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Concept explainers
(a)
Interpretation:
The solution having higher molarity needs to be determined.
Concept introduction:
Solutions are formed by homogeneous mixing of solute into a solvent. In the present case, solutes X and Y are dissolved using a solvent C to form a solution. Each case has its own uniqueness. The concentration of solutes and solvent should be defined in various terms to determine the strength of our solution through various angles.
Molarity is defined as ratio of number of moles of solute in a given volume of solution. It is represented by the unit “M”.
(b)
Interpretation:
The solution with higher mass percent needs to be determined.
Concept introduction:
Solutions are formed by homogeneous mixing of solute into a solvent. In the present case, solutes X and Y are dissolved using a solvent C to form a solution. Each case has its own uniqueness. The concentration of solutes and solvent should be defined in various terms to determine the strength of our solution through various angles.
Mass percent is defined as percent of mass of solute present in the solution.
(c)
Interpretation:
The solution having higher molality needs to be determined.
Concept introduction:
Solutions are formed by homogeneous mixing of solute into a solvent. In the present case, solutes X and Y are dissolved using a solvent C to form a solution. Each case has its own uniqueness. The concentration of solutes and solvent should be defined in various terms to determine the strength of our solution through various angles.
Molality of a solution is defined as number of moles of solute in 1 kg of the solvent.
(d)
Interpretation:
The solution having larger multiplier or i needs to be determined.
Concept introduction:
The multiplier is defined as the number of moles of particles of solution per mole of solute. In this case, this term can be redefined as the actual concentration of particle to the concentration of solute. The “particles” are the solutes X and Y in both cases. Hence, it is a relative ratio of concentration of solute molecules per mole of solute. Moles can be converted into molecules by multiplying it with
(e)
Interpretation:
The solution with solvent having higher mole fraction needs to be determined.
Concept introduction:
Mole fraction is a ratio of number of moles of one species with respect to total number of moles. In a solution, there is solvent and solute. Therefore, the number of moles of solvent and solute needs to be determined to obtain the total number of moles of solution.

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Chapter 10 Solutions
OWLv2 with Student Solutions Manual eBook for Masterton/Hurley's Chemistry: Principles and Reactions, 8th Edition, [Instant Access], 4 terms (24 months)
- For each reaction below, decide if the first stable organic product that forms in solution will create a new C-C bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. NH2 CI MgCl ? Will the first product that forms in this reaction create a new CC bond? Yes No MgBr ? Will the first product that forms in this reaction create a new CC bond? Yes No G टेarrow_forwardFor each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. དྲ。 ✗MgBr ? O CI Will the first product that forms in this reaction create a new C-C bond? Yes No • ? Will the first product that forms in this reaction create a new CC bond? Yes No × : ☐ Xarrow_forwardPredict the major products of this organic reaction: OH NaBH4 H ? CH3OH Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry. Click and drag to start drawing a structure. ☐ : Sarrow_forward
- Predict the major products of this organic reaction: 1. LIAIHA 2. H₂O ? Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry. Click and drag to start drawing a structure. X : ☐arrow_forwardFor each reaction below, decide if the first stable organic product that forms in solution will create a new C - C bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. NH2 tu ? ? OH Will the first product that forms in this reaction create a new CC bond? Yes No Will the first product that forms in this reaction create a new CC bond? Yes No C $ ©arrow_forwardAs the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule with a new C-C bond as its major product: 1. MgCl ? 2. H₂O* If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry. If the major products of this reaction won't have a new CC bond, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. This reaction will not make a product with a new CC bond. G marrow_forward
- Including activity coefficients, find [Hg22+] in saturated Hg2Br2 in 0.00100 M NH4 Ksp Hg2Br2 = 5.6×10-23.arrow_forwardgive example for the following(by equation) a. Converting a water insoluble compound to a soluble one. b. Diazotization reaction form diazonium salt c. coupling reaction of a diazonium salt d. indacator properties of MO e. Diazotization ( diazonium salt of bromobenzene)arrow_forward2-Propanone and ethyllithium are mixed and subsequently acid hydrolyzed. Draw and name the structures of the products.arrow_forward
- (Methanesulfinyl)methane is reacted with NaH, and then with acetophenone. Draw and name the structures of the products.arrow_forward3-Oxo-butanenitrile and (E)-2-butenal are mixed with sodium ethoxide in ethanol. Draw and name the structures of the products.arrow_forwardWhat is the reason of the following(use equations if possible) a.) In MO preperation through diazotization: Addition of sodium nitrite in acidfied solution in order to form diazonium salt b.) in MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at low pH c.) In MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at pH 4.5 d.) Avoiding not cooling down the reaction mixture when preparing the diazonium salt e.) Cbvcarrow_forward
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