This problem considers energy and work aspects of Example 10.7—use data from that example as needed. (a) Calculate the rotational kinetic energy in the merry-go-round plus child when they have an angular velocity of 20.0 rpm. (b) Using energy considerations, find the number of revolutions the father will have to push to achieve this angular velocity starting from rest. (c) Again, using energy considerations, calculate the force the father must exert to stop the merry-go- round in revolutions
This problem considers energy and work aspects of Example 10.7—use data from that example as needed. (a) Calculate the rotational kinetic energy in the merry-go-round plus child when they have an angular velocity of 20.0 rpm. (b) Using energy considerations, find the number of revolutions the father will have to push to achieve this angular velocity starting from rest. (c) Again, using energy considerations, calculate the force the father must exert to stop the merry-go- round in revolutions
This problem considers energy and work aspects of Example 10.7—use data from that example as needed. (a) Calculate the rotational kinetic energy in the merry-go-round plus child when they have an angular velocity of 20.0 rpm. (b) Using energy considerations, find the number of revolutions the father will have to push to achieve this angular velocity starting from rest. (c) Again, using energy considerations, calculate the force the father must exert to stop the merry-go- round in revolutions
Definition Definition Rate of change of angular velocity. Angular acceleration indicates how fast the angular velocity changes over time. It is a vector quantity and has both magnitude and direction. Magnitude is represented by the length of the vector and direction is represented by the right-hand thumb rule. An angular acceleration vector will be always perpendicular to the plane of rotation. Angular acceleration is generally denoted by the Greek letter α and its SI unit is rad/s 2 .
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A thrown brick hits a window, but doesn't
break it. Instead it reverses direction and
ends down on the ground below the
window. Since the brick didn't break the
glass, we know:
О
The force of the brick on the glass >
the force of the glass on the brick.
О
The force of the brick on the glass
the force of the glass on the brick.
=
О
The force of the brick on the glass <
the force of the glass on the brick.
О
The brick didn't slow down as it broke
the glass.
Alexandra (wearing rubber boots for
traction) is attempting to drag her 32.6-kg
Golden Retriever across the smooth ice by
applying a horizontal force. What force
must she apply to move the dog with a
constant speed of 0.950 m/s?
☐ 31.0 lb.
☐ 319 kg.
○ Zero.
32.6 kg.
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