To determine To graph: The curve represented by equation y 2 25 − x 2 16 = 1 . Explanation Given Information: The provided equation to graph the curve, y 2 25 − x 2 16 = 1 Graph: Consider the provided equation, y 2 25 − x 2 16 = 1 Since the provided equation is similar to the standard form of hyperbola, y 2 a 2 − x 2 b 2 = 1 Then, a 2 = 25 and b 2 = 16 , Which gives, a = 5 and b = 4 , The equations of the asymptotes are, y = ± b a x Or, y = ± 5 4 x . To find points to plot the asymptote y = 5 4 x , Substitute x = 4 , y = 5 4 ( 4 ) Then, y = 5 . So, point is ( 4 , 5 ) . Substitute x = − 4 , y = 5 4 ( − 4 ) Then, y = − 5

Intermediate Algebra For College Students (10th Edition)

10th Edition

ISBN: 9780134758992

Author: Allen R. Angel, Dennis Runde

Publisher: PEARSON

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Chapter 10, Problem 20CRT

To determine

To graph: The curve represented by equation y225−x216=1.

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Chapter 10, Problem 19CRT

Chapter 11.1, Problem 1ES

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Question 3 over a field K. In this question, MË(K) denotes the set of n × n matrices (a) Suppose that A Є Mn(K) is an invertible matrix. Is it always true that A is equivalent to A-¹? Justify your answer. (b) Let B be given by 8 B = 0 7 7 0 -7 7 Working over the field F2 with 2 elements, compute the rank of B as an element of M2(F2). (c) Let 1 C -1 1 [4] [6] and consider C as an element of M3(Q). Determine the minimal polynomial mc(x) and hence, or otherwise, show that C can not be diagonalised. [7] (d) Show that C in (c) considered as an element of M3(R) can be diagonalised. Write down all the eigenvalues. Show your working. [8]

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Chapter 10 Solutions

Intermediate Algebra For College Students (10th Edition)

Ch. 10.1 - Fill in the blanks with the appropriate word,...Ch. 10.1 - Prob. 2ES Ch. 10.1 - Prob. 3ES Ch. 10.1 - Prob. 4ES Ch. 10.1 - Prob. 5ES Ch. 10.1 - Prob. 6ES Ch. 10.1 - Prob. 7ES Ch. 10.1 - Prob. 8ES Ch. 10.1 - Prob. 9ES Ch. 10.1 - Prob. 10ES

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