Explanation Calculation: The value of loss tangent is very much greater than one for conducting medium. Therefore, write the expression for conducting medium as follows: tan θ ≫ 1 Consider the expression for loss tangent for nonmagnetic media. tan θ = σ ω ε (1) Here, σ is the conductivity, ω is radian frequency, and ε is the permittivity. Rewrite the Equation (1) as follows: tan θ = σ 2 π f ε { ∵ ω = 2 π f } (2) (a) Wet marshy soil: Substitute 10 − 2 S / m for σ , 8 MHz for f , and 15 ε o for ε in Equation (2). tan θ = 10 − 2 S / m ( 2 π ) ( 8 MHz ) ( 15 ε o ) = 10 − 2 S / m ( 2 π ) ( 8 × 10 6 Hz ) ( 15 ) ( 10 − 9 36 π ) { ∵ ε o = 10 − 9 36 π } = 1.5 As the value of loss tangent is not much greater than 1, wet marshy soil is not a conducting medium at 8 MHz. (b) Intrinsic germanium: Substitute 0.025 S / m for σ , 8 MHz for f , and 16 ε o for ε in Equation (2). tan θ = 0

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Chapter 10, Problem 25P

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Find out the medium from the given three media that conducts at 8 MHz.

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Chapter 10, Problem 24P

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I need help with a MATLAB code. For question b.6 I have the MATLAB code shown below. How do I edit the code to answer question b.7. Please make sure the plots are reasonable. clc; clear all; % Constants mu = 398600; % Earth gravitational parameter, km^3/s^2 % Initial chief and deputy positions and velocities in ECI frame % Assume circular orbits in equatorial plane for simplicity a_c = 10000; % km a_d = 11500; % km r_c0 = [a_c; 0; 0]; v_c0 = [0; sqrt(mu/a_c); 0]; r_d0 = [a_d; 0; 0]; v_d0 = [0; sqrt(mu/a_d); 0]; % Initial relative state delta_r0 = r_d0 - r_c0; delta_v0 = v_d0 - v_c0; x0 = [delta_r0; delta_v0]; % 6x1 initial relative state % Time span tspan = [0 3600]; % 1 hour in seconds % Damping cases cases = struct( ... 'name', {'Critically damped', 'Under-damped', 'Over-damped'}, ... 'Kr', {eye(3)*2.5e-3, eye(3)*0.001, eye(3)*0.01}, ... 'P', {eye(3)*0.01, eye(3)*0.0006, eye(3)*0.02} ... ); % Simulate each case for i = 1:length(cases) Kr = cases(i).Kr; P =…

Chapter 10 Solutions

Elements Of Electromagnetics

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Ch. 10.10 - Prob. 11PE Ch. 10.10 - Prob. 12PE Ch. 10.11 - Prob. 13PE Ch. 10 - Prob. 1RQ Ch. 10 - Prob. 2RQ Ch. 10 - Prob. 3RQ Ch. 10 - Prob. 4RQ Ch. 10 - Prob. 5RQ Ch. 10 - Prob. 6RQ Ch. 10 - Prob. 7RQ Ch. 10 - Prob. 8RQ Ch. 10 - Prob. 9RQ Ch. 10 - Prob. 10RQ Ch. 10 - Prob. 1P Ch. 10 - Prob. 2P Ch. 10 - Prob. 3P Ch. 10 - Prob. 4P Ch. 10 - Prob. 5P Ch. 10 - Prob. 6P Ch. 10 - Prob. 7P Ch. 10 - Prob. 8P Ch. 10 - Prob. 9P Ch. 10 - Prob. 10P Ch. 10 - Prob. 11P Ch. 10 - Prob. 12P Ch. 10 - Prob. 13P Ch. 10 - Prob. 14P Ch. 10 - Prob. 15P Ch. 10 - Prob. 16P Ch. 10 - Prob. 17P Ch. 10 - Prob. 18P Ch. 10 - Prob. 19P Ch. 10 - Prob. 20P Ch. 10 - Prob. 21P Ch. 10 - Prob. 22P Ch. 10 - Prob. 23P Ch. 10 - Prob. 24P Ch. 10 - Prob. 25P Ch. 10 - Prob. 26P Ch. 10 - Prob. 27P Ch. 10 - Prob. 28P Ch. 10 - Prob. 29P Ch. 10 - Prob. 30P Ch. 10 - Prob. 31P Ch. 10 - Prob. 32P Ch. 10 - Prob. 33P Ch. 10 - Prob. 34P Ch. 10 - Prob. 35P Ch. 10 - Prob. 36P Ch. 10 - Prob. 37P Ch. 10 - Prob. 38P Ch. 10 - Prob. 39P Ch. 10 - Prob. 40P Ch. 10 - Prob. 41P Ch. 10 - Prob. 42P Ch. 10 - Prob. 43P Ch. 10 - Prob. 44P Ch. 10 - Prob. 45P Ch. 10 - Prob. 46P Ch. 10 - Prob. 47P Ch. 10 - Prob. 48P Ch. 10 - Prob. 49P Ch. 10 - Prob. 50P Ch. 10 - Prob. 51P Ch. 10 - Prob. 52P Ch. 10 - Prob. 53P Ch. 10 - Prob. 54P Ch. 10 - Prob. 55P Ch. 10 - Prob. 56P Ch. 10 - Prob. 57P Ch. 10 - Prob. 58P Ch. 10 - Prob. 59P Ch. 10 - Prob. 60P Ch. 10 - Prob. 61P Ch. 10 - Prob. 62P Ch. 10 - Prob. 63P Ch. 10 - Prob. 64P Ch. 10 - Prob. 65P Ch. 10 - Prob. 66P Ch. 10 - Prob. 67P Ch. 10 - Prob. 68P Ch. 10 - Prob. 69P Ch. 10 - Prob. 70P Ch. 10 - Prob. 71P Ch. 10 - Prob. 72P Ch. 10 - Prob. 73P Ch. 10 - Prob. 74P Ch. 10 - Prob. 75P Ch. 10 - Prob. 76P Ch. 10 - Prob. 78P Ch. 10 - Prob. 79P Ch. 10 - Prob. 80P Ch. 10 - Prob. 81P Ch. 10 - Prob. 82P Ch. 10 - Prob. 83P Ch. 10 - Prob. 84P

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