COLLEGE PHYSICS LL W/ 6 MONTH ACCESS
COLLEGE PHYSICS LL W/ 6 MONTH ACCESS
2nd Edition
ISBN: 9781319414597
Author: Freedman
Publisher: MAC HIGHER
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Chapter 10, Problem 64QAP
To determine

(a)

The time to make each orbit and gravitational force on the object

Expert Solution
Check Mark

Answer to Problem 64QAP

Time taken for each orbital =1.52hours

Explanation of Solution

Given info:

Altitude = 345km

Mass of the object = 10.0kg

Formula used:

  T2=(4π2GM)(R+h)3

  T= Time

  G= Gravitational constant

  M= Mass of Earth

  R= Radius of Earth

  h= Altitude

  Fg=GMm(R+h)2

  F= Gravitational force

  m= Mass of the object

  F=mg

  F= Force

  m= Mass of the object

  g= Acceleration

Calculation:

Time taken for each orbital,

  T2=(4π2GM)(R+h)3T=2π (R+h) 3 GM=2π ((6371+345)× 10 3 ) ) 3 (6.67× 10 11 N m 2 /k g 2 )×(6.0× 10 24 kg)=5463.70s=1.52hours

Conclusion:

Time taken for each orbital =1.52hours

To determine

(b)

Gravitational force on the object

Expert Solution
Check Mark

Answer to Problem 64QAP

Gravitational force =88.73N

Fraction =88.73N98N=0.91

Explanation of Solution

Given info:

Altitude = 345km

Mass of the object = 10.0kg

Formula used:

  T2=(4π2GM)(R+h)3

  T= Time

  G= Gravitational constant

  M= Mass of Earth

  R= Radius of Earth

  h= Altitude

  Fg=GMm(R+h)2

  F= Gravitational force

  m= Mass of the object

  F=mg

  F= Force

  m= Mass of the object

  g= Acceleration

Calculation:

Gravitational force,

  Fg=GMm(R+h)2=(6.67×1011Nm2/kg2)×(6.0*1024kg)×10.0kg((6371+345)×103))2=88.73N

  F=mg=10.0kg×9.8m/s2=98NFraction=FgF=88.73N98N=0.91

Conclusion:

Gravitational force =88.73N

Fraction =88.73N98N=0.91

To determine

(c)

How can an object be considered weightless in ISS?

According to the calculation comparatively to the weight on Earth, in the ISS weigh of the object is less.

Given info:

Altitude = 345km

Mass of the object = 10.0kg

Explanation:

Comparatively to the weight on Earth, in the ISS weigh of the object is less.

Conclusion:

Comparatively to the weight on Earth, in the ISS weigh of the object is less.

Expert Solution
Check Mark

Answer to Problem 64QAP

According to the calculation comparatively to the weight on Earth, in the ISS weigh of the object is less.

Explanation of Solution

Given info:

Altitude = 345km

Mass of the object = 10.0kg

Comparatively to the weight on Earth, in the ISS weigh of the object is less.

Conclusion:

Comparatively to the weight on Earth, in the ISS weigh of the object is less.

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