Explanation The free body diagram of the cast-leg system is given as, Write the expression for the mass of the upper leg. m u l = 1 2 p m Here, m u l is the mass of the upper leg, p is the mass percent of the both the legs, and m is the mass of the body. Substitute 0.215 for p , and 74 kg for m to get m u l . m u l = 1 2 ( 0.215 ) ( 74 kg ) = 7.955 kg Write the expression for the mass of the lower leg. m l l = 1 2 p m Here, m l l is the mass of the lower leg. Substitute 0.140 for p , and 74 kg for m to get m u l . m l l = 1 2 ( 0.140 ) ( 74 kg ) = 5.18 kg Write the expression for the coordinate of the center of mass. x c m = x u l m u l + x l l m l l + x cast m cast m u l + m l l + m cast Here, x c m is the coordinate of the center of mass, x u l is the coordinate of the upper leg, x l l is the coordinate of the lower leg, x cast is the coordinate of the cast, and m cast is the mass of the cast

Masteringphysics With Pearson Etext - Valuepack Access Card - For College Physics

10th Edition

ISBN: 9780321976932

Author: YOUNG

Publisher: PEARSON

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Center of Gravity of a system

The centre of gravity is a property that is based on the geometry of a rigid body or any particle. It is described as an equilibrium point or a hypothetical location where the total weight of the body is concentrated.

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Chapter 10, Problem 36P

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The distance between the hip joint and the supporting strap.

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Chapter 10, Problem 35P

Chapter 10, Problem 37P

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Masteringphysics With Pearson Etext - Valuepack Access Card - For College Physics

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The distance between the hip joint and the supporting strap.

Solution Summary: The author explains the distance between the hip joint and the supporting strap. The free body diagram is given as, Write the expression for the mass of the upper leg.

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The distance between the hip joint and the supporting strap.

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Chapter 10 Solutions