(a) Explanation Graph: Consider the given equation, x 2 − 4 x + 8 y + 36 = 0 . Simplify the equation as, x 2 − 4 x + 8 y + 36 = 0 x 2 − 4 x + 36 + 4 − 4 = − 8 y x − 2 2 + 32 = − 8 y x − 2 2 = − 8 y + 4 Since the equation has x 2 term, the axis of symmetry is parallel to y -axis and as the coefficient of y is negative, parabola opens down. Note that the equation, x − 2 2 = − 8 y + 4 , compares with the standard equation of parabola, x − h 2 = 4 p y − k , with center, h , k (b) To determine To graph: The conic section with equation, 3 x 2 + 4 y 2 − 30 x − 8 y + 67 = 0 . (c) To determine To graph: The conic section with equation, 4 x 2 − 5 y 2 − 8 x − 30 y − 21 = 0 .

11th Edition

ISBN: 9781119244912

Author: Anton

Publisher: WILEY CONS

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Question

Chapter 10, Problem 38RE

(a)

To determine

To graph: The conic section with equation, x2−4x+8y+36=0 .

(b)

To determine

To graph: The conic section with equation, 3x2+4y2−30x−8y+67=0 .

(c)

To determine

To graph: The conic section with equation, 4x2−5y2−8x−30y−21=0 .

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Chapter 10, Problem 37RE

Chapter 10, Problem 39RE

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Chapter 10 Solutions

EBK CALCULUS:EARLY TRANSCENDENTALS

Ch. 10.1 - Prob. 1QCE Ch. 10.1 - The graph of the curve described by the parametric...Ch. 10.1 - Suppose that a parametric curve C is given by the...Ch. 10.1 - To find dy/dx directly from the parametric...Ch. 10.1 - Let L be the length of the curve x=lnt,y=sint1t An...Ch. 10.1 - (a) By eliminating the parameter, sketch the...Ch. 10.1 - (a) By eliminating the parameter, sketch the...Ch. 10.1 - Sketch the curve by eliminating the parameter, and...Ch. 10.1 - Sketch the curve by eliminating the parameter, and...Ch. 10.1 - Sketch the curve by eliminating the parameter, and...

Knowledge Booster

To graph: The conic section with equation, x 2 − 4 x + 8 y + 36 = 0 .

Solution Summary: The author illustrates how the conic section with equation, x2-4x+8y+36=0, compares with the standard equation of parabola.

To graph: The conic section with equation, x2−4x+8y+36=0 .

To graph: The conic section with equation, 3x2+4y2−30x−8y+67=0 .

To graph: The conic section with equation, 4x2−5y2−8x−30y−21=0 .

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Chapter 10 Solutions