Explanation The process of movement of the perfume molecules to the nose is an example of Brownian motion of gas molecules as shown in the figure. Whenever the perfume molecules i.e. in the gaseous form come out from the bottle it causes Brownian motion i.e. the gas particles move randomly and spontaneously by which they reach the nose. The postulates of Brownian motions are i) This motion is spontaneous. ii) The motion does not depend upon the vibration of the vessel. iii) The motion increases with the increment of temperature. iv) The motion increases as the size of the particle decreases. v) As the viscosity of the medium decreases the velocity of the particle increases. The Brownian motion can be explained in the light of kinetic molecular theory of gas. As per the kinetic molecular theory the gas molecules randomly move, and they collide with each other and for that sometimes their motion increase or decreases. This is completely a random motion of molecules. The gas molecules always collide with each other as per the kinetic molecular theory...

2nd Edition

ISBN: 9780137390977

Author: Tro

Publisher: PEARSON C

See similar textbooks

Concept explainers

Kinetic-Theory of Gases

Kinetic theory of gases is the model or method which was developed in the 19th century by Maxwell and Boltzmann. This is possible as the interatomic force which is of short-range forces that are important for solids and liquids can be neglected for gases…

Question

Chapter 10, Problem 21E

Interpretation Introduction

To determine: Explain the process of perfume molecules travel from bottle to nose and mean free path.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 10, Problem 20E

Chapter 10, Problem 22E

Students have asked these similar questions

pressure (atm) 3 The pressure on a sample of pure X held at 47. °C and 0.88 atm is increased until the sample condenses. The pressure is then held constant and the temperature is decreased by 82. °C. On the phase diagram below draw a path that shows this set of changes. 0 0 200 temperature (K) 400 а

er your payment details | bar xb Home | bartleby x + aleksogi/x/isl.exe/1o u-lgNskr7j8P3jH-1Qs_pBanHhviTCeeBZbufuBYT0Hz7m7D3ZcW81NC1d8Kzb4srFik1OUFhKMUXzhGpw7k1 O States of Matter Sketching a described thermodynamic change on a phase diagram 0/5 The pressure on a sample of pure X held at 47. °C and 0.88 atm is increased until the sample condenses. The pressure is then held constant and the temperature is decreased by 82. °C. On the phase diagram below draw a path that shows this set of changes. pressure (atm) 1 3- 0- 0 200 Explanation Check temperature (K) 400 X Q Search L G 2025 McGraw Hill LLC. All Rights Reserved Terms of Use Privacy Ce

Chapter 10 Solutions

CHEM: STRUC & PROP (LL) >CUST PKG<

Ch. 10 - Prob. 1E Ch. 10 - Prob. 2E Ch. 10 - Prob. 3E Ch. 10 - Prob. 4E Ch. 10 - Prob. 5E Ch. 10 - Prob. 6E Ch. 10 - Prob. 7E Ch. 10 - Prob. 8E Ch. 10 - Prob. 9E Ch. 10 - Prob. 10E

Ch. 10 - Prob. 11E Ch. 10 - Prob. 12E Ch. 10 - Prob. 13E Ch. 10 - Prob. 14E Ch. 10 - Prob. 15E Ch. 10 - Prob. 16E Ch. 10 - Prob. 17E Ch. 10 - Prob. 18E Ch. 10 - Prob. 19E Ch. 10 - Prob. 20E Ch. 10 - Prob. 21E Ch. 10 - Prob. 22E Ch. 10 - If a reaction occurs in the gas phase at STP, the...Ch. 10 - Prob. 24E Ch. 10 - Prob. 25E Ch. 10 - Prob. 26E Ch. 10 - Prob. 27E Ch. 10 - Prob. 28E Ch. 10 - Prob. 29E Ch. 10 - Prob. 30E Ch. 10 - Prob. 31E Ch. 10 - Prob. 32E Ch. 10 - A 48.3-mL sample of gas in a cylinder is warmed...Ch. 10 - A syringe containing 1.55 mL of oxygen gas is...Ch. 10 - A balloon contains 0.158 mol of gas and has a...Ch. 10 - Prob. 36E Ch. 10 - Prob. 37E Ch. 10 - Prob. 38E Ch. 10 - Prob. 39E Ch. 10 - Prob. 40E Ch. 10 - Prob. 41E Ch. 10 - Prob. 42E Ch. 10 - Prob. 43E Ch. 10 - Prob. 44E Ch. 10 - Prob. 45E Ch. 10 - Prob. 46E Ch. 10 - A wine-dispensing system uses argon canisters to...Ch. 10 - Prob. 48E Ch. 10 - Prob. 49E Ch. 10 - Prob. 50E Ch. 10 - Aerosol cans carry clear warnings against...Ch. 10 - Prob. 52E Ch. 10 - Prob. 53E Ch. 10 - Use the molar volume of a gas at STP to calculate...Ch. 10 - What is the density (in g/L) of hydrogen gas at...Ch. 10 - Prob. 56E Ch. 10 - Prob. 57E Ch. 10 - A 113-mL gas sample has a mass of 0.171 g at a...Ch. 10 - A sample of gas has a mass of 38.8 mg. Its volume...Ch. 10 - Prob. 60E Ch. 10 - A gas mixture contains each of these gases at the...Ch. 10 - A gas mixture with a total pressure of 745 mmHg...Ch. 10 - We add a 1.20-g sample of dry ice to a 755-mL...Ch. 10 - A 275-mL flask contains pure helium at a pressure...Ch. 10 - A gas mixture contains 1.25 g N2 and 0.85 g O2 in...Ch. 10 - Prob. 66E Ch. 10 - The hydrogen gas formed in a chemical reaction is...Ch. 10 - Prob. 68E Ch. 10 - Prob. 69E Ch. 10 - Prob. 70E Ch. 10 - Prob. 71E Ch. 10 - Prob. 72E Ch. 10 - Prob. 73E Ch. 10 - Prob. 74E Ch. 10 - Prob. 75E Ch. 10 - Prob. 76E Ch. 10 - Prob. 77E Ch. 10 - Prob. 78E Ch. 10 - Prob. 79E Ch. 10 - Prob. 80E Ch. 10 - Prob. 81E Ch. 10 - Prob. 82E Ch. 10 - CH3OH can be synthesized by the reaction:...Ch. 10 - Oxygen gas reacts with powered aluminum according...Ch. 10 - Automobile airbags inflate following serious...Ch. 10 - Lithium reacts with nitrogen gas according to the...Ch. 10 - Prob. 87E Ch. 10 - Prob. 88E Ch. 10 - Prob. 89E Ch. 10 - Carbon monoxide gas reacts with hydrogen gas to...Ch. 10 - Prob. 91E Ch. 10 - Prob. 92E Ch. 10 - Prob. 93E Ch. 10 - Use the vander Waals equation and the ideal gas...Ch. 10 - Pennies that are currently being minted are...Ch. 10 - A 2.85 g sample of an unknown chlorofluorocarbon...Ch. 10 - Prob. 97E Ch. 10 - A 118 mL flask is evacuated and found to have a...Ch. 10 - Prob. 99E Ch. 10 - A gaseous hydrogen- and carbon-containing compound...Ch. 10 - Prob. 101E Ch. 10 - Consider the reaction: 2Ag2O(s)4Ag(s)+O2(g) If...Ch. 10 - When hydrochloric acid is poured over potassium...Ch. 10 - Consider the reaction: 2SO2(g)+O2(g)2SO(g)3 If...Ch. 10 - Ammonium carbonate decomposes upon heating...Ch. 10 - Ammonium nitrate decomposes explosively upon...Ch. 10 - Prob. 107E Ch. 10 - Prob. 108E Ch. 10 - Gaseous ammonia is injected into the exhaust...Ch. 10 - Prob. 110E Ch. 10 - Prob. 111E Ch. 10 - Prob. 112E Ch. 10 - Prob. 113E Ch. 10 - Prob. 114E Ch. 10 - Prob. 115E Ch. 10 - Prob. 116E Ch. 10 - Prob. 117E Ch. 10 - Prob. 118E Ch. 10 - Prob. 119E Ch. 10 - Prob. 120E Ch. 10 - Prob. 121E Ch. 10 - Prob. 122E Ch. 10 - Prob. 123E Ch. 10 - Prob. 124E Ch. 10 - Prob. 125E Ch. 10 - Prob. 126E Ch. 10 - When 0.583 g of neon is added to an 800-cm3bulb...Ch. 10 - A gas mixture composed of helium and argon has a...Ch. 10 - Prob. 129E Ch. 10 - Prob. 130E Ch. 10 - Prob. 131E Ch. 10 - Prob. 132E Ch. 10 - Prob. 133E Ch. 10 - Prob. 134E Ch. 10 - The atmosphere slowly oxidizes hydrocarbons in a...Ch. 10 - Prob. 136E Ch. 10 - Prob. 137E Ch. 10 - Prob. 138E Ch. 10 - Prob. 139E Ch. 10 - Prob. 140E Ch. 10 - Prob. 141E Ch. 10 - Prob. 142E Ch. 10 - Prob. 143E Ch. 10 - Which gas would you expect to deviate most from...Ch. 10 - Prob. 145E Ch. 10 - Prob. 146E Ch. 10 - Prob. 147E Ch. 10 - Prob. 148E Ch. 10 - Prob. 149E Ch. 10 - Prob. 150E Ch. 10 - Prob. 151E Ch. 10 - Calculate the pressure exerted by 1 mol of an...Ch. 10 - Prob. 153E Ch. 10 - Prob. 1SAQ Ch. 10 - Prob. 2SAQ Ch. 10 - Prob. 3SAQ Ch. 10 - Prob. 4SAQ Ch. 10 - Prob. 5SAQ Ch. 10 - Prob. 6SAQ Ch. 10 - Prob. 7SAQ Ch. 10 - A gas mixture is a 1.55-L container at 298 K...Ch. 10 - Prob. 9SAQ Ch. 10 - Prob. 10SAQ Ch. 10 - Prob. 11SAQ Ch. 10 - Prob. 12SAQ Ch. 10 - Prob. 13SAQ Ch. 10 - Prob. 14SAQ Ch. 10 - Prob. 15SAQ

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Explain the process of perfume molecules travel from bottle to nose and mean free path.

Solution Summary: The author explains that the process of movement of perfume molecules to nose is due to the Brownian motion of gas molecules.

Concept explainers

To determine: Explain the process of perfume molecules travel from bottle to nose and mean free path.

Want to see the full answer?

Chapter 10 Solutions