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MindTapV2.0 for Farrell's Java Programming with 2021 Updates, 9th Edition [Instant Access], 1 term
9th Edition
ISBN: 9780357505540
Author: Farrell; Joyce
Publisher: Cengage Learning US
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Chapter 10, Problem 1RQ
Program Plan Intro
To find the correct option that can be used as a reliable way to find which class is a base class and which is a derived class.
Expert Solution & Answer
Program Description Answer
b. try saying the two class names together.
Explanation of Solution
Explanation:
Classes can be derived from other classes in Java, as in other object-oriented
A reliable way that will help to find which of the two classes is the base class and which is a subclass is by try saying the two class names together.
By saying the names of both base class and derived class, one should check which class is containing more generalized features and which is not. A class that contains more generalized features should be considered as the base class and the other one should be considered as the derived one.
For example: Consider two classes Birds and Pigeon. If we call the names of both, surely, the Birds class will contain more generalized features instead of the Pigeon class. So, the Birds class will be a base class and the Pigeon class will be the derived one.
Conclusion:
Therefore, the correct option is option b. try saying the two class names together.
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Students have asked these similar questions
Add a timer in the following code.
public class GameGUI extends JPanel { private final Labyrinth labyrinth; private final Player player; private final Dragon dragon; private Timer timer; private long elapsedTime;
public GameGUI(Labyrinth labyrinth, Player player, Dragon dragon) { this.labyrinth = labyrinth; this.player = player; this.dragon = dragon; String playerName = JOptionPane.showInputDialog("Enter your name:"); player.setName(playerName); elapsedTime = 0; timer = new Timer(1000, e -> { elapsedTime++; repaint(); }); timer.start();
}
@Override protected void paintComponent(Graphics g) { super.paintComponent(g); int cellSize = Math.min(getWidth() / labyrinth.getSize(), getHeight() / labyrinth.getSize());}
Change the following code so that when player wins the game, the game continues by creating new GameGUI with the same player. However the player's starting position is same, everything else should be reseted.
public static void main(String[] args) { Labyrinth labyrinth = new Labyrinth(10); Player player = new Player(9, 0); Random rand = new Random(); Dragon dragon = new Dragon(rand.nextInt(10), 9); JFrame frame = new JFrame("Labyrinth Game"); GameGUI gui = new GameGUI(labyrinth, player, dragon);
frame.setLayout(new BorderLayout()); frame.setSize(600, 600); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.add(gui, BorderLayout.CENTER); frame.pack(); frame.setResizable(false); frame.setVisible(true); }
public class GameGUI extends JPanel { private final Labyrinth labyrinth; private final Player player; private final Dragon dragon; private Timer timer; private long…
Create a menu item which restarts the game. Also add a timer, which counts the elapsed time since the start of the game level.
When the restart is pressed, the restarted game should ask the player' name (in the GameGUI constructor) and set the score of player to 0 (player.setScore(0)), and the timer should restart again. And create a logic so that if the player loses his life (checkGame if the condition is false), then save this number together with his name into two variables. And display two buttons where one quits the game altogether (System.exit(0)) and the other restarts the game.
public class GameGUI extends JPanel { private final Labyrinth labyrinth; private final Player player; private final Dragon dragon;
private final ImageIcon playerIcon = new ImageIcon("data/images/player.png"); private final ImageIcon dragonIcon = new ImageIcon("data/images/dragon.png"); private final ImageIcon wallIcon = new ImageIcon("data/images/wall.png"); private final ImageIcon…
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