PEARSON ETEXT ENGINEERING MECH & STATS
15th Edition
ISBN: 9780137514724
Author: HIBBELER
Publisher: PEARSON
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Q.2) Calculate the moment of inertia (Ixc and Iyc)
0.165 m
about the given axis for the composite area shown
in figure.
0.8 m
C
0.1m
0.265 m
1m
0.5m
None
Determine the moment of inertia about the x-axis of the rectangular area without and with the central rectangular hole.
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- A channel and a plate are welded together as shown to form a section that is symmetrical with respect to the y axis. Determine the moments of inertia of the combined section with respect to its centroidal x and yaxes if a = 14 in. 0.5 in. y C a CS×115 The moment of inertia with respect to the x axis is The moment of inertia with respect to the yaxis is in4 in4 Karrow_forwardAnswer asaparrow_forwardDetermine the moment of inertia for the shaded area about the x-axis. Express your answer to three significant figures and include the appropriate units. Look at the images for the needed figure and details to answer the question. y_1=x m y_2=2.1x m^2arrow_forward
- Determine the polar moment of inertia of the circular area without and with the central square hole. 1.18 R R 1.18 R Answers: Without the square hole lz= i 0.785 R4 With the square hole 1z = i R4 0.6235arrow_forwardDetermine the moments of inertia of the shaded area about the x- and y-axes. Also determine the polar moment of inertia about point O.arrow_forwardDetermine the moments of inertia of the shaded area about the x- and y-axes. Also determine the polar moment of inertia about point O.arrow_forward
- Determine the percent reduction n in the polar moment of inertia of the square plate due to the introduction of the circular hole. Assume a = 2.OR. a Answer: n = y | R 3.75 a a %arrow_forward4) 10–6. Determine the moment of inertia for the shaded area about the y axis. y =x!/2_ 1 m -1 marrow_forwardNEEED ASAParrow_forward
- Q.2) Calculate the moment of inertia (I, and I,) about the given axis for the shaded area shown in figure. Hint: the answer in terms of a. 2a 24-arrow_forwardThe difference between the moments of Inertia of area A with respect to the x1 and x axes is 0.365m^4. (Ix1-Ix=0.365)Calculate the area, knowing that A has its CG at C. P=27arrow_forwardDetermine the principal moments of inertia for the beam’s cross-sectionalthe area is shown in Figure with respect to an axis passing through the centroid C.arrow_forward
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