Explanation Given: The functions are s ( x ) = x − 2 , x ≥ 2 and p ( x ) = 2 x 2 − 3 x + 4 . Calculation: Consider the following functions. p ( x ) = 2 x 2 − 3 x + 4 s ( x ) = x − 2 , x ≥ 2 Substitute 2 x 2 − 3 x + 4 for p ( x ) and x − 2 for s ( x ) , s [ p ( x ) ]

MyLab Math with Pearson eText -- 24 MonthStandalone Access Card -- for Intermediate Algebra with Integrated Review

8th Edition

ISBN: 9780135910023

Author: Tobey, John, Slater, Jeffrey, Blair, Jamie , Crawford, Jenny

Publisher: PEARSON

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Chapter 10, Problem 34RP

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To calculate: The value of s[p(2)] for functions s(x)=x−2,x≥2 and p(x)=2x2−3x+4.

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Chapter 10, Problem 33RP

Chapter 10, Problem 35RP

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MyLab Math with Pearson eText -- 24 MonthStandalone Access Card -- for Intermediate Algebra with Integrated Review

Ch. 10.1 - For the function f ( x ) = 3 x − 5 , find the...Ch. 10.1 - For the function , find the following. 2. Ch. 10.1 - Prob. 3E Ch. 10.1 - Prob. 4E Ch. 10.1 - Prob. 5E Ch. 10.1 - Prob. 6E Ch. 10.1 - For the function , find the following. 7. Ch. 10.1 - Prob. 8E Ch. 10.1 - Prob. 9E Ch. 10.1 - Prob. 10E

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The value of s [ p ( 2 ) ] for functions s ( x ) = x − 2 , x ≥ 2 and p ( x ) = 2 x 2 − 3 x + 4 .

Solution Summary: The author explains how to calculate the value of s(x) right for functions such as sqrtx-2,x

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To calculate: The value of s[p(2)] for functions s(x)=x−2,x≥2 and p(x)=2x2−3x+4.

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Chapter 10 Solutions