Paged memory management: Paged memory management technique is to partition the main memory into a set of small fixed-sized blocks called as frames. Logical address of paged memory management: The logical address in paged memory management begins as a single integer value. The logical address is written in the format of “<page, offset>”. Page number is got by the number of times the page size divides the address, and offset is remainder of the division. The given logical address in a paged memory management system is <2, 133>. From this given data, the value “2” represents the page number and the value “133” represents offset. The above value means the “133” bytes on page “2” of the process. Physical address of paged memory format: To produce a physical address, the frame number in which a page is stored should be found out. Then, the frame number should be multiplied with the frame size. The multiplied value should be added with offset value to produce physical address. The formula to bind logical address to the physical address is, Physical address = Frame number * Frame size + Offset value (1) The following table is given table with specific page number and frame that the page belongs, Page 0 1 2 3 Frame 5 2 7 3

Question

Want to see the full answer?

Answer 1

Question

Chapter 10, Problem 58E

Program Plan Intro

Paged memory management:

Paged memory management technique is to partition the main memory into a set of small fixed-sized blocks called as frames.

Logical address of paged memory management:

The logical address in paged memory management begins as a single integer value.

The logical address is written in the format of “<page, offset>”.

Page number is got by the number of times the page size divides the address, and offset is remainder of the division.

The given logical address in a paged memory management system is <2, 133>.

From this given data, the value “2” represents the page number and the value “133” represents offset.

The above value means the “133” bytes on page “2” of the process.

Physical address of paged memory format:

To produce a physical address, the frame number in which a page is stored should be found out.

Then, the frame number should be multiplied with the frame size.

The multiplied value should be added with offset value to produce physical address.

The formula to bind logical address to the physical address is,

Physical address = Frame number * Frame size + Offset value (1)

The following table is given table with specific page number and frame that the page belongs,

Page 0 1 2 3
Frame 5 2 7 3

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

After playing our giving implementation, your task is to implement Dinning Philosophers with semaphore in C, by including and Your implementation will require creating five philosophers, each identified by a number 0.4. Each philosopher will run as a separate thread. Create threads using Pthreads as discussed in the Lecture slides on Chapter 4 and Practice Lab on Threads. Your solution needs to accomplish the following: Implement in C (15 points) 1. dp1.c - You are to provide your solution to this assignment as a single C program named 'dp1.c using semaphore. Explain in you code (as comments) that the dead lock will happen or not. If there is a possible deadlock, you can simply solve the deadlock by pick the fork in order like the first solution in our slides. Solve Deadlock by Footman (15 points) 1. Here is a new solution to overcome the deadlock. The Dining Philosophers decide to hire a footman whose task to allow only four philosophers to sit on the table. When entering and…

8.4 Self-Bias Configuration 20. Determine Zi. Zo. and A,, for the network of Fig. 8.73 if gf, = 3000 μS and gos = 50 μs. 21. Determine Z, Zo, and A, for the network of Fig. 8.73 if the 20-uF capacitor is removed and the parameters of the network are the same as in Problem 20. Compare results with those of Problem 20. +12 V 3.3 ΚΩ HE C₂ Vo Z Zo C₁ 10 ΜΩ Z₁ 1.1 ΚΩ Cs 20 µF FIG. 8.73 Problems 20, 21, 22, and 59.

21. Determine Zi, Zo, and A, for the network of Fig. 8.73 if the 20-μF capacitor is removed and the parameters of the network are the same as in Problem 20. Compare results with those of Problem 20. +12 V 3.3 ΚΩ +6 C₂ C₁ Z₁ 10 ΜΩ 1.1 ΚΩ Cs 20 μF FIG. 8.73 Zo