Explanation In the problem statement it is given that Ethane burns in air (oxygen) to give carbon dioxide and water. The raw chemical equation for the reaction can be written as, C 2 H 6 + O 2 → CO 2 + H 2 O The atoms of each kind are not same in total count on both side of the reaction arrow. The chemical equation has to be balanced. Consider balancing hydrogen atom as it occurs only once in both sides. This can be done by adding coefficient 3 to water in the product side. Then the equation becomes as shown below, C 2 H 6 + O 2 → CO 2 + 3 H 2 O In the above equation we see that, hydrogen atom is balanced. But other atoms are not. Again consider the subscript present for hydrogen atom in both sides. Multiply with the coefficient 2 on the reactant side for ethane and coefficient 6 for water on the product side. Now, the equation becomes as, 2C 2 H 6 + O 2 → CO 2 + 6 H 2 O In the above equation, hydrogen atom is balanced

16th Edition

ISBN: 9780077862619

Author: KRAUSKOPF, Konrad B. (konrad Bates), Beiser, Arthur

Publisher: Mcgraw-hill Education,

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Chapter 10, Problem 59E

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The balanced chemical equation for the given reaction.

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Chapter 10, Problem 58E

Chapter 10, Problem 60E

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The balanced chemical equation for the given reaction.

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The balanced chemical equation for the given reaction.

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