CONTROL SYSTEMS ENGINEERING
7th Edition
ISBN: 9781119185666
Author: NISE
Publisher: WILEY
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Chapter 10, Problem 1RQ
To determine
The advantages of Frequency response techniques over Root Locus technique.
Expert Solution & Answer

Explanation of Solution
Root locus represents the path of closed loop poles of given transfer function in s-plane as the system parameter changes whereas, frequency response represents the steady state response of given system for a sinusoidal input function.
The advantages of the Frequency response techniques compared to Root Locus technique are:
- Sinusoidal test signal for various ranges of frequencies and amplitude are easily available, thus the experimental determination of frequency response is easily accomplished and most reliable but in case of in Root Locus it is hard to extract sinusoidal inputs.
- In Root Locus, if the characteristic equation is complex or contain power of “e” cannot be evaluated but in Frequency Response technique such type of transfer function can be exactly applied and evaluated.
- The design and parameter adjustment of open loop transfer function of a system for a specified closed loop performance can be carried out easily in Frequency domain as compared to Time domain.
- The Root Locus technique is its inability to deal with the difficulty in dealing with time deal whereas Frequency Response handles correctly the time delays.
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Consider 0.65 kg of N2 at 300 K, 1 bar contained in a rigid tank connected by a valve to another rigid tank holding 0.3 kg of CO2 at 300 K, 1 bar. The valve is opened and gases are allowed to mix, achieving an equilibrium state at 290 K. Determine: (a) the volume of each tank, in m³. (b) the final pressure, in bar. (c) the magnitude of the heat transfer to or from the gases during the process, in kJ. (d) the entropy change of each gas and of the overall system, in kJ/K.
(Read Image) (Answer: ω = 1.10 rad/sec CW)
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Chapter 10 Solutions
CONTROL SYSTEMS ENGINEERING
Ch. 10 - Prob. 1RQCh. 10 - Prob. 2RQCh. 10 - Prob. 3RQCh. 10 - Briefly describe how to obtain the frequency...Ch. 10 - Prob. 5RQCh. 10 - Each pole of a system contributes how much of a...Ch. 10 - Prob. 7RQCh. 10 - Prob. 8RQCh. 10 - Prob. 9RQCh. 10 - What is the major difference between Bode...
Ch. 10 - Prob. 11RQCh. 10 - Prob. 12RQCh. 10 - Prob. 13RQCh. 10 - 14. What is a Nyquist diaoram?
Ch. 10 - Prob. 15RQCh. 10 - 16. When sketching a Nyquist diagram, what must be...Ch. 10 - Prob. 17RQCh. 10 - Prob. 18RQCh. 10 - Prob. 19RQCh. 10 - Prob. 20RQCh. 10 - Prob. 21RQCh. 10 - Prob. 22RQCh. 10 - Prob. 23RQCh. 10 - Prob. 24RQCh. 10 - Prob. 25RQCh. 10 - Prob. 26RQCh. 10 - Prob. 1PCh. 10 - Prob. 7PCh. 10 - Prob. 14PCh. 10 - For each closed-loop system with the following...Ch. 10 - Prob. 27PCh. 10 - For the Bode plots shown in Figure P10.10,...
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