(a)
The names of the microstructural products of
(b)
The names of the microstructural products of
(c)
The names of the microstructural products of
(d)
The names of the microstructural products of

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Chapter 10 Solutions
MATERIALS SCIENCE AND ENGINEERING -PACK
- 2. sin'³½ds dxarrow_forward14. sin² 20 cos³ 20 doarrow_forward500 Q3: The attachment shown in Fig.3 is made of 1040 HR. The static force is 30 kN. Specify the weldment (give the pattern, electrode number, type of weld, length of weld, and leg size). Fig. 3 All dimension in mm 30 kN 100 (10 Marks)arrow_forward
- Compute for the stresses (initial, const and final stage) and check for compliance in NSCP provisions. Also compute the following: 1. Compute and check if the section is Uncracked, Transition or Cracked as per NSCP. 2. Compute for its flexural capacity and check if it could carry the given load. BEAM SECTION NOT TO SCALE 1400mm 300 $1098 400 */ 400*300* 300 200 300 100 ORIGINAL SECTION/PRECA CAST-IN-PLACE (CIP) PART PRECAST LOADING AT SERVICE M • 21 KN (DEAD LOAD ONLY) 21KN 4.75m 9.25m CIVEN DATA STRANDS: 12-02 AT 120KN/STRAND (GOMM FROM BOTTOM) 8-2 AT 120HN/STRAND (120mm FROM BOTTOM) fc 42.5 MPa (BEAM) fc 38 MPa (CIP) f'a = 80% or fa fp-1860 MPa ESTRANDS 1976Pa OONG 23.6/m³ LOES 1-8% Loss 18% APPLY 3M LIVE LOAD AT CONST. PHASEarrow_forward(read image) (answer given)arrow_forwardA cylinder and a disk are used as pulleys, as shown in the figure. Using the data given in the figure, if a body of mass m = 3 kg is released from rest after falling a height h 1.5 m, find: a) The velocity of the body. b) The angular velocity of the disk. c) The number of revolutions the cylinder has made. T₁ F Rd = 0.2 m md = 2 kg T T₂1 Rc = 0.4 m mc = 5 kg ☐ m = 3 kgarrow_forward
- (read image) (answer given)arrow_forward11-5. Compute all the dimensional changes for the steel bar when subjected to the loads shown. The proportional limit of the steel is 230 MPa. 265 kN 100 mm 600 kN 25 mm thickness X Z 600 kN 450 mm E=207×103 MPa; μ= 0.25 265 kNarrow_forwardT₁ F Rd = 0.2 m md = 2 kg T₂ Tz1 Rc = 0.4 m mc = 5 kg m = 3 kgarrow_forward
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