The reason as to why the addition of HBr to alkenes A and C forms the addition products B and D is to be stated. Concept introduction: According to Markovinokov’s rule, the positive part of halogen acid attached to that carbon atom in C=C bond which carries maximum number of hydrogen atoms and the negative part of halogen acid will attach to that carbon atom in C=C bond which has minimum number of hydrogen atoms. The steps followed by electrophilic addition reaction are stated below: • First protonation of the alkene take place to generate the carbocation. • The halide ion will attack on the carbocation to give the final product.

Question

A student proposes the transformation below in one step of an organic synthesis. There may be one or more reactants missing from the left-hand side, but there are no products missing from the right-hand side. There may also be catalysts, small inorganic reagents, and other important reaction conditions missing from the arrow. • Is the student's transformation possible? If not, check the box under the drawing area. • If the student's transformation is possible, then complete the reaction by adding any missing reactants to the left-hand side, and adding required catalysts, inorganic reagents, or other important reaction conditions above and below the arrow. • You do not need to balance the reaction, but be sure every important organic reactant or product is shown. + T G OH де OH This transformation can't be done in one step.

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Question

Chapter 10, Problem 61P

Interpretation Introduction

Interpretation: The reason as to why the addition of HBr to alkenes A and C forms the addition products B and D is to be stated.

Concept introduction: According to Markovinokov’s rule, the positive part of halogen acid attached to that carbon atom in C=C bond which carries maximum number of hydrogen atoms and the negative part of halogen acid will attach to that carbon atom in C=C bond which has minimum number of hydrogen atoms.

The steps followed by electrophilic addition reaction are stated below:

• First protonation of the alkene take place to generate the carbocation.

• The halide ion will attack on the carbocation to give the final product.

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