Materials Science and Engineering: An Introduction, 10e WileyPLUS + Abridged Loose-leaf
Materials Science and Engineering: An Introduction, 10e WileyPLUS + Abridged Loose-leaf
10th Edition
ISBN: 9781119472070
Author: William D. Callister Jr., David G. Rethwisch
Publisher: Wiley (WileyPLUS Products)
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Chapter 10, Problem 32QAP
To determine

The two reasons why martensite is so hard and brittle:

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*3-4. A tension test was performed on a steel specimen having an original diameter of 0.503 in. and a gauge length of 2.00 in. The data is listed in the table. Plot the stress-strain diagram and determine approximately the modulus of elasticity, the ultimate stress, and the rupture stress. Use a scale of 1 in. = 15 ksi and 1 in. = 0.05 in./in. Redraw the linear-elastic region, using the same stress scale but a strain scale of 1 in. = 0.001 in. Load (kip) Elongation (in.) 0 0 2.50 0.0009 6.50 0.0025 8.50 0.0040 9.20 0.0065 9.80 0.0098 12.0 0.0400 14.0 0.1200 14.5 0.2500 14.0 0.3500 13.2 0.4700
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Here is my code please draw a transition diagram and nfa on paper public class Lexer { private static final char EOF = 0; private static final int BUFFER_SIZE = 10; private Parser yyparser; // parent parser object private java.io.Reader reader; // input stream public int lineno; // line number public int column; // column // Double buffering implementation private char[] buffer1; private char[] buffer2; private boolean usingBuffer1; private int currentPos; private int bufferLength; private boolean endReached; // Keywords private static final String[] keywords = { "int", "print", "if", "else", "while", "void" }; public Lexer(java.io.Reader reader, Parser yyparser) throws Exception { this.reader = reader; this.yyparser = yyparser; this.lineno = 1; this.column = 0; // Initialize double buffering buffer1 = new char[BUFFER_SIZE]; buffer2 = new char[BUFFER_SIZE]; usingBuffer1 = true; currentPos = 0; bufferLength = 0; endReached = false; // Initial buffer fill fillBuffer(); } private…
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