Concept explainers
(a)
Interpretation:
1-butene has one triple bond has to be indicated as true or false.
(a)

Explanation of Solution
1-butene is an
From the above structure it is found that 1-butene contains only a double bond and not a triple bond. Hence, the given statement is false.
(b)
Interpretation:
1-butene has lower melting point than ethene has to be indicated as true or false.
(b)

Explanation of Solution
1-butene contains four carbon atoms and eight hydrogen atoms. Ethene contains two carbon atoms and four hydrogen atoms. As the molar mass increases, the London Dispersion forces become stronger and as a result melting and boiling points will also increase. Hence, ethene will have lower melting point than 1-butene. Therefore, the given statement is false.
(c)
Interpretation:
1-butene is an unsaturated hydrocarbon has to be indicated as true or false.
(c)

Explanation of Solution
Structure of 1-butene can be given as,
A double bond is present between two carbon atoms in the structure of 1-butene. Therefore, 1-butene is an unsaturated hydrocarbon. Hence, the given statement is true.
(d)
Interpretation:
1-butene is polar has to be indicated as true or false.
(d)

Explanation of Solution
1-butene contains four carbon atoms and eight hydrogen atoms. The structure of 1-butene can be given as,
Pentane contains only carbon and hydrogen atom. Therefore, this is a nonpolar molecule only. Given statement is false.
(e)
Interpretation:
Molecular formula of 1-butene is
(e)

Explanation of Solution
1-butene contains four carbon atoms and eight hydrogen atoms. The molecular formula of 1-butene is
(f)
Interpretation:
1-butene is a liquid at room temperature has to be indicated as true or false.
(f)

Explanation of Solution
(g)
Interpretation:
Molar mass of 1-butene is
(g)

Explanation of Solution
Molecular formula of 1-butene is
Therefore, molar mass of 1-butene is
(h)
Interpretation:
Ionic bonding is present in 1-butene has to be indicated as true or false.
(h)

Explanation of Solution
1-butene is an organic compound. It contains only hydrogen and carbon atoms. Therefore, the bonds present between the atoms in 1-butene are covalent bonds only and not ionic bonds. Hence, the given statement is false.
(i)
Interpretation:
Ionic bonding is flammable has to be indicated as true or false.
(i)

Explanation of Solution
1-butene is an organic compound. All the hydrocarbons are flammable. Hence, 1-butene is also flammable because it contains only carbon and hydrogen atoms. The given statement is true.
(j)
Interpretation:
(j)

Explanation of Solution
1-butene is an organic compound. Structure of 1-butene can be given as,
This do not contain hydroxyl group as its functional group. It contains double bond as its functional group. Hence, the given statement is false.
(k)
Interpretation:
1-butene is an aliphatic hydrocarbon has to be indicated as true or false.
(k)

Explanation of Solution
1-butene is an organic compound. Structure of 1-butene can be given as,
1-butene do not contain any ring structure. It contains only carbon and hydrogen atoms. Therefore, 1-butene is an aliphatic hydrocarbon. The given statement is true.
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Chapter 10 Solutions
GENERAL, ORGANIC,BIO CHP.10-23-ACCESS>I
- Stuc X ctclix ALE X A ALE אן A ALEX Lab (195 X Nut x M Inb x NU X NUT X Unt x + → C www-awu.aleks.com/alekscgi/x/Isl.exe/10_u-lgNslkr7j8P3jH-IQ1g8NUi-mObKa_ZLx2twjEhK7mVG6PulJI006NcKTV37JxMpZuyrVCdQolLAKqp_7U3r1GUD3... New Chrome available: Naomi Question 26 of 39 (4 points) | Question Attempt: 1 of Unlimited Give the IUPAC name. 2,3-dimethylhexane Part: 1/2 Part 2 of 2 Draw the skeletal structure of a constitutional isomer of the alkane above that contains a different number of carbons in its longest chain. Skip Part Check Click and drag to start drawing a structure. 3 Finance headline Q Search mwa Harvard Intensifi... X Save For Later 00 dlo HB Submit Assignment 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility a 9:11 PM 4/22/2025arrow_forwardPredict the product of this organic reaction: + NH2 HO A P+ H2O Specifically, in the drawing area below draw the skeletal ("line") structure of P. If there is no reasonable possibility for P, check the No answer box under the drawing area. Click and drag to start drawing a structure. ✓arrow_forward个 Stuc X ctclix ALE X A ALE × A ALE X Lab x (195 × Nut x M Inbx EF 目 → C www-awu.aleks.com/alekscgi/x/Isl.exe/10_u-IgNslkr7j8P3jH-IQ1g8NUi-mObKa_ZLx2twjEhK7mVG6PulJI006NcKTV37JxMpz Chapter 12 HW = Question 27 of 39 (5 points) | Question Attempt: 1 of Unlimited Part: 1/2 Part 2 of 2 Give the IUPAC name. Check 3 50°F Clear ©2025 McGraw Hill L Q Search webp a عالياكarrow_forward
- 个 Stuck x ctc xALE X A ALE × A ALE X Lab x (19: x - G www-awu.aleks.com/alekscgi/x/Isl.exe/10_u-lgNslkr7j8P3jH-1Q1g8NUi-mObka ZLx2twjEhK7mVG6PUUIO06 Chapter 12 HW 三 Question 26 of 39 (4 points) 1 Question Attempt: 1 of Unlimited Answer the following questions about the given alkane. Part: 0 / 2 Part 1 of 2 Give the IUPAC name. Skip Part 2 53°F Clear Check × Q Search hp hp 02arrow_forwardCalculate the equilibrium constant at 25.0 oC for the following equation. Cd(s) + Sn+2(aq) ↔Cd+2(aq) + Sn(s) Group of answer choices 3.11x104 1.95x1018 9.66x108 1.40x109arrow_forwardWhat is the pH at the cathode for the following cell written in line notation at 25.0 oC with a Ecell = -0.2749 V? Ni(s)|Ni+2(aq, 1.00 M)||H+1(aq, ?M)|H2(g, 1.00 atm)|Pt(s)arrow_forward
- Calculate Ecell for a hydrogen fuel cell at 95.0 oC using the following half-reactions with PH2 = 25.0 atm and PO2 = 25.0 atm. O2(g) + 4H+1(aq) + 4e-1 → 2H2O(l) Eo = 1.229 V 2H2(g) → 4H+1(aq) + 4e-1 Eo = 0.00 Varrow_forwardCalculate Ecell at 25.0 oC using the following half-reactions with [Ag+1] = 0.0100 M and [Sn+2] = 0.0200 M. Ag+1(aq) + 1e-1 Ag(s) Sn+2(aq) + 2e-1 Sn(s)arrow_forwardDone 18:19 www-awu.aleks.com Chapter 12 HW Question 27 of 39 (5 points) | Question Attempt: 1 of Unlimited .. LTE סוי 9 ✓ 20 ✓ 21 × 22 23 24 25 26 27 28 29 30 Answer the following questions about the given alkane. Part: 0 / 2 Part 1 of 2 Classify each carbon atom as a 1º, 2º, 3º, or 4°. Highlight in red any 1° carbons, highlight in blue any 2° carbons. highlight in green any 3° carbons, and leave any 4° carbons unhighlighted. Skip Part Check Save For Later © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center | Accessibility ☑ คarrow_forward
- < Done 19:22 www-awu.aleks.com Chapter 12 HW Question 4 of 39 (2 points) | Question Attempt: 5 of Unlimited : .. LTE סוי 1 ✓ 2 ✓ 3 = 4 ✓ 5 ✓ 6 ✓ 7 ✓ 8 ✓ 9 = 10 11 ✓ 12 Consider the molecule (CH3)2CHCH2CHCн for the following questions. Part 1 of 2 Which of the following molecules is/are constitutional isomer(s) to (CH3)2CHCH2CH2CH3? Check all that apply. Part 2 of 2 (CH3),C(CH2)2CH3 CH3 H,C-CH-CH-CH, CH 3 None of the above. ☑ Which of the following molecules is/are identical molecules to (CH3)2CHCH2CH2CH₁₂? Check all that apply. CH3 H,C-CH-CH₂-CH2-CH, CH3(CH2)2CH(CH3)2 CH2-CH2-CH3 HỌC-CH=CH, 乂 ☑ а None of the above Check Save For Later Submit Assignment © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accessibilityarrow_forward18:11 LTE ا... US$50 off hotels is waiting for you Book now, hotels in Nashville are going fast QUTSLIVII 25 61 69 points) | QuestIVIT ALLēm... now Give the IUPAC name for each compound. Part 1 of 3 Part 2 of 3 X ☑ Х Check Save For Later Submit © 2025 McGraw Hill LLC. All Rights Reserved. TOMS CT US ...vacy Center | Accessibilityarrow_forwardDone 19:17 www-awu.aleks.com Chapter 12 HW Question 29 of 39 (6 points) | Question Attempt: 1 of Unlimited .III LTE סוי 27 28 = 29 30 31 32 = 33 34 35 Consider this structure. CH3CH2CH2 Part 1 of 3 3 CH2 CH2CH3 - C-CH2CH 3 H CH₂ Give the IUPAC name of this structure. 3-ethyl-3,4-dimethylheptane Part: 1/3 Part 2 of 3 Draw the skeletal structure. Skip Part < Check Click and drag to start drawing a structure. Save For Later Submit © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility Хarrow_forward
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