Explanation 1) Concept: We use the concept of Newton’s second law. We find acceleration of the system by applying Newton’s second law for both masses and pulley. We can write three equations because we have three unknowns. Solving these equations simultaneously, we get acceleration. Once acceleration is found, we can find tensions. 2) Formulae: i) F = m a ii) τ = I α = F × r 3) Given: i) Mass of block 1 is m 1 = 400 g ii) Mass of block 2 is m 2 = 600 g iii) Mass of the disk is M = 500 g iv) Radius of disk is R = 12.0 c m 4) Calculations: a) The magnitude of the acceleration of the blocks: First we write the equation for net force on each block and pulley: m 1 a = T 1 - m 1 g … … … … … … … … … … … … … … … … … … … … … … … … … … … … … … … … ( 1 ) m 2 a = m 2 g - T 2 … … … … … … … … … … … … … … … … … … … … … … … … … … … … … … … . . . ( 2 ) T 2 R - T 1 R = I α We know moment of inertia of disk is I = 1 2 M R 2 also α = a R T 2 R - T 1 R = 1 2 M R 2 a R R will get cancelled out from both sides, so we get T 2 - T 1 = 1 2 M a We can write this equation as T 2 = 1 2 M a +

Fundamentals of Physics Extended 10E WileyPlus 5 Student Package

1st Edition

ISBN: 9781118441497

Author: Halliday

Publisher: John Wiley & Sons Inc (US)

See similar textbooks

Concept explainers

Center of Gravity of a system

The centre of gravity is a property that is based on the geometry of a rigid body or any particle. It is described as an equilibrium point or a hypothetical location where the total weight of the body is concentrated.

Question

Chapter 10, Problem 83P

To determine

To find:

a) The magnitude of the acceleration of the blocks.

b) The tension in the cord at left.

c) The tension in the cord at right.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 10, Problem 82P

Chapter 10, Problem 84P

Students have asked these similar questions

Two resistors of resistances R1 and R2, with R2>R1, are connected to a voltage source with voltage V0. When the resistors are connected in series, the current is Is. When the resistors are connected in parallel, the current Ip from the source is equal to 10Is. Let r be the ratio R1/R2. Find r. I know you have to find the equations for V for both situations and relate them, I'm just struggling to do so. Please explain all steps, thank you.

Bheem and Ram, jump off either side of a bridge while holding opposite ends of a rope and swing back and forth under the bridge to save a child while avoiding a fire. Looking at the swing of just Bheem, we can approximate him as a simple pendulum with a period of motion of 5.59 s. How long is the pendulum ? When Bheem swings, he goes a full distance, from side to side, of 10.2 m. What is his maximum velocity? What is his maximum acceleration?

The position of a 0.300 kg object attached to a spring is described by x=0.271 m ⋅ cos(0.512π⋅rad/s ⋅t) (Assume t is in seconds.) Find the amplitude of the motion. Find the spring constant. Find the position of the object at t = 0.324 s. Find the object's velocity at t = 0.324 s.

Chapter 10 Solutions

Fundamentals of Physics Extended 10E WileyPlus 5 Student Package

Ch. 10 - Figure 10-20 is a graph of the angular velocity...Ch. 10 - Figure 10-21 shows plots of angular position ...Ch. 10 - A force is applied to the rim of a disk that can...Ch. 10 - Figure 10-22b is a graph of the angular position...Ch. 10 - In Fig. 10-23, two forces F1 and F2 act on a disk...Ch. 10 - In the overhead view of Fig. 10-24, five forces of...Ch. 10 - Figure 10-25a is an overhead view of a horizontal...Ch. 10 - Figure l0-25b shows an overhead view of a...Ch. 10 - Figure 10-26 shows a uniform metal plate that had...Ch. 10 - Figure 10-27 shows three flat disks of the same...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

a) The magnitude of the acceleration of the blocks. b) The tension in the cord at left. c) The tension in the cord at right.

Concept explainers

To find: a) The magnitude of the acceleration of the blocks. b) The tension in the cord at left. c) The tension in the cord at right.

Want to see the full answer?

Chapter 10 Solutions

To find:

a) The magnitude of the acceleration of the blocks.

b) The tension in the cord at left.

c) The tension in the cord at right.