introduction:

To draw the Lewis structure of the molecule with multiple bonds there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons

Step 5: Convert the lone pair into bond pair.

Expert Solution & Answer

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Answer 5

Chapter 10.1, Problem 10.1BFP

(a)

Interpretation Introduction

Interpretation:

The Lewis structure of OF2 is to be drawn.

Concept introduction:

To draw the Lewis structure of the molecule there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons.

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons.

(b)

Interpretation Introduction

Interpretation:

The Lewis structure of the CH2Br2 is to be drawn

Concept introduction:

To draw the Lewis structure of the molecule there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons

(c)

Interpretation Introduction

Interpretation:

The Lewis structure of the IBr2+ is to be drawn

Concept introduction:

To draw the Lewis structure of the molecule with multiple bonds there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons

Step 5: Convert the lone pair into bond pair.

Answer 6

Chapter 10.1, Problem 10.1BFP

(a)

Interpretation Introduction

Interpretation:

The Lewis structure of OF2 is to be drawn.

Concept introduction:

To draw the Lewis structure of the molecule there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons.

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons.

Answer 7

Chapter 10.1, Problem 10.1BFP

(a)

Interpretation Introduction

Interpretation:

The Lewis structure of OF2 is to be drawn.

Concept introduction:

To draw the Lewis structure of the molecule there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons.

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The Lewis structure of the CH2Br2 is to be drawn

Concept introduction:

To draw the Lewis structure of the molecule there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons

Answer 9

(b)

Interpretation Introduction

Interpretation:

The Lewis structure of the CH2Br2 is to be drawn

Concept introduction:

To draw the Lewis structure of the molecule there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons

Answer 10

(c)

Interpretation Introduction

Interpretation:

The Lewis structure of the IBr2+ is to be drawn

Concept introduction:

To draw the Lewis structure of the molecule with multiple bonds there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons

Step 5: Convert the lone pair into bond pair.

Answer 11

(c)

Interpretation Introduction

Interpretation:

The Lewis structure of the IBr2+ is to be drawn

Concept introduction:

To draw the Lewis structure of the molecule with multiple bonds there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons

Step 5: Convert the lone pair into bond pair.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 10.1 - Write a Lewis structure for H2S; ; SOCl2. Ch. 10.1 - Prob. 10.1BFP Ch. 10.1 - Prob. 10.2AFP Ch. 10.1 - Prob. 10.2BFP Ch. 10.1 - Prob. 10.3AFP Ch. 10.1 - Prob. 10.3BFP Ch. 10.1 - Prob. 10.4AFP Ch. 10.1 - Prob. 10.4BFP Ch. 10.1 - Prob. 10.5AFP Ch. 10.1 - Prob. 10.5BFP

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