Explanation 1) Concept: We use the concept of Newton’s second law. We find acceleration of the system by applying Newton’s second law for both masses and pulley. We can write three equations because we have three unknowns. Solving these equations simultaneously, we get acceleration. Once acceleration is found, we can find tensions. 2) Formulae: i) F = m a ii) τ = I α = F × r 3) Given: i) Mass of block 1 is m 1 = 400 g ii) Mass of block 2 is m 2 = 600 g iii) Mass of the disk is M = 500 g iv) Radius of disk is R = 12.0 c m 4) Calculations: a) The magnitude of the acceleration of the blocks: First we write the equation for net force on each block and pulley: m 1 a = T 1 - m 1 g … … … … … … … … … … … … … … … … … … … … … … … … … … … … … … … … ( 1 ) m 2 a = m 2 g - T 2 … … … … … … … … … … … … … … … … … … … … … … … … … … … … … … … . . . ( 2 ) T 2 R - T 1 R = I α We know moment of inertia of disk is I = 1 2 M R 2 also α = a R T 2 R - T 1 R = 1 2 M R 2 a R R will get cancelled out from both sides, so we get T 2 - T 1 = 1 2 M a We can write this equation as T 2 = 1 2 M a +

Fundamentals of Physics Extended 10E WileyPlus 5 Student Package

1st Edition

ISBN: 9781118441497

Author: Halliday

Publisher: John Wiley & Sons Inc (US)

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Chapter 10, Problem 83P

To determine

To find:

a) The magnitude of the acceleration of the blocks.

b) The tension in the cord at left.

c) The tension in the cord at right.

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Chapter 10, Problem 82P

Chapter 10, Problem 84P

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During a concentric loading of the quadriceps muscle in the upper leg, an athlete extends his lower leg from a vertical position (see figure (a)) to a fully extended horizontal position (see figure (b)) at a constant angular speed of 45.0° per second. Two of the four quadriceps muscles, the vastis intermedius and the rectus femoris, terminate at the patellar tendon which is attached to the top of the tibia in the lower leg. The distance from the point of attachment of the patellar tendon to the rotation axis of the tibia relative to the femur is 4.10 cm in this athlete. a b (a) The two quadriceps muscles can exert a maximum force of 225 N through the patellar tendon. This force is applied at an angle of 25.0° to the section of the tibia between the attachment point and the rotation axis. What is the torque (in N⚫ m) exerted by the muscle on the lower leg during this motion? (Enter the magnitude.) N⚫ m (b) What is the power (in W) generated by the athlete during the motion? W (c)…

Chapter 10 Solutions

Fundamentals of Physics Extended 10E WileyPlus 5 Student Package

Ch. 10 - Figure 10-20 is a graph of the angular velocity...Ch. 10 - Figure 10-21 shows plots of angular position ...Ch. 10 - A force is applied to the rim of a disk that can...Ch. 10 - Figure 10-22b is a graph of the angular position...Ch. 10 - In Fig. 10-23, two forces F1 and F2 act on a disk...Ch. 10 - In the overhead view of Fig. 10-24, five forces of...Ch. 10 - Figure 10-25a is an overhead view of a horizontal...Ch. 10 - Figure l0-25b shows an overhead view of a...Ch. 10 - Figure 10-26 shows a uniform metal plate that had...Ch. 10 - Figure 10-27 shows three flat disks of the same...

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a) The magnitude of the acceleration of the blocks. b) The tension in the cord at left. c) The tension in the cord at right.

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To find: a) The magnitude of the acceleration of the blocks. b) The tension in the cord at left. c) The tension in the cord at right.

Want to see the full answer?

Chapter 10 Solutions

To find:

a) The magnitude of the acceleration of the blocks.

b) The tension in the cord at left.

c) The tension in the cord at right.