Explanation Given data: The speed at which the spore ejected upward ( v ) is 3.6 m s . The height at which the spore reaches ( y ) is 20 cm. Formula used: Refer to the equation (10.8) in the textbook, and write the expression for initial kinetic energy of the spore as follows. K = 1 2 m v 2 (1) Here, m is the mass of the spore, and v is the speed at which the spore ejected upward. Refer to the equation (10.14) in the textbook, and write the expression for final gravitational potential energy of the spore as follows. U g = m g y (2) Here, g is the acceleration due to the gravity, which is 9.8 m s 2 , and y is the height at which the spore reaches. Explanation: Consider the mass of the spore ( m ) as m kg . Calculation of initial kinetic energy: Substitute m kg for m , and 3.6 m s for v in equation (1), K = 1 2 ( m kg ) ( 3.6 m s ) 2 = ( 1 2 ) ( m kg ) ( 12.96 m 2 s 2 ) = 6.48 m kg ⋅ m 2 s 2 = 6.48 m J { ∵ 1 kg ⋅ m 2 s 2 = 1 J } Calculation of final gravitational potential energy: Substitute m kg for m , 9

MODIFIED MASTERING COLLEGE PHYSICS 18WK.

4th Edition

ISBN: 9780136782216

Author: Knight

Publisher: PEARSON

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Question

Chapter 10, Problem 46P

To determine

To find: The fraction of initial kinetic energy that converts to the final potential energy and to explain the reason for lost energy.

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Chapter 10, Problem 45P

Chapter 10, Problem 47P

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Chapter 10 Solutions

MODIFIED MASTERING COLLEGE PHYSICS 18WK.

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