
Concept explainers
(a)
Interpretation: The structure of stereoisomer that has higher melting point than eleostearic acid is to be drawn.
Concept introduction: Fatty acids are of two types: saturated fatty acid and unsaturated fatty acid. In Saturated fatty acid, double bond is absent, whereas unsaturated fatty acid consists of one or more than one double bond. The melting point of a fatty acid indirectly depends upon the number of double bond present in an acid. Higher is the number of double bonds in acid, lower will be the melting point of an acid.
When two higher priority groups are present on the opposite side then it is an
(b)
Interpretation: The structure of stereoisomer that has lower melting point is to be drawn.
Concept introduction: Fatty acids are of two types: saturated fatty acid and unsaturated fatty acid. In Saturated fatty acid, double bond is absent, whereas unsaturated fatty acid consists of one or more than one double bond. The melting point of a fatty acid indirectly depends upon the number of double bond present in an acid. Higher is the number of double bonds in acid, lower will be the melting point of an acid.
When two higher priority groups are present on the opposite side, then it is an

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Chapter 10 Solutions
ORGANIC CHEMISTRY W/BIOLOGICAL TOPICS
- b. H3C CH3 1. 2. H3O+ H3C MgBr H3Carrow_forwardPredict the major products of this reaction: excess H+ NaOH ? A Note that the first reactant is used in excess, that is, there is much more of the first reactant than the second. If there won't be any products, just check the box under the drawing area instead. Explanation Check Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privarrow_forward1. For each of the reaction "railroads" below, you are either asked to give the structure(s) of the starting material(s) or product(s), or provide reagents/conditions to accomplish the transformation, as indicated by the boxes. a. NaOMe H+ .CO,H HO₂C MeOH (excess) MeOH H3C Br يع CH3 1. LiAlH4 2. H3O+ 3. PBг3 H3C 1. Et-Li 2. H3O+ -CO₂Me -CO₂Me OH CH3 CH3 ল CH3arrow_forward
- Predict the intermediate 1 and final product 2 of this organic reaction: NaOMe ག1, ད།་, - + H You can draw 1 and 2 in any arrangement you like. 2 work up Note: if either 1 or 2 consists of a pair of enantiomers, just draw one structure using line bonds instead of 3D (dash and wedge) bonds at the chiral center. Explanation Check Click and drag to start drawing a structure. Х © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Parrow_forwardWhat is the total energy cost associated with the compound below adopting the shown conformation? CH3 HH DH CH3arrow_forwardΗΝ, Draw Final Product C cyclohexanone pH 4-5 Edit Enamine H3O+ CH3CH2Br THF, reflux H Edit Iminium Ionarrow_forward
- How many hydrogen atoms are connected to the indicated carbon atom?arrow_forwardIdentify the compound with the longest carbon - nitrogen bond. O CH3CH2CH=NH O CH3CH2NH2 CH3CH2C=N CH3CH=NCH 3 The length of all the carbon-nitrogen bonds are the samearrow_forwardIdentify any polar covalent bonds in epichlorohydrin with S+ and 8- symbols in the appropriate locations. Choose the correct answer below. Η H's+ 6Η Η Η Η Η Ηδ Η Ο Ο HH +Η Η +Η Η Η -8+ CIarrow_forward
- H H:O::::H H H HH H::O:D:D:H HH HH H:O:D:D:H .. HH H:O:D:D:H H H Select the correct Lewis dot structure for the following compound: CH3CH2OHarrow_forwardRank the following compounds in order of decreasing boiling point. ннннн -С-С-Н . н-с- ННННН H ΗΤΗ НННН TTTĪ н-с-с-с-с-о-н НННН НН C' Н н-с-с-с-с-н НН || Ш НННН H-C-C-C-C-N-H ННННН IVarrow_forwardRank the following compounds in order of decreasing dipole moment. |>||>||| ||>|||>| |>|||>|| |||>||>| O ||>>||| H F H F H c=c || H c=c F F IIIarrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
